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Basile [38]
3 years ago
11

What effect does air resistance have on the projectile

Physics
2 answers:
Vesnalui [34]3 years ago
7 0

more deceleration.

in vertical motion downwards => terminal velocity ... raindrops etc

tino4ka555 [31]3 years ago
7 0

Answer:

Decreases its maximum acceleration

Explanation:

Air resistance which is also known as drag force occurs with an object in air while in motion, it encounters air resistance which reduces its speed and reduces its maximum height. Example of bodies in which air resistance affects are rockets, bullets, a ball in air etc

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What did Thomson’s and Rutherford’s experiments have in common? They both used charged particles in their experiments. They both
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Both Thomson and Rutherford used charged particles in their experiments.

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An object in circular motion has velocity that is constantly changing. The direction of the acceleration is
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<h2>Answer: Toward the center of the circle.</h2>

This situation is characteristic of the uniform circular motion , in which the movement of a body describes a circumference of a given radius with constant speed.  

However, in this movement the velocity has a constant magnitude, but its direction varies continuously.

Let's say \vec{V} is the velocity vector, whose direction is perpendicular to the radius r of the trajectory, therefore   the acceleration \vec{a} is directed toward the center of the circumference.

 

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Give two examples of gravity in the solar system
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The planets revolving around the sun, The moon revolving around the Earth.

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during a lunar mission, it is necessary to increase the speed of a spacecraft by 2.2 m/s when it is moving at 400 m/s relative t
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The initial mass fraction of the spacecraft that must be burned and ejected to achieve an increase in speed is 0,00219 m/s

<h3>What fraction of the initial mass of the spacecraft?</h3>

Increase the speed: Vf-Vi = 2.2 m/s

Speed of aircraft: Vr = 400 m/s

Speed of ejected products: Vrel = 1000 m/s

The answer is:

V_f - V_i = V_{rel} log_{e} (\frac{mi}{mf})\\\\2.2 = 1000 log_{e} (\frac{mi}{mf})\\\\ log_{e} (\frac{mi}{mf} ) = \frac{2.2}{1000} \\\\ log_{e} (\frac{mi}{mf} ) = 0.0022

\frac{mi}{mf} = e^{0,0022} \\\\\frac{mf}{mi} = e^{-0,0022} \\\\\frac{mi-mf}{mi} = 1 - e^{-0,0022} = 0,00219

So, the initial mass fraction of the spacecraft that must be burned and ejected to achieve an increase in speed is 0,00219 m/s

Learn more about spaceship speed fraction brainly.com/question/28256735

#SPJ4

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