Hello!
To find our answer, we just divide.
57/60=0.95
We multiply by 100 to find our percent
100(0.95)-95
Therefore, our answer is 95%
I hope this helps!
we are given

Firstly, we will factor numerators and denominators

we can see that
n^2 -6 is factor on both numerator and denominator
so, it will get cancelled
and n^2 -6 can not be equal to 0
so, one of restriction is


we can simplify it

we know that denominator can not be zero


so, option-B.......Answer
Answer:
yes
Step-by-step explanation:
RHS
=4x-27/0
=not defined=0
LHS
=x-2x+3x+4/7=2x+4/7=(14x+4)/7= 14x+4.
14x=-4
x=-4/14
X=-2/7
The probability is 1/650.
There is 1 a out of 26 letters; P(a) = 1/26
There is 1 e out of 26 letters; however, since it comes after drawing the a and is done without replacement, it is out of 25: 1/25
Together, their probabilities are 1/26(1/25) = 1/650