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dimaraw [331]
4 years ago
12

Which statement correctly stated kepler's 3rd law of planetary motion?

Physics
2 answers:
nadya68 [22]4 years ago
8 0
When you square the "year" of each planet and divide it by the cube of its distance, or axis from the sun, the number would be the same for all the planets
svetlana [45]4 years ago
6 0

Answer:D

Explanation: the square of the orbital periods of the planets are directly proportional to the cubes of their average distances from the sun

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Answer:

Species A and C

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How does the polar jet stream affect temperature and precipitation in North America?
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It increases the precipitation in North America.
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Which of these observations would show a chemical
11Alexandr11 [23.1K]

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6 0
4 years ago
Why might the measurements of ""true distances"" be different for different groups even though they are measuring the same dista
Mamont248 [21]

While measuring , there are a lot of errors which can happen due to which ""true distances"" be different for different groups even though they are measuring the same distance.

While measuring , there are a lot of errors which can happen , to find the most correct value in order to make the result precise and accurate number of measurements needed to be done in order to reduce the error

As nothing can be measured with full precision and accuracy, different measurements for different groups even though they are measuring the same distance.

To learn more about  accuracy here

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5 0
2 years ago
When a slice of buttered toast is accidentally pushed over the edge of a counter, it rotates as it falls. Suppose the distance t
tankabanditka [31]

Answer:

7.38 rad/s

Explanation:

Assume no air resistance, we can first calculate the time it takes for the toast to be dropped 0.89m to the floor. Since we have

h = \frac{gt^2}{2}

where g = 9.81m/s^2 and h = 0.89 m

t^2 = \frac{2h}{g} = \frac{2*0.89}{9.81} \approx 0.181

t = \sqrt{0.811} \approx 0.426 s

This is also the time for the toast to flip one time at a constant angular speed. The angle it covered would be at \theta = \pi radian.

So the smallest angular speed it needs to hit and topple butter-side down is

\omega = \frac{\theta}{t} = \frac{\pi}{0.426} \approx 7.38 rad/s

6 0
3 years ago
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