Question

A vertical spring with stiffness k originally is at rest with no mass attached. Then, a mass M is attached, and the spring rocks back and forth until it is at rest at a new equilibrium position. What is this position in terms of g, M, and k?

Answer 1

Answer:

The position of the spring in terms of g, m & k is $x = \frac{m g}{k}$

Explanation:

Stiffness of the spring = k

Mass = m

When a mass m is attached with the spring then spring stretched. in that case the force exerted on the spring is equal to weight of the mass attached.

⇒ Force exerted on the spring F = k x

⇒ m g = k x

⇒ $x = \frac{m g}{k}$

This is the position of the spring in terms of g, m & k.