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adelina 88 [10]
3 years ago
11

Kinetic energy depends on the height of an object above the ground?

Physics
1 answer:
s344n2d4d5 [400]3 years ago
5 0
Annnnd? Ummmmmmmmmmmmmmm
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Shattered glass from a window is scattered across the floor what is the chemical treatment
Mariulka [41]

Answer: something must drop it over

Explanation:

3 0
3 years ago
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A blacksmith heats a 1,540 g iron horseshoe to a temperature of 1445°c before dropping it into 4,280 g of water at 23.1°c. if th
Marta_Voda [28]
Given:
m₁ = 1540 g, mass of iron horseshoe
T₁ = 1445 °C, initial temperature of horseshoe
c₁ = 0.4494 J/(g-°C), specific heat

m₂ = 4280 g, mass of water
T₂ = 23.1 C, initial temperature of water
c₂ = 4.18 J/(g-°C), specific heat of water
L = 947,000 J heat absorbed by the water.

Let the final temperature be T °C.
For energy balance,
m₁c₁(T₁ - T) = m₂c₂(T - T₂) + L
(1540 g)*(0.4494 J/(g-C))*(1445-T C) = (4280 g)*(4.18 J/(g-C))*(T-23.1 C) + 947000 J
692.076(1445 - T) = 17890(T - 23.1) + 947000
10⁶ - 692.076T = 17890T - 413259 + 947000
466259 = 18582.076T
T = 25.09 °C

Answer: 25.1 °C
3 0
3 years ago
You can, in an emergency, start a manual transmission car by putting it in neutral, letting the car roll down a hill to pick up
Anna [14]

Answer:

The hill should be not less than 0.625 m high

Explanation:

This problem can be solved by using the principle of conservation of mechanical energy. In the absence of friction, the total mechanical energy is conserved. That means that

E_m=U+K is constant, being U the potential energy and K the kinetic energy

U=mgh

K=\frac{mv^2}{2}

When the car is in the top of the hill, its speed is 0, but its height h should be enough to produce the needed speed v down the hill.

The Kinetic energy is then, zero. When the car gets enough speed we assume it is achieved at ground level, so the potential energy runs out to zero but the Kinetic is at max. So the initial potential energy is transformed into kinetic energy.

mgh=\frac{mv^2}{2}

We can solve for h:

h=\frac{v^2}{2g}=\frac{3.5^2}{2(9.8)}=0.625m

The hill should be not less than 0.625 m high

8 0
3 years ago
What type of motion does an object have if it is falling with terminal velocity ?
Arte-miy333 [17]

Answer:

I believe force :|

Explanation:

4 0
3 years ago
Problem 02.061 For the given circuit, assume vS = 10 V, R1 = 9 Ω, R2 = 4 Ω, R3 = 4 Ω, R4 = 5 Ω, and R5 = 4 Ω. Reference Book &am
stich3 [128]

Answer:

Ws=8.75 Watts

Explanation:

As per fig. of prob 02.061, it is clear that R5 and R4 are in parallel, its equivalent Resistance will be:

\frac{1}{Req45}=\frac{1}{R4}+\frac{1}{R5}

\frac{1}{Req45}=\frac{1}{5}+\frac{1}{4}

\frac{1}{Req45}=0.2+0.25=0.45\\ Req45=2.22

Now, this equivalent Req45 is in series with R3, therefore:

Req345=R3+Req45\\Req345=4+2.22\\Req345=6.22

This Req345 is in parallel with R2, i.e

Req2345=(R2^{-1}+Req345^{-1}  )^{-1}\\ Req2345=(4^{-1}+6.22^{-1}  )^{-1} \\Req2345=2.43

Now this gets in series with R1:

Req12345=R1+Req2345\\Req12345=9+2.43\\Req12345=11.43

Now, the power delivered Ws is:

Ws=Vs*I=\frac{Vs^{2}}{Req}  \\Ws=\frac{10^{2} }{11.43} \\Ws=8.75 Watts

8 0
3 years ago
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