1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Likurg_2 [28]
3 years ago
14

A circuit contains three 1,200 ohm resistors connected in parallel. The circuit's supply voltage is 12 VDC. What is the total po

wer in this circuit?
a. 0.03 W
b. 1.42 W
c. 0.36 W
d. 0.47 W
Physics
1 answer:
Llana [10]3 years ago
5 0
-- The net effective resistance of three 1200-ohm resistors in
parallel is (1200/3) = 400 ohms.  That's what the battery sees.

-- Power = (voltage)² / (resistance)

               =      (12²)    /      (400)

               =        144    /      400

               =             0.36 watt . 

There's no such thing as "power in the circuit".

0.36 watt is the power dissipated by the resistors.
It's the rate at which the battery must supply energy,
and the rate at which the resistors blow it off in the form
of heat, for as long as the battery lasts.
You might be interested in
HELPPPPPPPPP Which option is a series of movement exercises for physical and mental health and is based on Hindu philosophy? O p
nika2105 [10]

Answer:

The correct answer is option ( D ) Yoga

Explanation:

hope it helps you dear :)

have a nice day

7 0
3 years ago
What is the magnitude of the velocity of a 25 kg mass that is moving with a momentum of 100 kg*m/s?
Gekata [30.6K]

Answer:

v= 4 m/s

Explanation:

Momenutm is, by definition, the product of mass and velocity.

p = mv

Let's replace what we know and solve for whatever's left

100 kg\cdot m/s = 25kg \cdot v \rightarrow v= 4 m/s

7 0
2 years ago
Physics question, any help is appreciated :)
Gekata [30.6K]

Runner 2 sees Runner 1 passing him with a velocity of 17 m/s west.


8 0
2 years ago
Read 2 more answers
Three equal charge 1.8*10^-8 each are located at the corner of an equilateral triangle ABC side 10cm.calculate the electric pote
Arlecino [84]

Answer:

If all these three charges are positive with a magnitude of 1.8 \times 10^{-8}\; \rm C each, the electric potential at the midpoint of segment \rm AB would be approximately 8.3 \times 10^{3}\; \rm V.

Explanation:

Convert the unit of the length of each side of this triangle to meters: 10\; \rm cm = 0.10\; \rm m.

Distance between the midpoint of \rm AB and each of the three charges:

  • d({\rm A}) = 0.050\; \rm m.
  • d({\rm B}) = 0.050\; \rm m.
  • d({\rm C}) = \sqrt{3} \times (0.050\; \rm m).

Let k denote Coulomb's constant (k \approx 8.99 \times 10^{9}\; \rm N \cdot m^{2} \cdot C^{-2}.)

Electric potential due to the charge at \rm A: \displaystyle \frac{k\, q}{d({\rm A})}.

Electric potential due to the charge at \rm B: \displaystyle \frac{k\, q}{d({\rm B})}.

Electric potential due to the charge at \rm A: \displaystyle \frac{k\, q}{d({\rm C})}.

While forces are vectors, electric potentials are scalars. When more than one electric fields are superposed over one another, the resultant electric potential at some point would be the scalar sum of the electric potential at that position due to each of these fields.

Hence, the electric field at the midpoint of \rm AB due to all these three charges  would be:

\begin{aligned}& \frac{k\, q}{d({\rm A})} + \frac{k\, q}{d({\rm B})} + \frac{k\, q}{d({\rm C})} \\ &= k\, \left(\frac{q}{d({\rm A})} + \frac{q}{d({\rm B})} + \frac{q}{d({\rm C})}\right) \\ &\approx 8.99 \times 10^{9}\; \rm N \cdot m^{2} \cdot C^{-2} \\ & \quad \quad \times \left(\frac{1.8 \times 10^{-8} \; \rm C}{0.050\; \rm m} + \frac{1.8 \times 10^{-8} \; \rm C}{0.050\; \rm m} + \frac{1.8 \times 10^{-8} \; \rm C}{\sqrt{3} \times (0.050\; \rm m)}\right) \\ &\approx 8.3 \times 10^{3}\; \rm V\end{aligned}.

4 0
3 years ago
a 45 kg ice skater initially skating at a velocity of 3 m/s speeds up to a velocity of 5 m/s. calculate the difference in the ma
ad-work [718]

Answer: 90 kgm/s

Explanation:

The momentum (linear momentum) p is given by the following equation:

p=m.V

Where:

m=45 kg is the mass of the skater

V is the velocity

In this situation the skater has two values of momentum:

Initial momentum: p_{1}=m.V_{1}

Final momentum: p_{2}=m.V_{2}

Where:

V_{1}=3 m/s

V_{1}=5 m/s

So, if we want to calculate the difference in the magnitude of the skater's momentum, we have to write the following equation(assuming the mass of the skater remains constant):

p=p_{2}-p_{1}=m.V_{2}-m.V_{1}

p=m(V_{2}-V_{1})

p=45 kg(5 m/s - 3 m/s)

Finally:

p=90 kgm/s

4 0
3 years ago
Read 2 more answers
Other questions:
  • Find the magnitude of vector A = i - 2j + 3k O V14 10 O4
    7·1 answer
  • Which best describes reflection and refraction?
    12·1 answer
  • What types of mediums are involved in the energy transfer
    12·1 answer
  • A basketball player throws a chall -1 kg up with an initial speed of his hand at shoulder height = 2.15 m Le gravitational poten
    11·1 answer
  • (a) How long will it take an investment to double in value if the interest rate is 8% compounded continuously? (Round your answe
    8·1 answer
  • The _________ principle states that the net electrical force on a specific charge is equal to the sum of the vector components o
    10·2 answers
  • Ocean waves are hitting a beach with a frequency of 0.100 Hz. Their average wavelength is 15.0 m. What is their average speed?
    8·1 answer
  • What is the mass of air in a room
    8·1 answer
  • 4.
    13·1 answer
  • What Is the west component of 85 m 25 north of west
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!