<u>Given that </u>–
<u>We know that</u> –
Then –
![\qquad](https://tex.z-dn.net/?f=%5Cqquad)
![\bf\longrightarrow pOH = 14 -12.5](https://tex.z-dn.net/?f=%5Cbf%5Clongrightarrow%20pOH%20%3D%2014%20-12.5%20)
![\qquad](https://tex.z-dn.net/?f=%5Cqquad)
![\sf \longrightarrow pOH = 1.5](https://tex.z-dn.net/?f=%5Csf%20%5Clongrightarrow%20pOH%20%3D%201.5)
![\qquad](https://tex.z-dn.net/?f=%5Cqquad)
![\sf \longrightarrow [OH^- ] = 10^{-1.5 }](https://tex.z-dn.net/?f=%5Csf%20%5Clongrightarrow%20%20%5BOH%5E-%20%5D%20%3D%2010%5E%7B-1.5%20%7D)
![\qquad](https://tex.z-dn.net/?f=%5Cqquad)
![\bf \longrightarrow [OH^-] = 3.16 × 10^{-2}](https://tex.z-dn.net/?f=%5Cbf%20%5Clongrightarrow%20%5BOH%5E-%5D%20%3D%203.16%20%C3%97%2010%5E%7B-2%7D)
Now the number of moles of KOH need to ensure that concentration of Hydroxide anions is equal to –
![\qquad](https://tex.z-dn.net/?f=%5Cqquad)
![\bf \longrightarrow 3.74\: L \times \dfrac{3.16× 10^{-2}}{1 \: L }](https://tex.z-dn.net/?f=%5Cbf%20%5Clongrightarrow%20%203.74%5C%3A%20%20L%20%5Ctimes%20%5Cdfrac%7B3.16%C3%97%2010%5E%7B-2%7D%7D%7B1%20%5C%3A%20L%20%7D)
![\qquad](https://tex.z-dn.net/?f=%5Cqquad)
![\bf \longrightarrow 1. 18 × 10^{-1 }M](https://tex.z-dn.net/?f=%5Cbf%20%5Clongrightarrow%201.%2018%20%C3%97%2010%5E%7B-1%20%7DM%20)
Volume of the solution contains the need number of moles of Hydroxide anions –
![\qquad](https://tex.z-dn.net/?f=%5Cqquad)
![\sf \longrightarrow \dfrac{ 1.18×10^{-1} \: moles \: OH^-}{0.826 \: moles \: OH^-}](https://tex.z-dn.net/?f=%5Csf%20%5Clongrightarrow%20%5Cdfrac%7B%201.18%C3%9710%5E%7B-1%7D%20%5C%3A%20moles%20%5C%3A%20OH%5E-%7D%7B0.826%20%20%5C%3A%20moles%20%5C%3A%20OH%5E-%7D)
![\qquad](https://tex.z-dn.net/?f=%5Cqquad)
![\sf \longrightarrow 0.143 L](https://tex.z-dn.net/?f=%5Csf%20%5Clongrightarrow%200.143%20L%20)
![\qquad](https://tex.z-dn.net/?f=%5Cqquad)
![\sf \longrightarrow 0.143 \times 1000](https://tex.z-dn.net/?f=%5Csf%20%5Clongrightarrow%20%200.143%20%5Ctimes%201000)
![\qquad](https://tex.z-dn.net/?f=%5Cqquad)
![\pink{\bf\longrightarrow 143 mL }](https://tex.z-dn.net/?f=%5Cpink%7B%5Cbf%5Clongrightarrow%20143%20mL%20%7D)
______________________________________
If you were to compare the mass of the products and reactants in a reaction, you would find that the mass of the products is <span>equal to the mass of the reactants.</span>
Hello!!! I do not see any options!!!!!