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Readme [11.4K]
3 years ago
10

What can landmark cases produce that help courts decide how to interpret certain laws

Physics
2 answers:
Ganezh [65]3 years ago
6 0
A landmark case is a case in a court that is being studied due to its legal and historical significance. These cases are those that have lasting effect on the implementation of a law and these would often pertain to individual beliefs and rights. The landmark cases are keys to the interpretation of certain laws that were not present during the period of that certain case. It provides better understanding and grounds for the implementation of a certain law. Examples of landmark cases are Marbury v. Madison, McCulloch v. Maryland, Plessy v. Ferguson, Korematsu v. United States and Dred Scott v. Sandford.
netineya [11]3 years ago
4 0

Answer:

Standards and tests

Explanation:

(APEX)

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Which element has properties of electrical conductivity and luster and exists as a liquid at STP?
Bumek [7]

Answer:

Mercury - hydrargyrum (Hg)

Explanation:Mercury is a chemical element with the symbol Hg and atomic number 80. It is commonly known as quicksilver and was formerly named hydrargyrum.  

Symbol: Hg

Atomic number: 80

Atomic mass: 200.59 u

Melting point: -38.83 °C

Boiling point: 356.7 °C

Electron configuration: [Xe] 4d^14 5d^10 6s^2

Group :12

Ionization energy 1007.1J

Electronegativity :2

Crust Abundance : 0.085ppm

Electron Affinity : Unknown eV

Name: Mercury , the first planet in the solar system (Hg from former name hydrargyrum , from greek  hydr - water and  argyros silver .

I hope it helps. :).

8 0
3 years ago
To run the physics cart, the fan speed of the cart is manipulated. This is the (blank) variable. The cart accelerates due to the
vlabodo [156]

Answer:

A) Independent

B) Dependent

C) Mass

Explanation:

The speed applied to the physics cart is manipulated. This doesn't depend on another variable. Thus, speed is the (independent) variable.

The cart accelerates due to the speed applied to the cart. Acceleration depends on the speed applied. Thus, acceleration is therefore the (dependent) variable.

A “constant” is a parameter that remains the same regardless of the variables.

One parameter of the cart that is held constant is the (mass).

6 0
3 years ago
The planets Hox and Blox are near each other in the Dorgon system. The Dorgons have very advanced technology, and a Dorgon scien
dexar [7]
<h2>Answer: Decreasing the distance between Hox and Blox, increasing the mass of Hox, or increasing the mass of Hox and Blox. </h2>

Explanation:

According to the law of universal gravitation:

F=G\frac{m_{1}m_{2}}{r^2}  

Where:  

F is the module of the attraction force exerted between both planets  

G is the universal gravitation constant.  

m_{1} and m_{2} are the masses of both planets.  

r is the distance between both planets.

As we can see, the gravity force is directly proportional to the mass of the bodies and inversely proportional to the square of the distance that separates them.

In other words:

If we decrease the distance between both planets (Hox and Blox), the gravitational pull between them will increase.  

On the other hand, if we keep the distance between Hox and Blox, but we increase the mass of one of them, or increase the mass of both, the gravitational pull between them will also increase.

7 0
3 years ago
Read 2 more answers
Sarah invested 12000 in a unit trust 5 years ago, the value of the unit trust has increased by 7% per annum for the last 3 years
miss Akunina [59]

Answer:

The value of the fund today is $13831.72

Explanation:

Let us calculate the value at the end of each year, step by step. An annual  decrease of 3% corresponds to a multiplier 1.0-0.03 = 0.97. An increase of 7% corresponds to 1.07.

Value at the end of

year 1: 12000 * 0.97

year 2: 12000 * 0.97 * 0.97

year 3: 12000 * 0.97 * 0.97 * 1.07

year 4: 12000 * 0.97 * 0.97 * 1.07 * 1.07  

year 5: 12000 * 0.97 * 0.97 * 1.07 * 1.07 * 1.07 = 13831.72

The value of the fund today (end of year 5) is $13831.72

8 0
4 years ago
Read 2 more answers
What current flows through a 2.62 cm diameter rod of pure silicon that is 23.5 cm long, when 1000 v is applied to it? (such a ro
arlik [135]
Resistivity = resistance * Area / Length
resistance = ??
rho = 2.30 * 10^3 ohms meters.
l = 23.5 cm = 0.235 meters.
diameter = 2.62 cm = 0.0262 m
Radius = diameter / 2 = 0.0131 m
Area = pi r^2 where pi = 3.14
Area = 3.14 * 0.0131^2 = 0.000539 m^2

2.30 * 10^3 = R * 0.000539 /0.235
2.30 * 10^3 * 0.235/0.000539 = R
R = 1002783 which is about 1 meg ohm, but I'll use the calculation here.

E = 1000 V
R = 1 002 783 ohms
I = ???

E = I * R
1000 = I * 1002783 We should really round that resistor to 1 megohm or 1 * 10^6 ohms.

I = 1*10^3 / 1 * 10^6
I = 1 * 10^-3 amp = 1 milliamp. Pretty reasonable all things considered. 
6 0
3 years ago
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