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anastassius [24]
3 years ago
8

A 10-kg piece of aluminum sits at the bottom of a lake, right next to a 10-kg piece of lead, which is much denser than aluminum.

Which one has the greater buoyant force on it? Please explain. Answer: B - the aluminum
A) Both have the same buoyant force.
B) the aluminum
C) the lead
D) It cannot be determined without knowing their volumes.
Physics
2 answers:
AysviL [449]3 years ago
8 0

The buoyant force on a submerged object is the weight of the water it displaces ... the water it pushes out of the way.  That amount is simply the volume of the submerged object.  So the more volume is submerged, the greater will be the buoyant force acting on it.

Since Aluminum is less-dense than lead, the same 10kg of Aluminum needs a bigger container to hold it than 10kg of lead needs.  The aluminum needs  more volume to hold the same mass.

The aluminum displaces more water.  So the buoyant force acting on the <em>aluminum</em> is greater than the buoyant force acting on the lead.<em> (B) </em>.

I'm guessing this is a big part of the reason why fishing sinkers are not made of aluminum.

Lelechka [254]3 years ago
5 0
I think that the answer is B
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Part CPart complete Determine the maximum force P that can be applied without causing the two 43-kg crates to move. The coeffici
Wewaii [24]

Answer:

the maximum force will be equal to 134.84 N  

Explanation:

We have given mass m = 43 kg

Coefficient of static friction \mu _s=0.32

Acceleration due to gravity g=9.8m.sec^2

We have to find the maximum force which , when applied there is no movement of crates

This maximum force will be equal to frictional force

Frictional force is given by f=\mu mg=0.32\times 43\times 9.8=134.84N

So the maximum force will be equal to 134.84 N  

3 0
3 years ago
During the course of a trajectory, is the vertical component of the velocity a constant or a changing value? ___________________
ICE Princess25 [194]

Answer:

1) Changing value

2) The velocity is decreasing for upward motion and increasing for downward motion due to gravitational force

Explanation:

1) A trajectory is the motion of an object which is being acted upon by specified forces. The flight path of an object in projectile motion is its trajectory

During the course of a trajectory, the vertical component of the velocity, v_y, is a changing value

2) The vertical component of the velocity first decreases, during the upward motion, according to the following equation;

v_y = u_y - g·t

Where;

v_y = The vertical component of the velocity after a given time, t

u_y = The initial vertical velocity

t = The time of motion of the trajectory

g = The acceleration due to gravity ≈ 9.8 m/s²

When the vertical velocity of the object decreases to zero, which is the point at which the object reaches the maximum height of its motion, the direction of the vertical motion of the object reverses, and object begins to accelerate and increase its velocity downwards according to the following equation;

v_y = u_y + g·t

Therefore, the velocity of the object is decreasing on its way up, and then increasing on its way down.

3 0
3 years ago
The gravity between me (68 kg) and my laptop (0.91 kg)
zepelin [54]
If you mean gravitational force, then it is GMm/r^2, which is G(68)(.91)/ (the distance between you and the laptop), where G is the universal gravitational constant
4 0
3 years ago
You have a large flashlight that takes 4 D-cell batteries, each with a voltage of 1.5 volts. If the current in the flashlight is
tino4ka555 [31]

Answer:

The answer is "C. 3.0 ohms". 

Explanation:

Ohm's law states the following:,

V = IR

where:

Voltage (V) = 1.5 volts × 4 batteries = 6.0 volts

Current (I) = 2.0 amps

Resistance (R) = ? ohms

To solve for Resistance (R) the equation must be rearranged this way:

 R = V / I

Then, the variables must be replaced with the known values:

 R = 6.0 volts / 2.0 amp

R = 3.0 ohms

The answer is  C. 3.0 ohms. 

------------

P.D: I got it right on PLATO

7 0
3 years ago
An apparatus like the one Cavendish used to find G has large lead balls that are 7.2 kg in mass and small ones that are 0.053 kg
uranmaximum [27]

Answer:

6.41537\times 10^{-9}N

Explanation:

Given that G=6.67259\times 10^{-11}Nm^2/kg, we can use Newton's Universal law of gravitation to determine the magnitude of the gravitational force as:

F=G\frac{m_1m_2}{r^2}\\\\\\=G=6.67259\times 10^{-11}Nm^2/kg\frac{7.2kg\times 0.053kg}{(0.063m)^2}\\\\\\=6.41537\times 10^{-9}N

Hence, the magnitude of the gravitational force between the masses is 6.41537\times 10^{-9}N

4 0
4 years ago
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