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Paul [167]
3 years ago
12

HELP NOW PLS !!

Physics
1 answer:
Kitty [74]3 years ago
7 0

Answer:

The value is s =197.88 \  m  

Explanation:

From the question we are told that

    The  impulse is  I =  950 \  N\cdot s

    The mass is  m  =  12 \  kg

     The time t =  5 s

Generally impulse is mathematically represented as

         I =  F *  t

=>       F =  \frac{I}{t}

=>       F =  \frac{950 }{ 5 }

=>       F = 190 \  N

Generally force is mathematically represented as

      F =  m * a

=>    a =   \frac{F }{ m }

=>     a =   \frac{190 }{ 12  }

=>     a =   15.83 \  m/s^2

Generally from kinematic equation , the distance covered is  

      s =  ut +  \frac{1}{2}  * at^2

Here  u is the initial velocity of the cart and the value is u =  m/s

=>   s =  0 * 5 +  \frac{1}{2}  *  15.83 * 5^2  

=>   s =197.88 \  m  

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Answer: Gravitational potential energy changes.

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2 years ago
We have three identical metallic spheres A, B, C. Initially sphere A is charged with charge Q, while B and C are neutral. First,
larisa [96]

Answer:

The final charges of each sphere are:   q_A = 3/8 Q , q_B = 3/8 Q ,               q_C = 3/4 Q

Explanation:

This problem asks for the final charge of each sphere, for this we must use that the charge is distributed evenly over a metal surface.

Let's start Sphere A makes contact with sphere B, whereby each one ends with half of the initial charge, at this point

                q_A = Q / 2

                q_B = Q / 2

Now sphere A touches sphere C, ending with half the charge

                q_A = ½ (Q / 2) = ¼ Q

                q_B = ¼ Q

Now the sphere A that has Q / 4 of the initial charge is put in contact with the sphere B that has Q / 2 of the initial charge, the total charge is the sum of the charge

                  q = Q / 4 + Q / 2 = ¾ Q

This is the charge distributed between the two spheres, sphere A is 3/8 Q and sphere B is 3/8 Q

                  q_A = 3/8 Q

                  q_B = 3/8 Q

The final charges of each sphere are:

                q_A = 3/8 Q

                q_B = 3/8 Q

                q_C = 3/4 Q

7 0
3 years ago
Match each chemical name with the correct chemical formula.
pochemuha
Is there any chemical names listed ?
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3 years ago
To win a prize at the county fair, you're trying to knock down a heavy bowling pin by hitting it with a thrown object. Should yo
Setler [38]

Answer:

Being an elastic object, rubber ball will be an ideal choice as it will bounce off the bowling pit and will experience a large change in momentum in comparison with the beanbag which will either slow down or come to a halt upon hitting a bowling pit. That is why rubber ball will experience a greater impulse and the bowling pin will experience the negative impulse of the rubber ball.

For Rubber Ball

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change in momentum = P

P = m(v_{f} -v_{i})\\v_{f}=-v_{i} \\  P = -2mv_{i}

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value of impulse will large if velocity is zero.

v_{f}=0\\ P = -mv_{i}

Explanation:

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