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frutty [35]
3 years ago
8

What investigations are best for demonstrating cause and effect relationship

Physics
2 answers:
poizon [28]3 years ago
8 0
The cause would be how the idea started or developed and the effect would be how they both effected you together
ella [17]3 years ago
7 0

Answer:

Experimental investigations are best for demonstrating cause-and-effect relationships.

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Where is the chart option found in the Excel application?
vodomira [7]

Answer:

its under the insert table

Explanation:

5 0
4 years ago
If the frequency of wave is 400 Hz and its
agasfer [191]

Answer:

D) 1000 m/s

Explanation:

wavelength = \frac{velocity}{frequency}

You have the wavelength and frequency, you just need to solve for velocity. You can do this by multiplying each side of the equation by frequency.

Hope this helps.

8 0
4 years ago
A girl is bouncing on a trampoline where is her gravitational potential energy a maximum and where is her kinetic energy maximum
Stella [2.4K]

Answer:

When you jump down, your kinetic is converted to potential energy of the stretched trampoline. The trampoline's potential energy is converted into kinetic energy, which is transferred to you, making you bounce up. At the top of your jump, all your kinetic energy has been converted into potential energy. Right before you hit the trampoline, all of your potential energy has  been converted back into kinetic energy. As you jump up and down your kinetic energy increases and decrease.

7 0
3 years ago
Tarzan is in the path of a pack of stampeding elephants when Jane swings in to the rescue on a rope vine, hauling him off to saf
timurjin [86]

Answer:

h = 3.56 m

Explanation:

  • Assuming no friction on the rope or air resistance, we can apply the conservation of mechanical energy principle to the first part of the trajectory, from when Jane starts her swing till she catches Tarzan at the ground level.

⇒      \Delta K + \Delta U = 0 (1)

  • Rearranging terms, we get:

        U_{ij} + K_{ij} = U_{fj} + K_{f}   (2)

  • Now, as Jane starts from rest, Kij =0.
  • if we choose the ground level as our zero reference level, it will be also  Ufj = 0.
  • Replacing in (2) by the expressions of Uij and Kfj, we have:

        m_{j} * g* h_{ij} = \frac{1}{2} * m_{j} * v_{fj} ^{2}  (3)

  • Replacing in (3) by the givens, and rearranging terms, we can solve for vfj, as follows:

       v_{fj} =\sqrt{2*9.8 m/s2*27 m} = 23 m/s (4)

  • Now, as once jane catches Tarzan, both continue swinging together, we can take the catching moment as a completely inelastic collision.
  • Assuming no external forces act during the collision, total momentum must be conserved.

⇒     p_{o} = p_{f}    (5)

  • Assuming that Tarzan is at rest when Jane catches him, the initial momentum will be simply as follows:

        p_{o} = m_{j} * v_{j} = 49 kg * 23 m/s = 1127 kg*m/s (6)

  • The final momentum, will be just the product of the combined mass of Jane and Tarzan times the common speed for them after the collision:

        p_{f} = (m_{j} + m_{t} ) * v_{jt} = 135 kg*  v_{jt}  (7)

  • As (6) and (7) are equal each other, we can solve for vjt, as follows:

       v_{jt} = \frac{1127 kg*m/s}{135 kg} = 8.35 m/s (8)

  • Finally we can apply the same energy conservation principle to the last part of the trajectory, as follows:

       U_{ijt} + K_{ijt} = U_{fjt} + K_{fjt}   (9)

  • We know that Uijt = 0 and also that Kfjt = 0, due to both starts from the ground level and reach to the highest point before starting to fall down, so at this point, the kinetic energy will be zero.
  • Replacing by the givens and the result from (8), we can solve for the h as follows:
  • h_{f} =\frac{v_{ijt} ^{2} }{2*g} = \frac{69.7m2/s2}{2*9.8m/s2} = 3.56 m
8 0
3 years ago
A box weighing 4.0 N is lifted 3.0 meters. How much work is done on the box?
Rashid [163]

The answer is 12 J

because you have to multiply the two together. hope it helps


6 0
3 years ago
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