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3 years ago

PLEASE ANSWER FAST!!

Physics

2 answers:

nataly862011 [7]3 years ago

7 0

I think that it’s false I might be wrong but I want the points

Nostrana [21]3 years ago

6 0

The answer is true, because Newton's first law of motion states that "Any object continues in its state of rest or motion unless it is compelled by a net external force."

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The value of g is greater at the poles than at the equator why

Degger [83]

The reason is because the Earth is not a perfect sphere. The distance from the poles to the centre of the Earth is smaller and the gravity is slightly greater.
The distance from the equator to the centre is slightly bigger so gravity is slightly smaller.

4 0

2 years ago

Read 2 more answers

A centripetal force of 5.0 newtons is applied to a rubber stopper moving at a constant speed in a horizontal circle. If the same

mezya [45]

Answer:

Both the frequency f and velocity v will increase.

When the radius reduces, the circumference of the circular path becomes smaller which means that more number of revolutions can be made per unit time as long as the force is kept constant; this is an increase in frequency.

Explanation:

The centripetal force acting on a mass in circular motion is given by equation (1);

$F_c=\frac{mv^2}{r}....................(1)$

where m is the mass of the object and r is radius of the circle. From equation one we see that the centripetal force is directly proportional to the square of the velocity and inversely proportional to the radius of the circular path.

However, according to the problem, the force is constant while the radius and the velocity changes. Therefore we can write the following equation;

$\frac{mv_1^2}{r_1}=\frac{mv_2^2}{r_2}......................(2)$

Also recall that m is constant so it cancels out from both sides of equation (2). Therefore from equation we can write the following;

$v_2=\sqrt{\frac{v_1^2r_2}{r_1}} .................(2)$

By observing equation (2) carefully, the ratio $\frac{r_2}{r_1}$ will with the square root increase $v_1$ since $r_2$ is lesser than $r_1$ .

Hence by implication, the value of $v_2$ will be greater than $v_1$ .

As the radius changes from $r_1$ to $r_2$ , the velocity also changes from $v_1$ to $v_2$ .

3 0

3 years ago

If fluorine was in ionic compounds with ions of each of the following atoms, how many fluorines would be needed?

nevsk [136]

<span>You forgot to post the list of "following atoms", but

Fluorine ions have a -1 charge. So find the charges of the other ions and The number of Fluorines you'll need should match the </span>other ion's charge.

8 0

3 years ago

What are various systems of unit?

Naya [18.7K]

Answer:

hlw its jess bregoli

your answer is here

SI (International System of Units) (meter-kilogram-second-ampere-kelvin-mole-candela)

FPS (foot-pound-second)

MKS (meter-kilogram-second)

CGS (centimeter-gram-second)

EMU (Electromagnetic) (centimeter-gram-second-abampere)

ESU (Electrostatic) (centimeter-gram-second-abcoulomb)

Atomic (bohr-electron mass-atomic second-electron)

MTS (meter-tonne-second)

Explanation:

hope it may help you !!

6 0

2 years ago

Read 2 more answers

A disk of radius 10 cm is pulled along a frictionless surface with a force of 16 N by a string wrapped around the edge. At the i

drek231 [11]

Answer:

t = 0.2845Nm (rounded to 4 decimal places)

Explanation:

The disk rotates at a distance of an arc length of 28cm

Arc length = radius × central angle × π/180

28cm = 10cm × central angle × π/180

Central angle = $\frac{28}{10}$ × 180/π ≈ 160.4°

Torque (t) = rFsin(central angle) , where F is the applied force

Radius in meters = 10/100 = 0.1m

t = 0.1m × 16N × sin160.4°

t = 0.2845Nm (rounded to 4 decimal places)

8 0

3 years ago