What is one of the most common ways in which workers get hurt around machines?

What is the relationship of waste management and bioremediation?

andriy [413]

Answer:

In the simplest terms, bioremediation is a waste management process using live organisms to neutralize or remove harmful pollutants from contaminated areas. Bioremediation is an environmental science that amplifies natural biological actions to remedy or remediate polluted groundwater and contaminated soil.

Explanation:

4 0

2 years ago

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What is 7-?=4 i need help

aleksandr82 [10.1K]

Answer:

3

Explanation:

7-3=4

6 0

3 years ago

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What’s the number of gold atoms in a nanogram? a picogram?

zvonat [6]

Answer :

The number of gold atoms in nanogram is, $3.057\times 10^{12}$

The number of gold atoms in picogram is, $3.057\times 10^{9}$

Explanation :

As we know that the molar mass of gold is, 196.97 g/mole. That means, 1 mole of gold has 196.97 grams of mass of gold.

As we know that,

1 mole contains $6.022\times 10^{23}$ number of atoms.

First we have to determine the number of gold atoms in a nanogram.

As, 196.97 grams of gold contains $6.022\times 10^{23}$ number of gold atoms

And, 1 grams of gold contains $\frac{1g}{196.97g}\times (6.022\times 10^{23})$ number of gold atoms

So, $10^{-9}$ nanograms of gold contains $\frac{1g}{196.97g}\times (10^{-9})\times (6.022\times 10^{23})=3.057\times 10^{12}$ number of gold atoms

The number of gold atoms in nanogram is, $3.057\times 10^{12}$

Now we have to determine the number of gold atoms in a picogram.

As, 196.97 grams of gold contains $6.022\times 10^{23}$ number of gold atoms

And, 1 grams of gold contains $\frac{1g}{196.97g}\times (6.022\times 10^{23})$ number of gold atoms

So, $10^{-12}$ picograms of gold contains $\frac{1g}{196.97g}\times (10^{-12})\times (6.022\times 10^{23})=3.057\times 10^{9}$ number of gold atoms

The number of gold atoms in picogram is, $3.057\times 10^{9}$

8 0

3 years ago

Help..

iren [92.7K]

Answer:

7

Explanation:

A quotient is the answer to a division.For example,the quotient of 10 is 2 and 5 because 5÷10=2.

5 0

3 years ago

A freeway is being designed for a location in rolling terrain. The expected free-flow speed is 55 mi/h. During the peak hour, it

balu736 [363]

Answer:

3.

Explanation:

We start calcualting the factor for heavy-vehicle, that is,

$f_{HV} = \frac{1}{1+P_T(E_T-1)+P_R(E_R-1)}$

$E_T = 2.5$ for rolling terrain, so, replacing,

$f_{HV} = \frac{1}{1+0.18(2.5-1)+0}$

$f_{HV} = 0.7874$

We calculate the number of lanes by using the relation as follow:

$N=\frac{V}{\upsilon_p PHF f_{HV} f_p}$

$N=\frac{2700}{1915*0.88*0.7874*1}$

$N= 2.035$

In this way the necessary number of lanes is 3.

Note: To calculate $\upsilon_p$ you need to consult the Exhibit 23-2

in 'Highway capacity Manual' for 55mph and the LOS D criteria.

6 0

3 years ago