Answer:
PE=0.92414J and KE=0.28175J
Explanation:
Gravitational potential energy=mass*gravity*height
PE=mgh
Data,
M=0.046kg
H=2.05m
g=9.8m/s^2
PE=0.046kg * 9.8m/s^2 * 2.05m
PE =0.92414J
KE=1/2mv^2
V=3.5m/s
KE=[(0.046kg)*(3.5m/s)^2]\2
KE=0.28175J
A. Q= It
30E-3A=q
Ne = q
30E-3/1.6*10-19= N
N= 1.8*10^16 electrons
B. Power= I x v
= 30*10^-3A x 100*10^3v
= 3000watts
you need to divide 7500/286.2
D: Heat from the water moves into the ice
Answer: Um I would say maybe b
The coefficient of static friction between the coin and the turntable is 0.51
at the time of the slip:
centripetal force = frictional force
mv^2/r = x*m*980
v^2/r = 980x
x = v^2/980r
= [(120)^2]/[980*29]
= 0.51
Therefore, The coefficient of static friction between the coin and the turntable is 0.51
