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marin [14]
3 years ago
13

Question 13 of 32

Chemistry
2 answers:
noname [10]3 years ago
8 0
Mark Brainliest please

Answer is D

Explanation

We know that pH=−log[H^+]

pH=8

Thus, 8= −log[H^+]

Hence [H+]=10^−8

Thus, concentration of H^+ is 10^−8M
FromTheMoon [43]3 years ago
7 0

Answer:

D

Explanation:

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At Jim's auto shop, it takes him minutes to do an oil change and minutes to do a tire change. Let be the number of oil changes h
Juli2301 [7.4K]

Answer:

The total time that Jim needs to change x oil changes and y tire changes is less than 180 min.

The time needed for x oil changes is 12 * x.

The time needed for y tire changes is 18 * y.

The total time is the sum of the above times and needs to be less than 180 that is

12 * x + 18 * y < 180 divide both sides of equation by 6

12/6 * x + 18/6*y < 180/6

2*x + 3*y < 30

2*x < 30 - 3*y divide both sides by 2 to get the inequality for x

x < 30/2 - 3/2*y = 15 - 1.5 y < 15 that is x < = 15

2*x + 3*y < 30

3*y < 30 - 2*x divide both sides by 3 to get the inequality for y

y < 30/3 - 2/3 *x = 10 - 2/3*x < 10 that is y < = 10

Also we can write x + y < x+ 3/2 * y < 15.

Explanation:

Jim's can do not more then 5 oil changes and not more then 10 tire changes or all together she can do not more then 15 total of oil and tire changes.

5 0
3 years ago
If I mix bleach and namona and throw it on a person what will happen​
satela [25.4K]

Answer:

They have the chance to inhale toxic fumes secreted by the mixture.

Explanation:

7 0
3 years ago
11. The modern periodic table is arranged in order of increasing atomic
Pani-rosa [81]

Answer:

number. so the option is c

6 0
2 years ago
Read 2 more answers
What is the element above the element in Group 3, Period 4?
Dennis_Churaev [7]
Scandium? Is that what you mean?
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3 years ago
4. An 82 kg hiker climbs Mt. Humphrey near Flagstaff. During a two hour period, the hiker's
bazaltina [42]

Answer:

\Delta E = 434253.96\,J, \Delta P = 60.313\,W

Explanation:

The change in energy is given by the change in gravitational potential energy:

\Delta E = m\cdot g \cdot \Delta h

\Delta E = (82\,kg)\cdot (9.807\,\frac{m}{s^{2}} )\cdot (540\,m)

\Delta E = 434253.96\,J

The average rate of change in terms of time is approximately this:

\Delta P = \frac{\Delta E}{\Delta t}

\Delta P = \frac{434253.96\,J}{(2\,h)\cdot (\frac{3600\,s}{1\,h} )}

\Delta P = 60.313\,W

8 0
3 years ago
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