___Fe + ___O2 →___Fe2O3
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Refer to the diagram shown below.
W₁ = (4 kg)*(9.8 m/s²) = 39.2 N
W₂ = (1 kg)*(9.8 m/s²) = 9.8 N
The normal reaction on the 4-kg mass is
N = (39.2 N)*cos(25°) = 35.5273 N
The force acting down the inclined plane due to the weight is
F = (39.2 N)*sin(25°) = 16.5666 N
The net force that accelerates the 4-kg mass at a m/²s down the plane is
F - W₂ = (4 kg)*(a m/s²)
4a = 16.5666 - 9.8
a = 1.6917 m/s²
Answer: 1.69 m/s² (nearest hundredth)
W₁ = (4 kg)*(9.8 m/s²) = 39.2 N
W₂ = (1 kg)*(9.8 m/s²) = 9.8 N
The normal reaction on the 4-kg mass is
N = (39.2 N)*cos(25°) = 35.5273 N
The force acting down the inclined plane due to the weight is
F = (39.2 N)*sin(25°) = 16.5666 N
The net force that accelerates the 4-kg mass at a m/²s down the plane is
F - W₂ = (4 kg)*(a m/s²)
4a = 16.5666 - 9.8
a = 1.6917 m/s²
Answer: 1.69 m/s² (nearest hundredth)
The total amount of energy transferred as heat is equal to 288 Joules.
<u>Given the following data:</u>
- Internal energy = 123 Joules
- Work done = 165 Joules
To calculate the total amount of energy transferred as heat, we would apply the first law of thermodynamics.
<h3>The first law of thermodynamics.</h3>Mathematically, the first law of thermodynamics is given by the formula:
<u>Where;</u>
is the change in internal energy.
- Q is the quantity of heat transferred.
- W is the work done.
Substituting the given parameters into the formula, we have;
Q = 288 Joules.
Read more on internal energy here: brainly.com/question/25737117