The resistance of the silver block is given by
where
is the silver resistivity
is the length of the block
is the cross-sectional area of the block
If we plug the data into the equation, we find the resistance of the silver block:
Answer:
F » magnetic force
B » magnetic flux density
l » length / circumference
r » radius
<u>Answer:</u> The correct answer is two electrons are shared between each hydrogen atom and the carbon atom bonded to it, and four electrons are shared between the carbon atoms.
<u>Explanation:</u>
Ethylene is a compound given by the chemical formula .
The bond present between hydrogen and carbon atoms or carbon and carbon atoms are covalent bonds. A covalent bond is formed by the sharing of electrons between the atoms combining.
A double bond is present between carbon and carbon atoms. So 2 pairs of electrons are shared which means in total of 4 electrons are shared.
Bond present between hydrogen and carbon atoms are single bonds. So, a pair of electrons is shared which means that in total of 2 electrons are shared.
Hence, the correct answer is two electrons are shared between each hydrogen atom and the carbon atom bonded to it, and four electrons are shared between the carbon atoms.
Given Information:
Magnetic field = B = 1×10⁻³ T
Frequency = f = 72.5 Hz
Diameter of cell = d = 7.60 µm = 7.60×10⁻⁶ m
Required Information:
Maximum Emf = ?
Answer:
Maximum Emf = 20.66×10⁻¹² volts
Explanation:
The maximum emf generated around the perimeter of a cell in a field is given by
Emf = BAωcos(ωt)
Where A is the area, B is the magnetic field and ω is frequency in rad/sec
For maximum emf cos(ωt) = 1
Emf = BAω
Area is given by
A = πr²
A = π(d/2)²
A = π(7.60×10⁻⁶/2)²
A = 45.36×10⁻¹² m²
We know that,
ω = 2πf
ω = 2π(72.5)
ω = 455.53 rad/sec
Finally, the emf is,
Emf = BAω
Emf = 1×10⁻³*45.36×10⁻¹²*455.53
Emf = 20.66×10⁻¹² volts
Therefore, the maximum emf generated around the perimeter of the cell is 20.66×10⁻¹² volts
Answer:
The fish is experiencing a water pressure of 502.8 kPa.
Explanation:
The water pressure the fish is experiencing can be found as follows:
(1)
Where:
g: is the gravity = 9.81 m/s²
h: is the height (depth) = 50.0 m
ρ: is the seawater's density = 1.025 g/cm³
By replacing the above values into equation (1) we have:
Therefore, the fish is experiencing a water pressure of 502.8 kPa.
I hope it helps you!