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Pachacha [2.7K]
3 years ago
8

A force F produces an acceleration a on an object of mass m. A force 3F is exerted on a second object, and an acceleration 8a re

sults. What is the mass of the second object in terms of m?
a. 3m
b. 9m
c. 24m
d. (3/8)m
e. (8/3)m
Physics
1 answer:
Pie3 years ago
3 0

To solve this problem we will proceed to use Newton's second law for which the mass (m) multiplied by the acceleration (a) is defined as the Force (F) applied on a body, mathematically that is,

F = ma

According to the statement for the first object, the acceleration is,

a = \frac{F}{m} \rightarrow 1^{st} Object

For the second object the acceleration is,

8a = \frac{3F}{m_2} \rightarrow 2^{nd} Object

Solving for the mass of the second object,

m_2 = \frac{3F}{8a}

m_2 = \frac{3F}{8(F/m)}

m_2 = \frac{3}{8}m

Therefore the correct answer is D.

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Vadim26 [7]

Answer:

Probably the more correct version of the story is that Newton, upon observing an apple fall from a tree, began to think along the following lines: The apple is accelerated, since its velocity changes from zero as it is hanging on the tree and moves toward the ground. Thus, by Newton's 2nd Law there must be a force that acts on the apple to cause this acceleration. Let's call this force "gravity", and the associated acceleration the "acceleration due to gravity". Then imagine the apple tree is twice as high. Again, we expect the apple to be accelerated toward the ground, so this suggests that this force that we call gravity reaches to the top of the tallest apple tree.

3 0
3 years ago
Which one of the following acid-base imbalances? Arterial blood gas levels are obtained from the client. If the client’s results
nekit [7.7K]

Answer:

Explanation:

The correct answer is Metabolic alkalosis (D). A pH of 7.48 shows slight alkalinity, this normal concentration of Co2 in the blood ranges from 35 mmHg (millimetre Mercury) to 45 mmHg and the normal HCo3 ( Hydrogen trioxo carbonate ion) concentration ranges from 22mEq/L to 26mEq/L.

Therefor the patients pH level is high the Co2 level is normal and the HCo3 level is high. Hence, Metabolic alkalosis

7 0
3 years ago
A student is bicycling north along Main Street to school. Another student is timing the bicycling student in order to determine
MatroZZZ [7]

The average velocity is -4.17 m/s

Explanation:

The average velocity of a body is given by:

v=\frac{d}{t}

where

d is the displacement of the body

t is the time elapsed

For the student in this problem, we have:

Initial position: x_i = 450 m

Final position: x_f = 200 m

So the displacement is

d=x_f -x_i = 200 - 450 = -250 m

The time elapsed is

t = 60 s

Therefore, the average velocity is

v=\frac{-250}{60}=-4.17 m/s

Where the negative sign means the student is moving towards the origin.

Learn more about average speed and velocity:

brainly.com/question/8893949

brainly.com/question/5063905

#LearnwithBrainly

8 0
4 years ago
Determine the slit width that produces a diffraction pattern with the 2nd dark fringe at 6.2mm from the central fringe. The scre
Elanso [62]

Answer:

d= 0.242 mm

Explanation:

Slit width (d ) = ?

Screen distance ( D ) = 1.25 m

Wave length of light λ = 600 nm

Distance of n the dark fringe from centre

= n λ D / d

Here n = 2

so

6.2\times10^{-3}=\frac{2\times600\times10^{-9}}{d}

d=\frac{1500\times10^{-6}}{6.2}

d= 0.242 mm

4 0
3 years ago
A sailboat is traveling to the right when a gust of wind causes the boat to accelerate leftward at 2.5​​​​m​​/s2 for 4s. After t
Ber [7]

Answer:

+7.0 m/s

Explanation:

Let's take rightward as positive direction.

So in this problem we have:

a = -2.5 m/s^2 acceleration due to the wind (negative because it is leftward)

t = 4 s time interval

v = -3.0 m/s is the final velocity (negative because it is leftward)

We can use the following equation:

v = u + at

Where u is the initial velocity

We want to find u, so if we rearrange the equation we find:

u = v - at = (-3.0 m/s) - (-2.5 m/s^2)(4 s)=+7.0 m/s

and the positive sign means the initial direction was rightward.

6 0
4 years ago
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