⚡️⚡️⚡️Kinetic energy ⚡️⚡️⚡️
A. Radio waves
Have the lowest frequencies
Answer:
Magnetic energy and electromagnetic energy form of potential energy followed by a form of kinetic energy.
(B) is correct option.
Explanation:
Given that,
Lists a form of potential energy followed by a form of kinetic energy
We know that,
Sound energy :
The movement of energy through object it is called sound energy. When a object produced vibration by force then it moves in wave.
Sound wave is example of kinetic energy.
Nuclear energy :
The store energy in the nucleus of the atom it is called nuclear energy. This energy released when occurs fusion and fission.
Nuclear energy is the example of potential energy
Magnetic energy :
Magnetic energy is a type of potential energy which is depend on distance and position in the magnetic field.
Electromagnetic energy :
Electromagnetic energy is light energy. it is type of kinetic energy.
Gravitational energy :
Gravitational energy is a type of potential energy. It is an energy related with gravity or gravitational force.
Elastic energy :
The store energy in elastic object it is called elastic energy. This energy is a type of potential energy.
Electrical energy :
The movement of electrons is called electrical energy. When electrons move through a wire then it is are called electricity. Electrical energy is type of kinetic energy.
Hence, Magnetic energy and electromagnetic energy form of potential energy followed by a form of kinetic energy.
(B) is correct option.
The current is defined as the amount of charge Q that passes through a given point of a wire in a time
![\Delta t](https://tex.z-dn.net/?f=%5CDelta%20t)
:
![I= \frac{Q}{\Delta t}](https://tex.z-dn.net/?f=I%3D%20%5Cfrac%7BQ%7D%7B%5CDelta%20t%7D%20)
Since I=500 A and the time interval is
![\Delta t=4.0 min=240 s](https://tex.z-dn.net/?f=%5CDelta%20t%3D4.0%20min%3D240%20s)
the charge is
![Q=I \Delta t=(500 A)(240 s)=1.2 \cdot 10^5 C](https://tex.z-dn.net/?f=Q%3DI%20%5CDelta%20t%3D%28500%20A%29%28240%20s%29%3D1.2%20%5Ccdot%2010%5E5%20C)
One electron has a charge of
![q=1.6 \cdot 10^{-19}C](https://tex.z-dn.net/?f=q%3D1.6%20%5Ccdot%2010%5E%7B-19%7DC)
, therefore the number of electrons that pass a point in the wire during 4 minutes is
![N= \frac{Q}{q}= \frac{1.2 \cdot 10^5 C}{1.6 \cdot 10^{-19}C}=7.5 \cdot 10^{23}](https://tex.z-dn.net/?f=N%3D%20%5Cfrac%7BQ%7D%7Bq%7D%3D%20%5Cfrac%7B1.2%20%5Ccdot%2010%5E5%20C%7D%7B1.6%20%5Ccdot%2010%5E%7B-19%7DC%7D%3D7.5%20%5Ccdot%2010%5E%7B23%7D%20%20)
electrons
Answer:
0.625m
Explanation:
Now Velocity of a wave ,V = frequency × wavelength
Wavelength =velocity /frequency
=500/800 =0.625m