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omeli [17]
3 years ago
9

While scuba diving with some friends, Deshawn notices that the air bubbles exhaled by his friends increase in size as they get c

loser to the surface of the water.
Why does this occur and which gas law explains it?
Physics
1 answer:
aleksklad [387]3 years ago
8 0

Answer:

Sample Response: As the air bubbles rise to the surface, the pressure on them decreases. This decrease in pressure allows the air to expand and each bubble increases in size. Boyle’s law explains why this occurs.

Explanation:

Edgenuity

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Jet001 [13]
Formula: Ca=Vt^2/r

centripetal acceleration(Ca)= ?
tangential speed(Vt)= 2.8m/s
Radius(r)=2m

Substitute: Ca=2.8^2/2
                  Ca=3.92m/s^2
3 0
4 years ago
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Light with a wavelength range of 141–295 nm shines on a silicon surface in a photoelectric effect apparatus, and a reversing pot
Ksju [112]

Answer:

a) the longest wavelength of the light that will eject electrons from the silicon surface is 258.7891 nm

b) maximum kinetic energy will electrons reach the anode is 0.5098 eV

Explanation:

Given:

Wavelength range = 141-295 nm

Potential of 3.5 V

For the silicon, the work function is Φ = 4.8 eV = 7.68x10⁻¹⁹J

Questions:

a) What is the longest wavelength of the light that will eject electrons from the silicon surface, λ = ?

b) With what maximum kinetic energy will electrons reach the anode,

a) The longest wavelength that will eject electrons:

\lambda =\frac{hc}{\phi  }

Here

h = Planck's constant = 6.625x10⁻³⁴J s

c = speed of light = 3x10⁸m/s

Substituting values:

\lambda =\frac{6.625x10^{-34}*3x10^{8}  }{7.68x10^{-19} } =2.588x10^{-7} m=258.7891nm

b) The maximum kinetic energy (one electron):

K=\frac{hc}{\lambda } -\phi =\frac{6.625x10^{-34}*3x10^{8}  }{141x10^{-9} } -7.68x10^{-19} =6.416x10^{-19} J=4.0098eV

Now, you need to calculate the potential difference:

K'=eV

Here

e = charge of electron = 1.6x10⁻¹⁹C

Substituting:

K'=1.6x10^{-19} *3.5=5.6x10^{-19} J=3.5eV

Now, the maximum kinetic energy of the electrons:

Kmax = 4.0098 - 3.5 = 0.5098 eV

6 0
4 years ago
A string that is restricted at both ends has a length of 1.50 m. what is the wavelength of the string’s fundamental frequency?
lara31 [8.8K]
Since it is restricted at both ends, λ/2 = length of string

λ/2 = 1.5m
λ = 1.5*2 = 3m
6 0
3 years ago
What is the speed of a bus that travels 250.0 km in 2.00 hours?
hram777 [196]
125 kmph

250=2
X=1

250/2= 125

5 0
3 years ago
A golfer imparts a speed of 29.0 m/s to a ball, and it travels the maximum possible distance before landing on the green. the te
Roman55 [17]

Explanation:

It is given that,

Initial speed of a golfer, u = 29 m/s

If it travels the maximum possible distance before landing. It means that it is projected at an angle of 45 degrees.

(a) We need to find the time spent by the ball in the air. It can be calculated by using second equation of motion.

s=ut+\dfrac{1}{2}at^2

Here,

a = -g

s = 0 (it is displacement and it is equal to 0 as the ball lands on the green).

So,

0=29\sin(45)t-\dfrac{1}{2}\times 9.8t^2\ (\text{Initial vertical component of velocity is taken})\\\\-4.9t^2+29\times \dfrac{1}{\sqrt2}t=0\\\\-4.9t^2+20.5t=0\\\\t=0,4.184\ s

So, it will take 4.184 seconds in the air.

(b) let x is the longest hole in one that the golfer can make if the ball does not roll when it hits the green. It can be given by :

x=vt\cos\theta\\\\x=29\times 4.184\times \cos(45)\\\\x=85.79\ m

Hence, this is the required solution.

8 0
4 years ago
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