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dexar [7]
3 years ago
7

Which solute produces the highest boiling point in a 0.15 m aqueous solution?

Chemistry
1 answer:
saul85 [17]3 years ago
6 0
In order to determine the increase in boiling point of a solvent due to the presence of a solute, we use the formula:

ΔT = Kb * m * i

Here, Kb is a property of the solvent, so remains constant regardless of the solute. Moreover, because the concentration m has been fixed, this will also not be considered. In order to determine which solute will have the greatest effect, we must check i, the van't Hoff factor.

Simply stated, i is the number of ions that a substance produces when dissolved. Therefore, the solute producing the most ions will be the one causing the greatest change in boiling point temperature.
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Match each description below:
neonofarm [45]

Answer:

a) will react with water: K

b) will react with steam or acid, but not water: Cr & Sn

d) will not react with water, steam, or acid: Cu

Explanation:

K reacts violently with water.

Cr will react with steam to form an oxide + H gas and will react with most acids

Sn will react with steam to form SnO₂ + H gas and, though it does not react as rapidly as other metals in acid, it dissolves easily in concentrated acids

Cu is an extremely nonreactive metal, which is what makes it so suitable for wiring

5 0
3 years ago
Match the definitions below with the correct component of the scientific method:
laiz [17]
A and 3

B and 6

C and 5

D and 1

E and 2

F and 4
8 0
3 years ago
In[7.60x10-³] = In(5.63×10-2) - (k s¯¹)(480 s)
Lerok [7]

Answer:

I'm not understand that question

I'm so sorry

8 0
2 years ago
What is the cell wall & the chloroplasts?
adoni [48]

The cell wall is mixed with the cell membrane, the cell wall is outside of the membrane and the cell membrane is letter i which allows materials to pass in and out of the cell.

Chloroplasts are letter k they basically just help the plant use photosynthesis.

cell wall: f

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6 0
4 years ago
How many moles of Ag can be produced if 350. g of Cu are reacted with excess AgNO3 according to the equation Cu(s) + 2AgNO3(aq)
Ksju [112]
Hello.

balance the equation first 
<span>Cu + 2AgNO3 ----> [2Ag] + Cu(NO3)2 
</span>

<span>Now set up the equation </span>
<span>350gCu*(1molCu/ 63.546g Cu) * (2molAg/1molCu) * (107.8682g Ag/1molAg)
 </span>

<span>Cancel out 1molCu with 1molCu, and cancel out 2molAg with 1molAg (it still remains 2mol Ag) </span>

<span>You are left with </span>
<span>350gCu*(1/63.546g Cu)*(2Ag/1)* (107.8682g Ag/1) 
</span>

<span>350gCu*1*2*107.8682= 75507.74g 
</span>

<span>now divide 75507.74g by 63.546g 
</span>
<span>you get [1188.2374972460896g Ag]
</span>
Have a nice day
3 0
3 years ago
Read 2 more answers
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