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anastassius [24]
3 years ago
8

A 10-kg piece of aluminum sits at the bottom of a lake, right next to a 10-kg piece of lead, which is much denser than aluminum.

Which one has the greater buoyant force on it? Please explain. Answer: B - the aluminum
A) Both have the same buoyant force.
B) the aluminum
C) the lead
D) It cannot be determined without knowing their volumes.
Physics
2 answers:
AysviL [449]3 years ago
8 0

The buoyant force on a submerged object is the weight of the water it displaces ... the water it pushes out of the way.  That amount is simply the volume of the submerged object.  So the more volume is submerged, the greater will be the buoyant force acting on it.

Since Aluminum is less-dense than lead, the same 10kg of Aluminum needs a bigger container to hold it than 10kg of lead needs.  The aluminum needs  more volume to hold the same mass.

The aluminum displaces more water.  So the buoyant force acting on the <em>aluminum</em> is greater than the buoyant force acting on the lead.<em> (B) </em>.

I'm guessing this is a big part of the reason why fishing sinkers are not made of aluminum.

Lelechka [254]3 years ago
5 0
I think that the answer is B
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\large{ \boxed{ \bf{ \color{red}{Universal \: law \: of \: gravitation}}}}

Every object in the universe attracts every other object with a force which is proportional to the product of their masses and inversely proportional to the square of the distance between them. The forces along the line joining the centre of the two objects.

❍ Let us consider two masses m1 and m2 line at a separation distance d. Let the force of attraction between the two objects be F.

According to universal law of gravitation,

\large{ \longrightarrow{ \rm{F \propto m_1 m_2}}}

Also,

\large{ \longrightarrow{ \rm{ F \propto  \dfrac{1}{ {d}^{2} } }}}

Combining both, We will get

\large{ \longrightarrow{ \rm{F  \propto  \dfrac{ m_1 m_2}{ {d}^{2}}}}}

Or, We can write it as,

\large{ \longrightarrow{ \rm{F  \propto  \:  G \dfrac{ m_1 m_2}{ {d}^{2} }}}}

Where, G is the constant of proportionality and it is called 'Universal Gravitational constant'.

☯️ Hence, derived !!

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If I am to understand this question correctly this is what asks you:

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