<h3>Answer</h3><h3>7 Ns</h3><h3>Explanation</h3>
Given in the question,
mass of foul ball = 0.140 kg
initial speed with which ball was hit with the bat = 30 m/s
final speed = 40 m/s
According to the scenario the whole scene is making a right angle triangle
So, to the solve the question we will use pythagorus theorem
<h3>Hypotenuse² = base² + height²</h3>
Here,
Hypotenuse= Magnitude of impulse
Base = 1st change of momentum
height = 2nd change of momentum
1st impulse (1st change of momentum)
p = m(1)v(1) = (0.14 kg)(40.0 m/s) = 5.6 kg m / s = 5.6 N s
2nd impulse (2nd change of momentum)
p = m(2)v(2) = (0.14 kg)(30.0 m/s) = 4.2 kg m / s = 4.2 N s
Magnitude of impulse (hypotenuse of triangle)
impulse² = (5.6)² + (4.2)²
impulse² = 31.36 + 17.64
impulse² = 49
impulse² = √49
impulse = 7.0 N s
