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avanturin [10]
3 years ago
8

A North American tourist takes his 26.0 W, 120 V AC razor to Europe, finds a special adapter, and plugs it into 220 V AC. Assumi

ng constant resistance, what power in watts does the razor consume as it is ruined?
Physics
1 answer:
Irina-Kira [14]3 years ago
7 0

Explanation:

For North America,

Power, P = 26 W

Voltage of AC razor, V = 120 V

For Europe,

Voltage of AC razor, V' = 220 V

The power of razor in North America is given by :

P=\dfrac{V^2}{R}\\\\R=\dfrac{V^2}{P}\\\\R=\dfrac{120^2}{26}\\\\R=553.84\ \Omega

Let P' is the power consumed by razor in Europe. Now,

P'=\dfrac{V'^2}{R}\\P'=\dfrac{220^2}{553.84}\\\\P'=87.38\ \Omega

So, the razor consumed 87.38 watts of power as it is ruined.

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The period of a carrier wave is T=0.01 seconds. Determine the frequency and wavelength of the carrier wave. a. f=10 Hz, λ=3E8 me
makvit [3.9K]

Explanation:

It is given that,

The period of the carrier wave, T = 0.01 s

Let f and \lambda are frequency and the wavelength of the wave respectively. The relationship between the time period and the frequency is given by :

f=\dfrac{1}{T}

f=\dfrac{1}{0.01}

f = 100 Hz

The wavelength of a wave is given by :

\lambda=\dfrac{c}{f}

\lambda=\dfrac{3\times 10^8}{100}

\lambda=3\times 10^6\ m

So, the  frequency and wavelength of the carrier wave are 100 Hz and 3\times 10^6\ m respectively. Hence, the correct option is (c).

6 0
3 years ago
Water has a mass per mole of 18.0 g/mol, and each water molecule (H20) has 10 electrons. (a) How many electrons are there in one
Allushta [10]

Answer:

total number of electron in 1 litter is 3.34 × 10^{26} electron

Explanation:

given data

mass per mole = 18 g/mol

no of electron = 10

to find out

how many electron in 1 liter of water

solution

we know molecules per gram mole is 6.02 ×10^{23} molecules

no of moles is 1

so

total number of electron in water is = no of electron ×molecules per gram mole × no of moles

total number of electron in water is = 10 × 6.02 ×10^{23} × 1

total number of electron in water is = 6.02×10^{24} electron

and

we know

mass = density × volume    ..........1

here we know density of water is 1000 kg/m

and volume = 1 litter = 1 × 10^{-3} m³

mass of 1 litter = 1000 × 1 × 10^{-3}

mass = 1000 g

so

total number of electron in 1 litter =  mass of 1 litter × \frac{molecules per gram mole}{mass per mole}

total number of electron in 1 litter =  1000 × \frac{6.02*10{24}}{18}

total number of electron in 1 litter is 3.34 × 10^{26} electron

8 0
3 years ago
Any fracture or system of fractures along which Earth moves is known as a
azamat
The answer is B.) Stress 
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3 years ago
How many earths could fit inside jupiter
Snezhnost [94]

1,300 or more.

hope this helped :)

8 0
4 years ago
A radioactive material has a count rate of 400 per minute. It has a half life of 40 years. How long will it take to decay to a r
cestrela7 [59]

Answer:

160 years.

Explanation:

From the question given above, the following data were obtained:

Initial count rate (Cᵢ) = 400 count/min

Half-life (t½) = 40 years

Final count rate (Cբ) = 25 count/min

Time (t) =?

Next, we shall determine the number of half-lives that has elapse. This can be obtained as follow:

Initial count rate (Cᵢ) = 400 count/min

Final count rate (Cբ) = 25 count/min

Number of half-lives (n) =?

Cբ = 1/2ⁿ × Cᵢ

25 = 1/2ⁿ × 400

Cross multiply

25 × 2ⁿ = 400

Divide both side by 25

2ⁿ = 400/25

2ⁿ = 16

Express 16 in index form with 2 as the base

2ⁿ = 2⁴

n = 4

Thus, 4 half-lives has elapsed.

Finally, we shall determine the time taken for the radioactive material to decay to the rate of 25 counts per minute. This can be obtained as follow:

Half-life (t½) = 40 years

Number of half-lives (n) = 4

Time (t) =?

n = t / t½

4 = t / 40

Cross multiply

t = 4 × 40

t = 160 years.

Thus, it will take 160 years for the radioactive material to decay to the rate of 25 counts per minute.

7 0
3 years ago
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