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shutvik [7]
3 years ago
13

A tool used to measure weight

Chemistry
2 answers:
sergeinik [125]3 years ago
4 0
Answer: A scale. Or beam scale
alex41 [277]3 years ago
3 0

Answer:

A scale

Explanation:

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The reaction shown below has a positive enthalpy change and a negative entropy change. 2C (s) + 2H2 (g) yields C2H4 (g) Which of
Drupady [299]
Answer is: <span>The reaction will not be spontaneous at any temperature.

</span>

<span>Gibbs free energy (G) determines if reaction will proceed spontaneously.
ΔG = ΔH - T·ΔS.
ΔG - changes in Gibbs free energy.
ΔH - changes in enthalpy.
ΔS - changes in entropy.
T is temperature in Kelvins.
When ΔS < 0 (negative entropy change) and ΔH > 0 (endothermic reaction), the process is never spontaneous (ΔG> 0).</span>

5 0
3 years ago
Where is the majority of Earth’s water found?<br><br> glaciers
galben [10]
Oceans are the most common of course
5 0
3 years ago
A series of chemicals were added to some AgNO3(aq). NaCl(aq) was added first to the silver nitrate solution to produce a precipi
OLEGan [10]

Answer:

First, precipitate of AgCl is formed. Second, a soluble complex of silver and ammonia is formed. Third, AgCl is reproduced due to disappearance of ammonia complex in presence of HNO_{3}.

Explanation:

In presence of NaCl, AgNO_{3} forms an insoluble precipitate of AgCl.

Reaction: Ag^{+}(aq.)+Cl^{-}(aq.)\rightarrow AgCl(s)

In presence of NH_{3}, AgCl gets dissolved into solution due to formation of soluble [Ag(NH_{3})_{2}]^{+} complex.

Reaction: AgCl(s)+2NH_{3}(aq.)\rightarrow [Ag(NH_{3})_{2}]^{+}(aq.)+ Cl^{-}(aq.)

In presence of HNO_{3}, [Ag(NH_{3})_{2}]^{+} complex gets destroyed and free Cl^{-} again reacts with free Ag^{+} to produce insoluble AgCl

Reaction: [Ag(NH_{3})_{2}]^{+}(aq.)+2H^{+}(aq.)+Cl^{-}(aq.)\rightarrow AgCl(s)+2NH_{4}^{+}(aq.)

4 0
3 years ago
a compound is decomposed In the laboratory and produces 1.40 g N and 0.20g H what is the empirical formula
Bumek [7]

First, find the number of moles for each element. The molar mass for nitrogen is 14 g/mol and that of hydrogen is 1 g/mol.

1.40 g N / 14 g/mol = 0.1 mol N

0.20 g H / 1 g/mol = 0.2 mol H

Find the mole ratio. Divide both numbers with the much lower value. In this case, it is 0.1 mol N.

For N: 0.1 ÷ 0.1 = 1

For H: 0.2÷0.1 = 2

Thus, the empirical formula is NH_{2}.

7 0
3 years ago
Someone help me please
Roman55 [17]

Answer:

i know it bro

Explanation:

Examples of metals are aluminium, copper, iron, tin, gold, lead, silver, titanium, uranium, and zinc. Well-known alloys include bronze and steel.

mark me Brainliest

5 0
3 years ago
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