A vertical spring with stiffness k originally is at rest with no mass attached. Then, a mass M is attached, and the spring rocks
1 answer:
Answer:
The position of the spring in terms of g, m & k is
Explanation:
Stiffness of the spring = k
Mass = m
When a mass m is attached with the spring then spring stretched. in that case the force exerted on the spring is equal to weight of the mass attached.
⇒ Force exerted on the spring F = k x
⇒ m g = k x
⇒
This is the position of the spring in terms of g, m & k.
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Hello
The bullet is moving by uniformly accelerated motion.
The initial velocity is
, the final velocity is 
, and the total time of the motion is 
, so the acceleration is given by
where the negative sign means that is a deceleration.
Therefore we can calculate the total distance covered by the bullet in its motion using
So, the bullet penetrates the sandbag 1.8 meters.
The bullet is moving by uniformly accelerated motion.
The initial velocity is
where the negative sign means that is a deceleration.
Therefore we can calculate the total distance covered by the bullet in its motion using
So, the bullet penetrates the sandbag 1.8 meters.
Answer:
final displacement lf = 0.39 m
Explanation:
from change in momentum equation:
given: m = 0.4kg, y/x = 19/85, li = 1.9 m,
\delta p = 1.27 kg*m/s.
putting all value to get the final displacement value
final displacement lf = 0.39 m