All categories

3 years ago

The Biot-Savart force law does not apply if the velocity is parallel to the field direction.

1 answer:

4 0

The statement ‘The Biot-Savart force law does not apply if the velocity is parallel to the field direction’ is true. The answer is letter A. Any electron moving in a conductor will produce a magnetic fiels around the flow. this is the fundamental of Biot – Savart law.

You might be interested in

A meteoroid is moving towards a planet. It has mass m = 0.78×109 kg and speed v1 = 4.1×107 m/s at distance R1 = 2.8×107 m from t

wariber [46]

Answer:

$PE=81.755\, J$

Explanation:

Given that:

mass of meteoroid, $m=7.8\times 10^8 \,kg$

radial distance from the center of the planet, $R= 2.8\times 10^7 m$

mass of the planet, $M=4.4\times 10^{25}\, kg$

<u>For gravitational potential energy we have:</u>

$PE=G\frac{M.m}{R}$

substituting the respective values:

$PE=6.67\times 10^{-11}\times \frac{4.4\times 10^{25}\times 7.8\times 10^8}{2.8\times 10^7}$

$PE=81.755\, J$

5 0

3 years ago

Why the distance between two loudspeakers have to be large??

tangare [24]

Answer:because each speaker has a large angle of of coverage (horizontal and vertical)

They place them apart to prevent their signals (sounds produced) from getting into each other's way as this may cause interference (which may be destructive.

Explanation:

7 0

3 years ago

A golf ball (m = 59.2 g) is struck a blow that makes an angle of 50.5 ◦ with the horizontal. The drive lands 130 m away on a fla

fomenos

Answer:

The force is calculated as 338.66 N

Explanation:

We know that force is given by

$\overrightarrow{F}=\frac{d\overrightarrow{p}}{dt}=\frac{m(v_{f}-v_{o})}{\Delta t}$

We know that range of a projectile is given by

$R=\frac{v_{o}^{2}sin(2\theta )}{g}$

it is given that R=130 m applying values in the above equation we get

$R=\frac{v_{o}^{2}sin(2\theta )}{g}\\\\v_{0}=\sqrt{\frac{Rg}{sin(2\theta )}}\\\\\therefore v_{o}=\sqrt{\frac{130\times 9.81}{sin(2\times 50.5_{o}} )}\\\\v_{o}=36.04m/s$

Thus the force is obtained as

$\overrightarrow{F}=\frac{d\overrightarrow{p}}{dt}=\frac{59.2\times 10^{}-3(36.04-0)}{6.3\times 10^{-3}}$

Thus force equals $F=338.66N$

4 0

3 years ago

Read 2 more answers

Projectile Motion: A hobbyist launches a projectile from ground level on a horizontal plain. It reaches a maximum height of 72.3

marin [14]

Answer:

The angle of launch from the horizontal direction is 20.99° .

Explanation:

Let u and θ be the initial speed and angle of projection from the horizontal axis of the object respectively.

The equations for projectile motion are :

H = ( u² sin²θ)/ 2g ......(1)

Here H is maximum height of the projectile motion and g is acceleration due to gravity.

R = ( u² sin2θ)/g .......(2)

Here R is the maximum horizontal displacement of the object.

Rearrange equation (1) in terms of u².

u² = (2gH)/sin²θ

Substitute this equation in equation (2).

R = (2gH sin2θ) / (sin²θ x g)

R = (2H sin2θ)/sin²θ

Using trigonometry property, sin2θ = 2 cosθ sinθ

So, above equation becomes,

R = (2H x 2 cosθ sinθ)/sin²θ

R = (4H cosθ)/sinθ

tanθ = R/4H

θ = tan⁻¹(R/4H)

Substitute 111 m for R and 72.3 m for H in the above equation.

θ = tan⁻¹( 111/ 4 x 72.3 )

θ = tan⁻¹(0.38)

θ = 20.99°

3 0

3 years ago

How did scientists determine the age of the ocean floor

Umnica [9.8K]

the layers of rocks, the ancient treasures that are at the bottom of the sea, how old the coral is. But I don't think they determined how old it is, how would the dinosaurs that lived in water swim or any drink water. I don't know if this helps but hopefully it does. Also scientist have made advanced tech that could help with the age determination of the ocean floor.

6 0

3 years ago

Read 2 more answers