Speed differs from velocity in the same way that distance differs from displacement.
<span>You are given two cars, one in front of the other, that are traveling down the highway at 25 m/s. You are also given a frequency of 500 Hz of the car travelling behind it. You are asked what is the frequency heard by the driver of the lead car. This problem can be solved using the Doppler effect
sound frequency heard by the lead car = [(speed of sound + lead car velocity)/( speed of sound + behind car velocity)] * (sound of frequency of the behind car)
</span>sound frequency heard by the lead car = [(340 m/s + 25 m/s)/(340 m/s - 25 m/s)] * (500 Hz)
sound frequency heard by the lead car = 579 Hz
Answer:
1440 × 10⁴ N/C
Explanation:
Data provided in the question:
Charge density λ1 = 0.6 μC/cm = 6 × 10⁻⁵ C/m
a = 7.5 cm = 0.075 m
Now,
Electric field due to a line charge at a distance 'a' is given as:
Ex(P) = 
also,
we know
= 9 × 10⁹ Nm²/C²
Thus,
we have
Ex(P) = 
therefore,
Ex(P) = 
= 1440 × 10⁴ N/C
