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adelina 88 [10]
3 years ago
11

Kinetic energy depends on the height of an object above the ground?

Physics
1 answer:
s344n2d4d5 [400]3 years ago
5 0
Annnnd? Ummmmmmmmmmmmmmm
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If another vehicle is trying to pass your vehicle,
Vladimir [108]

Answer:

Reduce you're speed, and let the other vehicle pass you

8 0
3 years ago
A 14.0 gauge copper wire of diameter 1.628 mm carries a current of 12.0 mA . A) What is the potential difference across a 1.80 m
Serga [27]

Answer: a) 139.4 μV; b) 129.6 μV

Explanation: In order to solve this problem we have to use the Ohm law given by:

V=R*I whre R= ρ *L/A  where ρ;L and A are the resistivity, length and cross section of teh wire.

Then we have:

for cooper R=1.71 *10^-8* 1.8/(0.001628)^2= 11.61 * 10^-3Ω

and for silver R= 1.58 *10^-8* 1.8/(0.001628)^2=10.80 * 10^-3Ω

Finalle we calculate the potential difference (V) for both wires:

Vcooper=11.62* 10^-3* 12 * 10^-3=139.410^-6 V

V silver= 10.80 10^-3* 12 * 10^-3=129.6 10^-6 V

8 0
4 years ago
Read 2 more answers
The magnetic field at the center of a 1.50-cm-diameter loop is 2.70 mT . Part A. What is the current in the loop?
elixir [45]

Explanation:

It is given that,

Diameter of the circular loop, d = 1.5 cm

Radius of the circular loop, r = 0.0075 m

Magnetic field, B=2.7\ mT=2.7\times 10^{-3}\ T

(A) We need to find the current in the loop. The magnetic field in a circular loop is given by :

B=\dfrac{\mu_o I}{2r}

I=\dfrac{2Br}{\mu_o}

I=\dfrac{2\times 2.7\times 10^{-3}\times 0.0075}{4\pi \times 10^{-7}}

I = 32.22 A

(b) The magnetic field on a current carrying wire is given by :

B=\dfrac{\mu_o I}{2\pi r}

r=\dfrac{\mu_o I}{2\pi B}

r=\dfrac{4\pi \times 10^{-7}\times 32.22}{2\pi \times 2.7\times 10^{-3}}

r = 0.00238 m

r=2.38\times 10^{-3}\ m

Hence, this is the required solution.

8 0
3 years ago
Which of the following best describes a galaxy?
valentinak56 [21]

Answer:

B-Large groups of stars held together by gravity

Explanation:

4 0
3 years ago
sound is a longitudinal wave, and its speed depends on the medium through which it propagates. in air, sound travels at 343 m/s
melomori [17]

The speed of the sound wave in the medium, given the data is 3900 m

<h3>Velocity of a wave </h3>

The velocity of a wave is related to its frequency and wavelength according to the following equation:

Velocity (v) = wavelength (λ) × frequency (f)

v = λf

With the above formula, we can obtain the speed of the sound wave. Details below:

<h3>How to determine speed of the sound wave</h3>

The speed of the wave can be obtained as illustrated below:

  • Frequency (f) = 600 Hz
  • Wavelength (λ) = 6.5 m
  • Velocity (v) =?

v = λf

v = 6.5 × 600

v = 3900 m

Thus, the speed of the sound wave in the medium is 3900 m

Learn more about wave:

brainly.com/question/14630790

#SPJ4

8 0
1 year ago
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