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dimaraw [331]
4 years ago
12

Which statement correctly stated kepler's 3rd law of planetary motion?

Physics
2 answers:
nadya68 [22]4 years ago
8 0
When you square the "year" of each planet and divide it by the cube of its distance, or axis from the sun, the number would be the same for all the planets
svetlana [45]4 years ago
6 0

Answer:D

Explanation: the square of the orbital periods of the planets are directly proportional to the cubes of their average distances from the sun

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If you were to drop a rock from a tall building, assuming that it had not yet hit the ground, and neglecting air resistance, how
taurus [48]
T=2s
g=10m/s2
h=?
free fall: h=gt2/2
              h= 10*4/2
               h=40/2
              h=20m








3 0
3 years ago
What is it called when velocity changes over time
natka813 [3]
Well,

When an object's velocity changes, we call it acceleration.

Acceleration: The time rate of change in an object's velocity
3 0
4 years ago
Read 2 more answers
Please help I'm stuck on this question ​
Afina-wow [57]

Answer:

increase

decrease

Explanation:

using formula

Vt=mg/6πηr

so if m increases V increases

r is the denominator so if r increases V decreases

8 0
2 years ago
A 43.9-g piece of copper (CCu= 0.385 J/g°C) at 135.0°C is plunged into 254 g of water at 39.0°C. Assuming that no heat is lost t
Semmy [17]

Answer:

T = 40.501\,^{\textdegree}C

Explanation:

The interaction of the piece of copper and water means that the first one need to transfer heat in order to reach a thermal equilibrium with water. Then:

-Q_{out,Cu} = Q_{in,H_{2}O}

After a quick substitution, the expanded expression is:

-(43.9\,g)\cdot (0.385\,\frac{J}{g\cdot ^{\textdegree}C} )\cdot (T-135^{\textdegree}C) = (254\,g)\cdot (4.187\,\frac{J}{g\cdot ^{\textdegree}C} )\cdot (T-39\,^{\textdegree}C)

-16.902\,\frac{J}{^{\textdegree}C}\cdot (T-135^{\textdegree}C) = 1063.498\,\frac{J}{^{\textdegree}C} \cdot  (T-39^{\textdegree}C)

43758,192\,J = 1080.4\,\frac{J}{^{\textdegree}C}\cdot T

The final temperature of the system is:

T = 40.501\,^{\textdegree}C

8 0
3 years ago
Read 2 more answers
John is traveling north at 20 meters/second and his friend Betty is traveling south at 20 meters/second. If north is the positiv
Tpy6a [65]
I think it's just 20/20
3 0
3 years ago
Read 2 more answers
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