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Alex17521 [72]
2 years ago
8

A ball has a mass of 0.046kg. Calculate the change in gravitational potential energy when the ball is lifted through a vertical

height of 2.05 m.
The mass of a ball is 0.046kg. The ball is released. Calculate the kinetic energy of the ball when the speed of the ball is 3.5 m/s
Physics
1 answer:
loris [4]2 years ago
3 0

Answer:

PE=0.92414J and KE=0.28175J

Explanation:

Gravitational potential energy=mass*gravity*height

PE=mgh

Data,

M=0.046kg

H=2.05m

g=9.8m/s^2

PE=0.046kg * 9.8m/s^2 * 2.05m

PE =0.92414J

KE=1/2mv^2

M=0.046kg

V=3.5m/s

KE=[(0.046kg)*(3.5m/s)^2]\2

KE=0.28175J

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Does gravity increase or decrease with greater mass?
Anni [7]
The force of gravity increases with mass, but decreases with increasing distance between objects.
4 0
2 years ago
The angle of elevation from a point on the ground to the top of a pyramid is 37 degrees 50​' The angle of elevation from a point
Serjik [45]

Answer:

The height of the pyramid is approximately 104 Ft. See the graphic attached.

Explanation:

First, you have to plot to realize that you have two rectangle triangles, formed by the different elevation points of view. From there you can have a system of two equations, with two unknown values.

Equation (1)

tan 37^{o}50'= \frac{Ph}{x} \\\\Ph=tan 37^{o}50'  x= 0.7766 x

Equation (2)

tan 18^{o}10'=\frac{Ph}{x+183} \\\\Ph=[tan 18^{o}10'][x+183]=[0.3281][x+183]

Matching (1) and (2)

0.7766 x=0.3281(x+183)\\\\(0.7766-0.3281)x=60.05\\\\x=\frac{60.05}{0.4485} =133.89ft

replacing x value in (1)

Ph=0.7766*133.89=103.9789\\Ph = 104 ft

5 0
3 years ago
Got it
Nimfa-mama [501]
Force=mass•acceleration
F=ma
15 N= 5kg•a
/5 =. /5
3= acceleration?
7 0
2 years ago
Consider a plywood square mounted on an axis that is perpendicular to the plane of the square and passes through the center of t
belka [17]

Answer:

T= 8.061N*m

Explanation:

The first thing to do is assume that the force is tangential to the square, so the torque is calculated as:

T = Fr

where F is the force, r the radius.

if we need the maximum torque we need the maximum radius, it means tha the radius is going to be the edge of the square.

Then, r is the distance between the edge and the center, so using the pythagorean theorem, r i equal to:

r = \sqrt{(0.38m)^2+(0.38m)^2}

r = 0.5374m

Finally, replacing the value of r and F, we get that the maximun torque is:

T = 15N(0.5374m)

T= 8.061N*m

4 0
3 years ago
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