The reason is because the Earth is not a perfect sphere. The distance from the poles to the centre of the Earth is smaller and the gravity is slightly greater.
The distance from the equator to the centre is slightly bigger so gravity is slightly smaller.
Answer:
Both the frequency f and velocity v will increase.
When the radius reduces, the circumference of the circular path becomes smaller which means that more number of revolutions can be made per unit time as long as the force is kept constant; this is an increase in frequency.
Explanation:
The centripetal force acting on a mass in circular motion is given by equation (1);

where m is the mass of the object and r is radius of the circle. From equation one we see that the centripetal force is directly proportional to the square of the velocity and inversely proportional to the radius of the circular path.
However, according to the problem, the force is constant while the radius and the velocity changes. Therefore we can write the following equation;

Also recall that m is constant so it cancels out from both sides of equation (2). Therefore from equation we can write the following;

By observing equation (2) carefully, the ratio
will with the square root increase
since
is lesser than
.
Hence by implication, the value of
will be greater than
.
As the radius changes from
to
, the velocity also changes from
to
.
<span>You forgot to post the list of "following atoms", but
Fluorine ions have a -1 charge. So find the charges of the other ions and The number of Fluorines you'll need should match the </span>other ion's charge.
Answer:
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your answer is here
SI (International System of Units) (meter-kilogram-second-ampere-kelvin-mole-candela)
FPS (foot-pound-second)
MKS (meter-kilogram-second)
CGS (centimeter-gram-second)
EMU (Electromagnetic) (centimeter-gram-second-abampere)
ESU (Electrostatic) (centimeter-gram-second-abcoulomb)
Atomic (bohr-electron mass-atomic second-electron)
MTS (meter-tonne-second)
Explanation:
hope it may help you !!
Answer:
t = 0.2845Nm (rounded to 4 decimal places)
Explanation:
The disk rotates at a distance of an arc length of 28cm
Arc length = radius × central angle × π/180
28cm = 10cm × central angle × π/180
Central angle =
× 180/π ≈ 160.4°
Torque (t) = rFsin(central angle) , where F is the applied force
Radius in meters = 10/100 = 0.1m
t = 0.1m × 16N × sin160.4°
t = 0.2845Nm (rounded to 4 decimal places)