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3 years ago

The Biot-Savart force law does not apply if the velocity is parallel to the field direction.

1 answer:

4 0

The statement ‘The Biot-Savart force law does not apply if the velocity is parallel to the field direction’ is true. The answer is letter A. Any electron moving in a conductor will produce a magnetic fiels around the flow. this is the fundamental of Biot – Savart law.

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What is the frequency of a transverse wave ?

yuradex [85]

Answer:

The number of complete vibration or wave made in

one second is called frequency.

7 0

3 years ago

Three equal point charges, each with charge 1.05 μCμC , are placed at the vertices of an equilateral triangle whose sides are of

kirza4 [7]

Answer:

The value is $U = 0.06 \ J$

Explanation:

From the question we are told that

The value of charge on each three point charge is

$q_1 = q_2 = q_3 =q= 1.05 \mu C = 1.05 *10^{-6} \ C$

The length of the sides of the equilateral triangle is $r = 0.500 \$

Generally the total potential energy is mathematically represented as

$U = k * [ \frac{q_1 * q_2}{r} + \frac{q_2 * q_3}{r} + \frac{q_3 * q_1}{r} ]$

=> $U = k * 3 * \frac{q^2}{r}$

Here k is coulomb constant with value $k = 9*10^{9}\ kg\cdot m^3\cdot s^{-4} \cdot A^{-2}.$

=> $U = 9*10^9 * 3 * \frac{(1.05 *10^{-6})^2}{0.5 }$

$U = 0.06 \ J$

6 0

3 years ago

A ball is kicked from the ground into the air at a velocity of 3 m/s at an angle 35° above the horizontal and hits the ground so

Dennis_Churaev [7]

Answer:2.45 m/s

Explanation:

Given

Launch velocity $(u)=3 m/s$

launch angle $=35^{\circ}$

as the vertical velocity first decreasing to zero and then increases to original value so its avg is zero .

$v_{avg}=\frac{displacement}{time}$

$v_{avg}=\frac{Range}{time}$

$v_{avg}=\frac{u\cos \theta \times t}{t}$

thus $v_{avg}=\frac{3\cos 35\times t}{t}$

$v_{avg}=3\cos 35=2.45 m/s$

8 0

3 years ago

WILL GIVE BRANLIEST<br> can you find a magnet with only a north pole? why or why not?

Novosadov [1.4K]

No you can’t because north and south attract eachother

3 0

3 years ago

A 500 kg object is hanging from a spring attached to the ceiling. If the spring constant in the spring is 900 N/kg, how far does

My name is Ann [436]

We are given that a 500 kg object is hanging from a spring. To determine the amount the spring is stretched we will use Hook's law, which states the following: