Answer:
0.003034 s
1.035 m
4.5 m
Explanation:
= frequency of the tone = 329.6 Hz
= Time period of the sound wave
we know that, Time period and frequency are related as
= speed of the sound in the air = 341 ms⁻¹
wavelength of the sound is given as
= speed of the sound in the water = 1480 ms⁻¹
wavelength of the sound in water is given as
Answer:
8 signals received by twin A during the trip.
Explanation:
Given that,
Distance = 12 light year
Speed = 0.6 c
Time = 1 year
We need to calculate the time by A
Using formula of time
Put the value into the formula
Similarly,
The expression for distance cover by A
We need to calculate the time
Using formula of time
We need to calculate the signals received by twin A
Using formula for number of signals
Put the value into the formula
Hence, 8 signals received by twin A during the trip.
Pressure decreases with increasing altitude. The pressure at any level in the atmosphere may be interpreted as the total weight of the air above a unit area at any elevation. At higher elevations, there are fewer air molecules above a given surface than a similar surface at lower levels.
Answer:
4960 N
Explanation:
First, find the acceleration.
Given:
v₀ = 6.33 m/s
v = 2.38 m/s
Δx = 4.20 m
Find: a
v² = v₀² + 2aΔx
(2.38 m/s)² = (6.33 m/s)² + 2a (4.20 m)
a = -4.10 m/s²
Next, find the force.
F = ma
F = (1210 kg) (-4.10 m/s²)
F = -4960 N
The magnitude of the force is 4960 N.
