Answer:
A. potential energy is 258720 Joule
Explanation:
A.Gravitational potential energy is: PE = m × g × h
velocity = 15.33 m/s when the car reaches the bottom of the hill.
where, m = mass
g = acceleration due to gravity
h = height from the bottom of hill.
The potential energy is : m×g×h
=(2200×9.8×12)
=258720 Joule
B. at the bottom of the hill, the potential energy is converted into kinetic energy so PE at top = KE at bottom
kinetic energy= 
(
)
where v = velocity
m= mass
therefore, v=
or, v=
or, v=15.33 m/s
Explanation:
Let us assume that the maximum allowable horizontal distance be represented by "d".
Therefore, torque equation about A will be as follows.
d = ![\frac{[2 \times 75 \times (0.7+0.15+0.15) - 60 \times 0.15 - 252 \times 0.15 \times 2]}{252}](https://tex.z-dn.net/?f=%5Cfrac%7B%5B2%20%5Ctimes%2075%20%5Ctimes%20%280.7%2B0.15%2B0.15%29%20-%2060%20%5Ctimes%200.15%20-%20252%20%5Ctimes%200.15%20%5Ctimes%202%5D%7D%7B252%7D)
d = 0.409 m
Thus, we can conclude that the maximum allowable horizontal distance from the axle A of the wheelbarrow to the center of gravity of the second bag if she can hold only 75 N with each arm is 0.409 m.
Answer:
The frequency of the beat is 
Explanation:
From the question we are told that
The speed of the ride 
The frequency of the oboe is 
The temperature outside is 
Generally the speed of sound generated in air is mathematically evaluated as
Substituting value
The frequency of sound(generated by the musician on he park) getting to the musicians on the unicycle is mathematically evaluated as
substituting values
Since the musician on the park is not moving the frequency of sound (from the musicians riding the unicycle )getting to him is = 440Hz
The beat frequency these musician here is mathematically evaluated as
So 
D. you develop positive interactions with your peers
Answer:
It's True...................
