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avanturin [10]
3 years ago
8

A North American tourist takes his 26.0 W, 120 V AC razor to Europe, finds a special adapter, and plugs it into 220 V AC. Assumi

ng constant resistance, what power in watts does the razor consume as it is ruined?
Physics
1 answer:
Irina-Kira [14]3 years ago
7 0

Explanation:

For North America,

Power, P = 26 W

Voltage of AC razor, V = 120 V

For Europe,

Voltage of AC razor, V' = 220 V

The power of razor in North America is given by :

P=\dfrac{V^2}{R}\\\\R=\dfrac{V^2}{P}\\\\R=\dfrac{120^2}{26}\\\\R=553.84\ \Omega

Let P' is the power consumed by razor in Europe. Now,

P'=\dfrac{V'^2}{R}\\P'=\dfrac{220^2}{553.84}\\\\P'=87.38\ \Omega

So, the razor consumed 87.38 watts of power as it is ruined.

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Answer:

Magnitude of electric field = E = q/Aε0

Explanation:

Consider plates are placed at a distance of d. As given in the question the charge stored on the plates have magnitude q and given by:

                                          q = CV

And  

                                          V = q/C    ……. (i)

The capacitance is given by the following equation:  

                                         C = Aε0/d ……. (ii)

Put equation (ii) in (i) ,

                                          V = qd/ Aε0 …..(iii)    

The electric field is defined as:  

                                            E = V/d   …… (iv)

Put equation (iii) in (iv),

                                            E = qd/ Aε0d

                                            E = q/Aε0

Hence, the magnitude of electric field will be q/Aε0 .

                                         

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The correct answer is: Velocity

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mart [117]
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Answer:

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