An airplane starts at rest and accelerates down the runway for 25 s. At the end of the runway, its final velocity is 75 m/s east
1 answer:
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Answer:
Explanation:
Electric force between two particles
= ( 9x10⁹x7.4 x 10⁻⁶ x 3.2 x 10⁻⁶ )/ (3.2 x 10⁻²)² ( Distance between particles is 1.6 +1.6 = 3.2 cm . )
= 20.81 x 10 = 208.1 N
1 ) Magnetic field due to movement of second charge
=
= 10⁻⁷ x 3.2 x 10⁻⁶ x 4 / (3.2 x 10⁻²)²
B = 1.25 x 10⁻⁹ T.
Due to this magnetic field , there is a force called magnetic force on first particle which will be expressed as follows
Force = Bqv
= 1.25 x 10⁻⁹ x 7.4 x 10⁻⁶ x 4
37 x 10⁻¹⁵ N
2 ) For magnetic force to be equal to electric force let velocity o particles be V
Then magnetic field due to second charge
= 10⁻⁷ x 3.2 x 10⁻⁶ x v / (3.2 x 10⁻²)²
= .3125 v x 10⁻⁹
Magnetic force on first charge
Bqv
= .3125 v x 10⁻⁹ x 7.4 x 10⁻⁶ x v
2.3125 x 10⁻¹⁵ v²
magnetic force = electric force
2.3125 x 10⁻¹⁵ v² = 208.1
v² = 90 x 10¹⁵
v² = 900 x 10¹⁴
v = 30 x 10⁷ m /s
Answer:
a) 0.05719 km/s^2
b) 0.00921 km/s^2
Explanation:
average acceleration can be calcuated as follows
a)
- In the initial time (), just before of race start the rocket is at rest. So
.
- After 3.22 s the rocket reach 663 km/h, So and the
. We convert units from km/h to km/s to have the same time units (seconds) the velocity would be:
(take into accoun that 1 h=3600 s)
and acceleration is:
b)
acceleration while stopping is calculate with the same formula but now
-we define the initial time () the instant just before begining the stopping. At this instant the velocity is 663 km/h which is the same as 0.18467 km/s.
-After 20 seconds the rocket stops. So tex]t_f=20 s[/tex] and
So, acceleration is: