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forsale [732]
4 years ago
13

A parallel-plate capacitor, with air dielectric, is charged by a battery, after which the battery is disconnected. A slab of gla

ss dielectric is then slowly inserted between the plates. As it is being inserted:
Physics
1 answer:
Diano4ka-milaya [45]4 years ago
3 0

Complete Question

A parallel-plate capacitor, with air dielectric, is charged by a battery, after which the battery is disconnected. A slab of glass dielectric is then slowly inserted between the plates. As it is being inserted,  

A :

a force repels the glass out of the capacitor.  

B :

a force attracts the glass into the capacitor.    

C :

no force acts on the glass.      

D :

a net charge appears on the glass.      

E :

the glass makes the plates repel each other.

Answer:

The correct option is B

Explanation:

Generally when the glass dielectric is slowly inserted between the plated,

The positive plate of the capacitor will induce a negative charge on the glass while the negative  plate of the capacitor will induce a positive charge on glass which a electric field that posses an electric force that will attract the glass

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How can you convert a temperature expressed in degrees celsius to kelvin?
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Two objects (42.0 and 21.0 kg) are connected by a massless string that passes over a massless, frictionless pulley. The pulley h
Kazeer [188]

Answer:

a = 3.27 m/s²

T = 275 N

Explanation:

Given that:

Mass m₁ = 42.p0 kg

Mass m₂ = 21.0 kg

Consider both masses to be in a whole system, then:

The acceleration can be determined as:

(m_1+m_2)a = g(m_1-m_2)

Making acceleration the subject in the above formula;

a =\dfrac{g(m_1-m_2)}{(m_1+m_2)}

a =\dfrac{9.8(42.0-21.0)}{(42.0+21.0)}

a =\dfrac{9.8(21.0)}{(63.0)}

a =\dfrac{205.8}{(63.0)}

a = 3.27 m/s²

in the string, the tension is calculated using the formula:

T = \dfrac{2m_1m_2g}{(m_1+m_2)}

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8 0
3 years ago
A plane flies from base camp to lake a, 205 km away in the direction 20.0° north of east. after dropping off supplies it flies
miss Akunina [59]
Draw a diagram to illustrate the problem as shown in the figure below.

Camp A  is 20° north of east from the camp, therefore
m∠CAB = 80°
where C => base camp.

Let d = distance from lake B to the base camp, at x° west of south.
Apply the Law of Cosines to determine d.
d² = 205² + 175² - 2*205*175*cos80⁰
     = 6.0191 x 10⁴
d = 245.338 km

Apply the Law of Sines to obtain
\frac{sin(x+30)}{205}= \frac{sin80^{o}}{245.338}\\ \\ sin(x+30)=( \frac{205}{245.338})sin80^{o}=   0.8229
x+30 = sin⁻¹ 0.8229 = 55.4°
x = 25.4°

Answer:
The distance from lake B to base camp is 243.3km (nearest tenth).
The direction is 25.4° west of south.

7 0
3 years ago
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