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viva [34]
3 years ago
11

How does net force affect the direction of motion?

Physics
2 answers:
erica [24]3 years ago
7 0
Balanced forces do not affect the motion of the object. Unbalanced forces affect the motion and velocity of an object.

A net force is the sum of all forces acting on an object. A net force is capable of accelerating a mass. For instance, if the wheels of a car push it forward with 5 Newtons and drag is 3 Newtons, the net force is 2 Newtons, forward. Motion to the right is positive. Motion to the left is negative.
spayn [35]3 years ago
6 0

Answer:

An unbalanced force (net force) acting on an object changes its speed and/or direction of motion. While the net force may not be in the same direction which the object is moving, it is always in the direction that the object is accelerating.

Explanation:

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An air track car with a mass of 6 kg and velocity of 4 m/s to the right collides with a 3 kg car moving to the left with a veloc
sammy [17]

Remember that moment before collision is equal to the moment after collision.

(m1 \times u1) + (m2 \times u2) = (m1 \times v1) + (m2  \times u2)

Plugging in our values,

(6 \times 4) - (3 \times 2) = (6 \times 1) + (3 \times v2) \\ 24 - 6 = 6 \times 3v2 \\ 18 = 18v2 \\ v2 = 1 {ms}^{ - 1}

8 0
2 years ago
The eagle drops the trout a height of 6.1 m the fish travels 7.9 m horizontaly before hitting the water what is the velocity of
Semenov [28]

The velocity of the eagle is 7.0 m/s

Explanation:

The motion of the fish is a projectile motion, which consists of two independent motions:

- A uniform motion (constant velocity) along the horizontal direction, where the horizontal velocity of the fish is equal to the horizontal velocity of the eagle

- An accelerated motion with constant acceleration (acceleration of gravity) in the vertical direction  

We start by analyzing the vertical motion, using the following suvat equation:

s=ut+\frac{1}{2}at^2

where:

s = 6.1 m is the vertical displacement of the fish

u = 0 is the initial vertical velocity of the fish

a=g=9.8 m/s^2 is the acceleration of gravity

t is the time

Solving for t, we find the time of flight of the fish:

t=\sqrt{\frac{2s}{a}}=\sqrt{\frac{2(6.1)}{9.8}}=1.12 s

Now we know that during this time, the fish travels a horizontal distance of

x = 7.9 m

Therefore, the horizontal velocity of the fish is

v_x = \frac{x}{t}=\frac{7.9}{1.12}=7.0 m/s

And therefore, this is the initial velocity of the eagle.

Learn more about projectile motion:

brainly.com/question/8751410

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6 0
3 years ago
You design toys for a toy company. Your boss wants you to hook up the lights in the toy car you are working on in the cheapest w
bezimeni [28]

Answer:

put the car on fire

Explanation:

if you put it on fire you would have a lot of light now

7 0
3 years ago
Read 2 more answers
The total distance from a house to a school to is 9.5 km. A student travels all the way from his house to the school and back to
marysya [2.9K]

Answer:

0

Explanation:

Displacement is a vector from initial to final point. Because initial and final point are the same, so displacement is 0.

6 0
3 years ago
To test the performance of its tires, a car
Rom4ik [11]

The coefficient of static friction is 0.222

Explanation:

In order for the car to remain in circular motion, the frictional force must be able to provide the necessary centripetal force. Therefore, the car will start skidding when the two forces are equal:

\mu mg=m\frac{v^2}{r}

where the term on the left is the frictional force, while the term on the right is the centripetal force, and where

\mu is the coefficient of static friction

m is the mass of the car

g is the acceleration of gravity

v is the speed of the car

r is the radius of the track

In this problem, we have:

r = 564 m

v = 35 m/s

g=9.8 m/s^2

And re-arranging the equation for \mu, we can find the coefficient of static friction:

\mu = \frac{v^2}{gr}=\frac{35^2}{(9.8)(564)}=0.222

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5 0
3 years ago
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