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Paul [167]
3 years ago
12

HELP NOW PLS !!

Physics
1 answer:
Kitty [74]3 years ago
7 0

Answer:

The value is s =197.88 \  m  

Explanation:

From the question we are told that

    The  impulse is  I =  950 \  N\cdot s

    The mass is  m  =  12 \  kg

     The time t =  5 s

Generally impulse is mathematically represented as

         I =  F *  t

=>       F =  \frac{I}{t}

=>       F =  \frac{950 }{ 5 }

=>       F = 190 \  N

Generally force is mathematically represented as

      F =  m * a

=>    a =   \frac{F }{ m }

=>     a =   \frac{190 }{ 12  }

=>     a =   15.83 \  m/s^2

Generally from kinematic equation , the distance covered is  

      s =  ut +  \frac{1}{2}  * at^2

Here  u is the initial velocity of the cart and the value is u =  m/s

=>   s =  0 * 5 +  \frac{1}{2}  *  15.83 * 5^2  

=>   s =197.88 \  m  

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Explanation:

Here is the complete question

The normal power for distant vision is 50.0 D. A young woman with normal distant vision has a 10.0% ability to accommodate (that is, increase) the power of her eyes. What is the closest object she can see clearly?

Solution

Now, the power of a lens, P = 1/f = 1/u + 1/v where f = focal length of lens, u = object distance from eye lens and v = image distance from eye lens.

Given that we require a 10 % increase in the power of the lens to accommodate the image she sees clearly, the new power P' = 50.0 D + 10/100 × 50 = 50.0 D + 5 D = 55.0 D.

Also, since the object is seen clearly, the distance from the eye lens to the retina equals the distance between the image and the eye lens. So, v = 2.00 cm = 0.02 m

Now, P' = 1/u + 1/v

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Formula used :

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Now put all the given values in the above formula, we get:

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