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forsale [732]
3 years ago
13

The Biot-Savart force law does not apply if the velocity is parallel to the field direction.

Physics
1 answer:
quester [9]3 years ago
4 0

The statement ‘The Biot-Savart force law does not apply if the velocity is parallel to the field direction’ is true. The answer is letter A. Any electron moving in a conductor will produce a magnetic fiels around the flow. this is the fundamental of Biot – Savart law.

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HELP!! ILL GIVE BRAINLIEST As we've learned so far, the popular model of the solar system shifted over
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Answer:

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3 years ago
Mary has a mass of 40 kg and sprints at 1 m/s. How much kinetic energy does she have?
Sav [38]

Answer:

20 J

Explanation:

Kinetic energy is given as half of the product of mass and the square of velocity of an object:

KE = \frac{1}{2}mv^2

where m = mass = 40 kg

v = velocity = 1 m/s

Hence, Mary's kinetic energy is:

KE = \frac{1}{2} * 40 * 1^2

KE = 20 * 1 = 20 J

She has a kinetic energy of 20 J.

8 0
3 years ago
Imagine holding a basketball in both hands, throwing it straight up as high as you can, and then catching it when it falls. At w
Alisiya [41]

Answer:

C. At the instant the ball reaches its highest point.

Explanation:

When a body is thrown up, it tends to come down due to the influence of gravitational force acting on the body. The body will be momentarily at rest at its maximum point before falling. At this maximum point, the velocity of the body is zero and since force acting on a body is product of the mass and its acceleration, the force acting on the body at that point will be "zero"

Remember, F = ma = m(v/t)

Since v = 0 at maximum height

F = m(0/t)

F = 0N

This shows that the force acting on the body is zero at the maximum height.

4 0
3 years ago
Compare and contrast the CONFLICT (choose one) in the short story you read with the elements appearing in The Watsons Go to Birm
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Answer:

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Explanation:

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4 0
3 years ago
A 75-m-long train begins uniform acceleration from rest. the the train has a speed of 23 m/s when it passes a railway worker tan
Lapatulllka [165]

Answer:

acceleration a = 1.04 m/s2

Explanation:

Assume the train has a speed of 23m/s when the last car passes the railway workers. Once this happens the last car would have traveled a total distance of the 180m distance between the railway worker standing 180 m from where the front of the train started plus the 75m distance from the first car to the last car:

s = 75 + 180 = 255 m

We can use the following equation of motion to find out the distance traveled by the car:

v^2 - v_0^2 = 2aswhere v = 23 m/s is the velocity of the car when it passes the worker, v_0 = 0m/s is the initial velocity of the car when it starts, a m/s2 is the acceleration, which we are looking for.

23^2 - 0^2 = 2*a*255

510a = 529

a = 529 / 510 = 1.04 m/s^2

8 0
3 years ago
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