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Amanda [17]
4 years ago
15

How much heat is absorbed when 4.5g of ice at 0°C melts to water at 10°C?

Chemistry
1 answer:
atroni [7]4 years ago
5 0

Answer: 90.45 joules

Explanation:

The quantity of Heat Energy (Q) absorbed by ice depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)

Thus, Q = MCΦ

In this case,

Q = ?

Mass of ice = 4.5g

C = 2.010 J/g°C (Though not provided, but the specific heat capacity of ice is 2.010 J/g°C)

Φ = (Final temperature - Initial temperature)

= 10°C - 0°C = 10°C

Then, Q = MCΦ

Q = 4.5g x 2.010 J/g°C x 10°C

Q = 90.45 joules

Thus, 90.45 joules of heat is absorbed by ice.

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a particular application calls for N2 g with a density of 1.80 g/L at 32 degrees C what must be the pressure of the n2 g in mill
baherus [9]

Answer:

1223.38 mmHg

Explanation:

Using ideal gas equation as:

PV=nRT

where,  

P is the pressure

V is the volume

n is the number of moles

T is the temperature  

R is Gas constant having value = 62.3637\text{ L.mmHg }mol^{-1}K^{-1}

Also,  

Moles = mass (m) / Molar mass (M)

Density (d)  = Mass (m) / Volume (V)

So, the ideal gas equation can be written as:

PM=dRT

Given that:-

d = 1.80 g/L

Temperature = 32 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T = (32 + 273.15) K = 305.15 K

Molar mass of nitrogen gas = 28 g/mol

Applying the equation as:

P × 28 g/mol  = 1.80 g/L × 62.3637 L.mmHg/K.mol × 305.15 K

⇒P = 1223.38 mmHg

<u>1223.38 mmHg must be the pressure of the nitrogen gas.</u>

5 0
3 years ago
35.0 mL of 12.0 M HCl is added to enough water to have a final volume of 1.20 L. What is the molarity of the final solution?
creativ13 [48]
<h3>Answer:</h3>

0.35 M

<h3>Explanation:</h3>

<u>We are given;</u>

  • Initial volume as 35.0 mL or 0.035 L
  • Initial molarity as 12.0 M
  • Final volume is 1.20 L

We are required to determine the final molarity of the solution;

  • Dilution involves adding solvent to a solution to make it more dilute which reduces the concentration and increases the solvent while maintaining solute constant.
  • Using dilution formula we can determine the final molarity.

M1V1 = M2V2

  • Rearranging the formula;

M2 = M1V1 ÷ V2

     = (12.0 M × 0.035 L) ÷ 1.2 L

      = 0.35 M

Thus, the final concentration of the solution is 0.35 M

6 0
3 years ago
How many grams of potassium (K) contain 5.11 x 10^22 atoms of potassium?
Darina [25.2K]

The atomic mass of K is 39

from Avogadro's law

39g of K contains 6.02x10^23 atoms

therefore if

39=6.02x19^23

X=5.11×10^22

making X the subject of the formula

X= (5.11×10^22×39)÷6.02×10^23

X= 33g

7 0
2 years ago
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Answer:

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5 0
3 years ago
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The answer is for this is A
3 0
3 years ago
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