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3 years ago

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A North American tourist takes his 26.0 W, 120 V AC razor to Europe, finds a special adapter, and plugs it into 220 V AC. Assumi

ng constant resistance, what power in watts does the razor consume as it is ruined?

1 answer:

Irina-Kira [14]3 years ago

7 0

Explanation:

For North America,

Power, P = 26 W

Voltage of AC razor, V = 120 V

For Europe,

Voltage of AC razor, V' = 220 V

The power of razor in North America is given by :

$P=\dfrac{V^2}{R}\\\\R=\dfrac{V^2}{P}\\\\R=\dfrac{120^2}{26}\\\\R=553.84\ \Omega$

Let P' is the power consumed by razor in Europe. Now,

$P'=\dfrac{V'^2}{R}\\P'=\dfrac{220^2}{553.84}\\\\P'=87.38\ \Omega$

So, the razor consumed 87.38 watts of power as it is ruined.

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Answer:

a) The severity index (SI) is 3047.749, b) The injured travels 0.345 meters during the collision.

Explanation:

a) The g-multiple of the acceleration, that is, a ratio of the person's acceleration to gravitational acceleration, is:

$a' = \frac{35\,\frac{m}{s^{2}} }{9.807\,\frac{m}{s^{2}} }$

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The time taken for the injured to accelerate to final speed is given by this formula under the assumption of constant acceleration:

$v_{f} = v_{o} + a \cdot t$

Where:

$v_{o}$ - Initial speed, measured in meters per second.

$v_{f}$ - Final speed, measured in meter per second.

$a$ - Acceleration, measured in $\frac{m}{s^{2}}$ .

$t$ - Time, measured in seconds.

$t = \frac{v_{f}-v_{o}}{a}$

$t = \frac{\left(12\,\frac{km}{h} \right)\cdot \left(1000\,\frac{m}{km} \right)\cdot \left(\frac{1}{3600}\,\frac{h}{s} \right)}{35\,\frac{m}{s^{2}} }$

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b) The initial and final speed of the injured are $1.944\,\frac{m}{s}$ and $5.278\,\frac{m}{s}$ , respectively. The travelled distance can be determined from this equation of motion:

$v_{f}^{2} = v_{o}^{2} + 2\cdot a \cdot \Delta s$

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$\Delta s = \frac{v_{f}^{2}-v_{o}^{2}}{2\cdot a}$

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