Ask question

Ask question

All categories

3 years ago

11

How does net force affect the direction of motion?

2 answers:

erica [24]3 years ago

7 0

Balanced forces do not affect the motion of the object. Unbalanced forces affect the motion and velocity of an object.

A net force is the sum of all forces acting on an object. A net force is capable of accelerating a mass. For instance, if the wheels of a car push it forward with 5 Newtons and drag is 3 Newtons, the net force is 2 Newtons, forward. Motion to the right is positive. Motion to the left is negative.

spayn [35]3 years ago

6 0

Answer:

An unbalanced force (net force) acting on an object changes its speed and/or direction of motion. While the net force may not be in the same direction which the object is moving, it is always in the direction that the object is accelerating.

Explanation:

You might be interested in

El ancho de la uña de su dedo meñique se acerca a una unidad metrica comun ¿cual?

BartSMP [9]

Answer:

I have no clue what's really going on I'm just here to get answer maybe I will just try to get an answer but I have no clue I'm sorry I am confused and dint really know what to do here.

3 0

3 years ago

Calculate the acceleration of gravity as a function of depth in the earth (assume it is a sphere). You may use an average densit

Ber [7]

Solution :

Acceleration due to gravity of the earth, g $=\frac{GM}{R^2}$

$g=\frac{G(4/3 \pi R^2 \rho)}{R^2}=G(4/3 \pi R \rho)$

Acceleration due to gravity at 1000 km depths is :

$g=G\left(\frac{4}{3}\pi (R-d) \rho\right)$

$g=6.67 \times 10^{-11}\left(\frac{4}{3}\times 3.14 \times (6371-1000) \times 5.5 \times 10^3\right)$

$= 822486 \times 10^{-8}$

$=0.822 \times 10^{-2} \ km/s$

= 8.23 m/s

Acceleration due to gravity at 2000 km depths is :

$g=G\left(\frac{4}{3}\pi (R-d) \rho\right)$

$g=6.67 \times 10^{-11}\left(\frac{4}{3}\times 3.14 \times (6371-2000) \times 5.5 \times 10^3\right)$

$= 673552 \times 10^{-8}$

$=0.673 \times 10^{-2} \ km/s$

= 6.73 m/s

Acceleration due to gravity at 3000 km depths is :

$g=G\left(\frac{4}{3}\pi (R-d) \rho\right)$

$g=6.67 \times 10^{-11}\left(\frac{4}{3}\times 3.14 \times (6371-3000) \times 5.5 \times 10^3\right)$

$= 3371 \times 153.86 \times 10^{-8}$

= 5.18 m/s

Acceleration due to gravity at 4000 km depths is :

$g=G\left(\frac{4}{3}\pi (R-d) \rho\right)$

$g=6.67 \times 10^{-11}\left(\frac{4}{3}\times 3.14 \times (6371-4000) \times 5.5 \times 10^3\right)$

$= 153.84 \times 2371 \times 10^{-8}$

$=0.364 \times 10^{-2} \ km/s$

= 3.64 m/s

3 0

3 years ago

10. A man throws a water balloon down off the edge of a building. If he wants the water

stepladder [879]

Answer:

intinal speed should be 10

Explanation:

v = v0 + at

30 = v0 +10.2

then v0= 10

5 0

2 years ago

What do you call the height of a wave?

Lina20 [59]

Answer:

amplitude is the answer

5 0

3 years ago

Read 2 more answers

Do yall love your best friend if yall do all was keep them close to you have a good day

KatRina [158]

Thank you for the message my friend, yoU have a good day as well :)

7 0

2 years ago

Read 2 more answers