The light must be either very dim or else non-existent.  
We can't see the light wave or the label.
        
             
        
        
        
Answer:
The angle of incidence is greater than the angle of refraction
Explanation:
Refraction occurs when a light wave passes through the boundary between two mediums.
When a ray of light is refracted, it changes speed and direction, according to Snell's Law:
 
where
:
 is the index of refraction of the 1st medium
 is the index of refraction of the 1st medium
 is the index of refraction of the 2nd medium
 is the index of refraction of the 2nd medium
 is the angle of incidence (the angle between the incident ray and the normal to the boundary)
 is the angle of incidence (the angle between the incident ray and the normal to the boundary)
 is the angle of refraction (the angle between the refracted ray and the normal to the boundary)
 is the angle of refraction (the angle between the refracted ray and the normal to the boundary)
In this problem, we have a ray of light passing from air into clear plastic. We have:
 (index of refraction of air)
 (index of refraction of air)
 approx. (index of refraction in clear plastic)
 approx. (index of refraction in clear plastic)
Snell's Law can be rewritten as

And since  , we have
, we have 

And so

Which means that
The angle of incidence is greater than the angle of refraction
 
        
             
        
        
        
Do you have a book about it? or if you have a dictionary?
        
             
        
        
        
Answer:
The turnover number of the enzyme molecule bovine carbonic anhydrase = 67,272,727.27 s^–1. 
Explanation:
Given:
The concentration of bovine carbonic anhydrase = total enzyme concentration = Et = 3.3 pmol⋅L^–1 = 3.3 × 10^–12 mol.L^–1
The maximum rate of reaction = Rmax (Vmax) = 222 μmol⋅L^–1⋅s^–1 = 222 × 10^–6 mol.L^–1⋅s^–1
The formula for the turnover number of an enzyme (kcat, or catalytic rate constant) = Rmax ÷ Et = 222 × 10^–6 mol.L^–1⋅s^–1 ÷ 3.3 × 10^–12 mol.L^–1 = 67,272,727.27 s^–1
Therefore, the turnover number of the enzyme molecule bovine carbonic anhydrase = 67,272,727.27 s^–1
 
        
             
        
        
        
Because it is if you know you know and it is also helping the sentwcnde and air and confiscation