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Lostsunrise [7]
2 years ago
6

How to walk a dog dududududududududesssss

Engineering
2 answers:
bagirrra123 [75]2 years ago
6 0
Pick up a leash put the dog on the leash open the door/cage take the dog out and walk it
rusak2 [61]2 years ago
4 0
Putting them on a leash and picking a route and walking it
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What is kirchoff's current law?​
Anastaziya [24]

Answer:

The sum of all currents entering a junction is 0

Explanation:

Current cannot disappear, so the currents leaving a junction have to equal the currents entering a junction. If you would give the currents leaving the junction an opposite sign (e.g., negative) it implies that the sum of all these currents is exactly 0.

4 0
3 years ago
Read 2 more answers
Remember from Lab 3C that Mad Libs are activities that have a person provide various words, which are then used to complete a sh
Harlamova29_29 [7]

Answer:

Python code is explained below

Explanation:

CODE(TEXT): -

9A.py:-

def sentence(): #function to read input and display

  name = input("Enter a name: ") #input name

  place = input("Enter a place: ") #input place

  number = int(input("Enter a number: ")) #input number typecasted to int

  noun = input("Enter a plural noun: ") #input plural noun

  adjective = input("Enter an adjective: ") #input adjective

  print("\n{} went to {} to buy {} different types of {}".format(name, place, number, noun)) #format is used to display o/p

  print("but unfortunately, the {} were all {} so {} went back to {} to return them.\n".format(noun, adjective,name, place))

op = "n" #initially op = n i.e. user not wanting to quit

while op != "y" : #while user does not input y

  sentence() #input words from user

  op = input("Do you want to quit [y/n]? ") #prompt to continue or quit

  if op == "y": #if yes then print goodbye and exit

      print("Goodbye")

      break

  else: #else print newline and take input

      print("")

9B.py: -

#inputs are strings by default applying a split() function to a string splits it into a list of strings

#then with the help of map() function we can convert all the strings into integers

numbers = list(map(int, input("Enter the input: ").split()))

sum = 0 #sum is initially 0

for i in range(len(numbers)): #loops for all the elements in the list

  sum = sum + numbers[i] #add the content of current element to sum

avg = sum/ len(numbers) #average = (sum of all elements)/ number of elements in the list

max = numbers[0] #initially max = first number

for i in range(1, len(numbers)): #loops for all remaining elements

  if numbers[i] > max : #if their content is greater than max

      max = numbers[i] #update max

print("The average and max are: {:.2f} {}".format(avg, max)) #format is used to print in formatted form

#.2f is used to print only 2 digits after decimals

9C.py: -

#inputs are strings by default applying a split() function to a string splits it into a list of strings

#then with the help of map() function we can convert all the strings into integers

numbers = list(map(int, input("Enter a list of numbers: ").split()))

numbers = [elem for elem in numbers if elem >= 0] #using list comprehension

#loops for all elements of the list and keep only those who are >= 0

numbers.sort() #list inbuilt function to sort items

print("The non-negative and sorted numbers are: ", end = "")

for num in numbers: #for all numbers in the list print them

  print("{} ".format(num), end = "")

7 0
3 years ago
A BOD test is to be run on a sample of wastewater that has a five-day BOD of 230 mg/L. If the initial DO of a mix of distilled w
Alexxandr [17]

Answer:

Distribution factor P = =38.33

V = 7.826 ml

Explanation:

given details:

BOD =230 mg/l

DO inital = 8.0mg/l

DO final = 2.0mg/l

we know

BOD = [DO inital -DO final] * distribution factor

230 = [8 - 2] D.F

Distribution factor P = \frac{230}{6}

Distribution factor P = =38.33

THE RANGE OF WASTE WATER VOLUME IN 300 ml bottle is

distribution factor = \frac{300}{V}

V = \frac{300}{38.33}

V = 7.826 ml

6 0
3 years ago
A heat pump cycle is used to maintain the interior of a building at 15°C. At steady state, the heat pump receives energy by heat
Hoochie [10]

Answer:

a) Ql=33120000 kJ

b) COP = 5.6

c) COPreversible= 29.3

Explanation:

a) of the attached figure we have:

HP is heat pump, W is the work supplied, Th is the higher temperature, Tl is the low temperature, Ql is heat supplied and Qh is the heat rejected. The worj is:

W=Qh-Ql

Ql=Qh-W

where W=2000 kWh

Qh=120000 kJ/h

Q_{l}=14days(\frac{24 h}{1 day})(\frac{120000 kJ}{1 h})-2000 kWh(\frac{3600 s}{1 h})=33120000 kJ

b) The coefficient of performance is:

COP=\frac{Q_{h} }{W}=\frac{120000 kJ/h*14(\frac{24 h}{1 day}) }{2000 kWh(\frac{3600 s}{1 h}) } = 5.6

c) The coefficient of performance of a reversible heat pump is:

COP_{reversible}=\frac{T_{h} }{T_{h}-T_{l}  }

Th=20+273=293 K

Tl=10+273=283K

Replacing:

COP_{reversible}=\frac{293}{293-283}=29.3

4 0
3 years ago
An air conditioning system operating on reversed carnot cycle is required to remove heat from the house at a rate of 32kj/s to m
Brilliant_brown [7]

Answer:

(e) 1.64 kW

Explanation:

The Coefficient of Performance of the Reverse Carnot's Cycle is:

COP = \frac{T_{L}}{T_{H}-T_{L}}

COP = \frac{293.15\,K}{308.15\,K-293.15\,K}

COP = 19.543

Lastly, the power required to operate the air conditioning system is:

\dot W = \frac{\dot Q_{L}}{COP}

\dot W = \frac{32\,kW}{19.543}

\dot W = 1.637\,kW

Hence, the answer is E.

3 0
3 years ago
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