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2 years ago

11

Please help I'm dispirit.

1 answer:

Natasha_Volkova [10]2 years ago

3 0

Synthesis and decomposition reactions are b. Synthesis and decomposition reactions are opposites of each other. Synthesis reactions are in the form A + B → AB, while decomposition reactions are in the form AB → A + B.

Synthesis reactions are reactions in which elements or compounds combine to form a larger compound. They are of the form A + B → AB.

Example: Na(s) + Cl (g)→ NaCl(s)

Decomposition reactions are reactions in which a larger compound breaks up into smaller compounds or elements. They are of the form AB → A + B.

Example: CaCO₃(s) → CaO (s) + CO₂ (g)

Synthesis and decomposition reactions are opposite of each other since synthesis reactions, new substances are formed while in decomposition reactions the compound is broken down into into smaller constituents.

So, Synthesis and decomposition reactions are b. Synthesis and decomposition reactions are opposites of each other. Synthesis reactions are in the form A + B → AB, while decomposition reactions are in the form AB → A + B.

Learn more about reactions here:

brainly.com/question/282113

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Answer:

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Explanation:

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3 years ago

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3 years ago

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Answer:

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3 years ago

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3 years ago

Read 2 more answers

A cyclist is riding a bicycle at a speed of 22 mph on a horizontal road. The distance between the axles is 42 in., and the mass

stealth61 [152]

Answer:

The shortest distance is $S = 24.86 ft$

Explanation:

The free body diagram of this question is shown on the first uploaded image

From the question we are told that

The speed of the bicycle is $v_b = 22\ mph = 22 * \frac{5280}{3600} = 32.26 ft/s$

The distance between the axial is $d = 42 \ in$

The mass center of the cyclist and the bicycle is $m_c = 26 \ in$ behind the front axle

The mass center of the cyclist and the bicycle is $m_h = 40 \ in$ above the ground

For the bicycle not to be thrown over the

Momentum about the back wheel must be zero so

$\sum _B = 0$

=> $mg (26) = ma(40)$

=> $a = \frac{26}{40} g$

Here $g = 32.2 ft/s^2$

So $a = \frac{26}{40} (32.2)$

$a = 20.93 ft/s^2$

Apply the equation of motion to this motion we have

$v^2 = u^2 + 2as$

Where $u = 32.26 ft /s$

and $v = 0$ since the bicycle is coming to a stop

$v^2 = (32.26)^2 - 2(20.93) S$

=> $S = 24.86 ft$

5 0

3 years ago