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Paul [167]
3 years ago
12

HELP NOW PLS !!

Physics
1 answer:
Kitty [74]3 years ago
7 0

Answer:

The value is s =197.88 \  m  

Explanation:

From the question we are told that

    The  impulse is  I =  950 \  N\cdot s

    The mass is  m  =  12 \  kg

     The time t =  5 s

Generally impulse is mathematically represented as

         I =  F *  t

=>       F =  \frac{I}{t}

=>       F =  \frac{950 }{ 5 }

=>       F = 190 \  N

Generally force is mathematically represented as

      F =  m * a

=>    a =   \frac{F }{ m }

=>     a =   \frac{190 }{ 12  }

=>     a =   15.83 \  m/s^2

Generally from kinematic equation , the distance covered is  

      s =  ut +  \frac{1}{2}  * at^2

Here  u is the initial velocity of the cart and the value is u =  m/s

=>   s =  0 * 5 +  \frac{1}{2}  *  15.83 * 5^2  

=>   s =197.88 \  m  

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A concert loudspeaker suspended high off the ground emits 39 w of sound power. a small microphone with a 1.0 cm2 area is 60 m fr
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As we know that intensity of sound is defined as power received per unit area

so here the power of source is given as

P = 39 W

distance of microphone is given as

d = 60 m

now if loudspeaker is considered as spherical source then we will have

Intensity = \frac{power}{area}

Intensity = \frac{39}{4\pi r^2

here

r = d = 60 m

Intensity = \frac{39}{4\pi (60^2)}

Intensity = 0.86 \times 10^{-3} W/m^2

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3 years ago
A golfer is 40.8 meters away from the green and swings so that the ball has an initial velocity of +20 m/s. Which of the followi
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Answer:

C. 45

Explanation:

Took the quiz and got it right

7 0
3 years ago
How much energy does it take to melt a 16.87 g ice cube? ΔHfus = 6.02 kJ/mol How much energy does it take to melt a 16.87 g ice
Vilka [71]

Answer:

How much energy does it take to melt a 16.87 g ice cube? ΔHfus = 6.02 kJ/mol How much energy does it take to melt a 16.87 g ice cube? = 6.02 kJ/mol

A. 108 kJ

B. 102 kJ

C. 5.64 kJ

D. 936 kJ

E. none of the above

<em>5.64 kJ</em>

Explanation:

The Heat of fusion is the heat energy required to dissolve a given mass of ice at melting point.

<h3>Step by Step Calculation</h3>

The heat energy required to dissolve ice can be calculated using the expression below;

Q = ΔH_{f} x m ...............................................1

where Q is the heat energy required;

           ΔH_{f}  is the heat of fusion for ice;

           m is the mole

All the parameters above are provided in the question except m, so to get m we use the molar mass of water (also for ice) which is 18.01528 g/mol .

<em>This means that 18.01528 g of ice is contained in one mole, therefore the mole for 16.87 g of ice is given as;</em>

m = \frac{16.87g}{18.015g/mol}

m = 0.9364 mole of ices

Now the parameters are complete, we are given;

ΔH_{f}  = 6.02 kJ/mol

m = 0.9364 mol

Q =?

Substituting into equation 1, we have

Q =  6.02 kJ/mol x 0.9364 mol

Q = 5.64 kJ

<em>Therefore, the energy required to melt 16.87 g of ice is 5.64 kJ</em>

5 0
3 years ago
Explain why a real image must be produced in a camera and how the object and the lens are positioned to produce a real image whi
PilotLPTM [1.2K]
This is best explained through the use of an optics diagram, this is a little too complicated to explain in a short answer, and as I can't draw an appropriate diagram in this answer, I will point you to this excellent resource which explains what you have asked very well!

Go onto the BBC website (you should have access to it even if you aren't in the UK) and paste this after the BBC url,

/bitesize/intermediate2/physics/waves_and_optics/image_formation_from_lens/revision/1/
5 0
4 years ago
Reto: Aníbal desea construir una carpa de base hexagonal de 1,40 m de altura. El vértice de la base es de 0,80m y la longitud de
Rudiy27

Answer:

1.- para cubrir la superficie lateral 4.32 metros²

2.- Area de la base  2.15 metros²

3.- Volumen 1 m³

4.- Area total 6.47 metros²

Explanation:

El área lateral sera calcular el area de seis triangulos iguales cuya base es

0.80 de base x 6 lados = 4.80 metros perimetro de la base

4.80 perimetro de base x 1.80 arista lateral / 2 = 4.32m2

Area de la base:

Perímetro x Apotema / 2

Siendo la Apotema la altura de los triangulos que componen un hexagono calculada utilizando el teorema de pitágoras:

\sqrt{0.8^2 + (0.8/2)^2} = Apotema

Apotema = 0.894427191

Area: 4.80 x 0.894427191 / 2 = 2.146625258

sumando el area de la base mas el area lateral se obtiene el area total

2.15 + 4.32 = 6.47 metros

Volumen de la pirámide:

Area de la Base x Altura / 3

2.15 x 1.40 / 3 = 1.00333 m3

3 0
3 years ago
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