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Dahasolnce [82]

3 years ago

7

An airplane starts at rest and accelerates down the runway for 25 s. At the end of the runway, its final velocity is 75 m/s east

. What is its acceleration?

1 answer:

elena-s [515]3 years ago

7 0

Answer

3m/s²

Explanation

u=o

t=25s

v=75m/s

from Newton's first law of motion,

v=u+at

75=0+a(25)

75=25a

a= 75/25

a=3m/s²

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A 300 gg bird flying along at 5.7 m/sm/s sees a 10 gg insect heading straight toward it with a speed of 29 m/sm/s (as measured b

liberstina [14]

Answer:

bird's speed = 4.58 m/s

Explanation:

given data

mass of bird mb = 300 g

velocity of bird vb = 5.7 m/s

mass of insect mi = 10 g

velocity of insect vi = - 29 m/s

solution

here momentum of system is constant

we apply here conservation of momentum so

mb × v + mi × v = mb × vb + mi × vi ....................1

v ( mb + mi ) = mb × vb + mi × vi

put here value and we get

v ( 300 + 10 ) = { 300 × 5.7 } + { 10 × (-29) }

v = $\frac{1710-290}{310}$

v = 4.58 m/s

8 0

3 years ago

Square root of 40 as a fraction

AysviL [449]

Answer:

158/25

Explanation:

I really hope I helped you!!

Have a good day! :)

8 0

3 years ago

Vector C has a magnitude of 24.6 m and points in the − y ‑ direction. Vectors A and B both have positive y ‑ components, and mak

frez [133]

Answer:

A= 61.35

B= -44.40

Explanation:

1. Using the components method we have:

$A_{x}= A cos \alpha\\B_{x}= B cos \beta\\C_{x}= 0\\\\A_{y}= A sin \alpha\\B_{y}= B sin \beta\\C_{y}= 24.6\\$

Considering that the vector sum $A+B+C=0$ , then:

$|V|=\sqrt{V_{x}^{2} +V_{y}^{2} }=0$

Then:

$V_{x} ^{2} =0; V_{x} =0\\V_{y} ^{2} =0; V_{y} =0$

It means the value of x and y component is 0.

2. Determinate the equations that describe each component:

$V_{x}= A cos \alpha -B cos \beta=0 (1)\\V_{y}= A sin \alpha +B sin \beta - C=0 (2)$

Form Eq. (1):

$A=B \frac{cos \beta}{cos \alpha} (3)$

Replacing A in Eq. (2):

$(B\frac{cos \beta}{cos \alpha})(sin \alpha)+ B sin\beta-C=0\\(B\frac{cos \beta}{cos \alpha})(sin \alpha)+ B sin\beta-=C\\\\B(\frac{cos \beta. sin \alpha}{cos \alpha}+ sin\beta)=C\\B=C(\frac{cos \beta. sin \alpha}{cos \alpha}+ sin\beta)^{-1} (4)$

Replacing values of C, α and β in (4):

$B= 24.6 (\frac{(cos 27.7)(sin 44.9)}{cos 44.9}+sin 27.7)^{-1} \\B= -44.4$

Replacing value of B in (3)

$A=-44.40\frac{cos 27.7}{sin 49.9} \\A= 61.35$

5 0

3 years ago

You may make the following measurements of an object 42kg and 22m3. What would the objects density be?

ki77a [65]

Density=mass/volume
to find the density
mass=42kg
volume=22m3
so density=42/22
density=1.9Kgm3

8 0

3 years ago

You are a doctor and Jack is your patient. Jack wants to know about his overall health. What is the best thing you can do to hel

Novay_Z [31]

Answer:

determine his body composition

Explanation:

5 0

3 years ago