Kinetic energy depends on the height of an object above the ground?
1 answer:
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Answer:
The hill should be not less than 0.625 m high
Explanation:
This problem can be solved by using the principle of conservation of mechanical energy. In the absence of friction, the total mechanical energy is conserved. That means that
is constant, being U the potential energy and K the kinetic energy
When the car is in the top of the hill, its speed is 0, but its height h should be enough to produce the needed speed v down the hill.
The Kinetic energy is then, zero. When the car gets enough speed we assume it is achieved at ground level, so the potential energy runs out to zero but the Kinetic is at max. So the initial potential energy is transformed into kinetic energy.
We can solve for h:
The hill should be not less than 0.625 m high
Answer:
Ws=8.75 Watts
Explanation:
As per fig. of prob 02.061, it is clear that R5 and R4 are in parallel, its equivalent Resistance will be:
Now, this equivalent Req45 is in series with R3, therefore:
This Req345 is in parallel with R2, i.e
Now this gets in series with R1:
Now, the power delivered Ws is: