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lora16 [44]
3 years ago
6

Answer this i will mark brainliest and don't steal points im gonna report you ​

Chemistry
2 answers:
jeka943 years ago
8 0

Answer:

The answer is c

Explanation:

Nuetrik [128]3 years ago
3 0
The answer is for this is A
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Someone please help me with question 4 ! EXTRA POINTS
Aleks04 [339]
1. B
2. C
3. A
That should do it
6 0
3 years ago
Read 2 more answers
Given 50.0 grams of Strontium, find grams of Phosphorus required for complete reaction
Sveta_85 [38]

Answer:

                     Mass = 11.78 g of P₄

Explanation:

                     The balance chemical equation is as follow:

                                          6 Sr + P4 → 2 Sr₃P₂

Step 1: Calculate moles of Sr as;

Moles = Mass / M/Mass

Moles = 50.0 g / 87.62 g/mol

Moles = 0.570 moles

Step 2: Find moles of P₄ as;

According to equation,

6 moles of Sr reacted with  =  1 mole of P₄

So,

0.570 moles of Sr will react with  =  X moles of P₄

Solving for X,

X = 1 mol × 0.570 mol / 6 mol

X = 0.0952 mol of P₄

Step 3: Calculate mass of P₄ as,

Mass = Moles × M.Mass

Mass = 0.0952 mol × 123.89 g/mol

Mass = 11.78 g of P₄

8 0
3 years ago
How many grams of hydrogen gas would be needed to form 8.0 grams of water? H2+O2=H2O
damaskus [11]
8 H2= 0.90 g , hope that helps
you with your work 

7 0
3 years ago
Acid strength in a series of h−a molecules increases with increasing size of
-BARSIC- [3]
Hello there!

The statement that Acid strength in a series of H-A molecules increases with increasing size of A is True.

When only the size is involved, increasing the size will increase the Acid strength because as size increases, the H-A bond will become weaker as the atoms will be farther apart. Acid strength is related to the ability to release H⁺ ions and a weaker H-A bond will release H⁺ more easily. 

Have a nice day!
8 0
3 years ago
A sample of nitrogen gas, (N2), occupies 45.0 mL at 27.00∘C and 80.0 kPa. What will be the pressure if the gas is cooled to −73.
maxonik [38]

Answer:

The new pressure is 53.3 kPa

Explanation:

This problem can be solved by this law. when the volume remains constant, pressure changes directly proportional as the Aboslute T° is modified.

T° increase → Pressure increase

T° decrease → Pressure decrease

In this case, temperature was really decreased. So the pressure must be lower.

P₁ / T₁ = P₂ / T₂

80 kPa / 300K =  P₂/200K

(80 kPa / 300K) . 200 K = P₂ →  53.3 kPa

6 0
3 years ago
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