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Pavlova-9 [17]
3 years ago
11

Please help I'm dispirit.

Physics
1 answer:
Natasha_Volkova [10]3 years ago
3 0

Synthesis and decomposition reactions are  b. Synthesis and decomposition reactions are opposites of each other. Synthesis reactions are in the form A + B → AB, while decomposition reactions are in the form AB → A + B.

Synthesis reactions are reactions in which elements or compounds combine to form a larger compound. They are of the form A + B → AB.

Example: Na(s) + Cl (g)→ NaCl(s)

Decomposition reactions are reactions in which a larger compound breaks up into smaller compounds or elements. They are of the form AB → A + B.

Example: CaCO₃(s) → CaO (s) + CO₂ (g)

Synthesis and decomposition reactions are opposite of each other since synthesis reactions, new substances are formed while in decomposition reactions the compound is broken down into into smaller constituents.

So, Synthesis and decomposition reactions are  b. Synthesis and decomposition reactions are opposites of each other. Synthesis reactions are in the form A + B → AB, while decomposition reactions are in the form AB → A + B.

Learn more about reactions here:

brainly.com/question/282113

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Two. The both have a plasma membrane and cytoplasm. 
6 0
3 years ago
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An aluminum wire having a cross-sectional area equal to 2.20 10-6 m2 carries a current of 4.50 A. The density of aluminum is 2.7
Kazeer [188]

Answer:

The drift speed of the electrons in the wire is 2.12x10⁻⁴ m/s.

Explanation:

We can find the drift speed by using the following equation:

v = \frac{I}{nqA}

Where:

I: is the current = 4.50 A

n: is the number of electrons

q: is the modulus of the electron's charge = 1.6x10⁻¹⁹ C

A: is the cross-sectional area = 2.20x10⁻⁶ m²

We need to find the number of electrons:

n = \frac{6.022\cdot 10^{23} atoms}{1 mol}*\frac{1 mol}{26.982 g}*\frac{2.70 g}{1 cm^{3}}*\frac{(100 cm)^{3}}{1 m^{3}} = 6.03 \cdot 10^{28} atom/m^{3}                  

Now, we can find the drift speed:

v = \frac{I}{nqA} = \frac{4.50 A}{6.03 \cdot 10^{28} atom/m^{3}*1.6 \cdot 10^{-19} C*2.20 \cdot 10^{-6} m^{2}} = 2.12 \cdot 10^{-4} m/s              

Therefore, the drift speed of the electrons in the wire is 2.12x10⁻⁴ m/s.

I hope it helps you!      

4 0
3 years ago
The body weighing 8kg moves in a straight line uniformly accelerated with an acceleration of 3m / s? on a horizontal surface, un
Usimov [2.4K]

Answer:

pls explain this to me

Explanation:

I will not answer it

3 0
3 years ago
Technician A says voltage will not exist between any two points in a circuit if the potential is zero. Technician B says corrosi
nordsb [41]

Answer:

  • <u>Option-(A):</u> If there is no potential or we can say the difference in total amount of charges present inside the system then the voltage's value wont be greater then "0" inside the circuit or system.

Explanation:

  • While, the circuit or system requires the difference in total amount of energy that each atom on that spot has, as this potential energy difference or the total number of charges difference contribute to having a more specified manner of voltage,v in that system. And thus the flow of charges,Q from a point of origination or source towards a region of lower energy is all due to this difference in potential.
5 0
3 years ago
A rocket is fired straight upward, starting from rest with an acceleration of 25.0 m/s^2. It runs out of fuel at the end of 4.00
ANTONII [103]

Answer:

a) 200m, 100m/s

b) 710.20m

c) -117.98 m/s

d) 26.24 s

Explanation:

To solve this  we have to use the formulas corresponding to a uniformly accelerated motion problem:

V=Vo+a*t (1)

X=Xo+Vo*t+\frac{1}{2}*a*t^2\\ (2)

V^2=Vo^2+2*a*X (3)

where:

Vo is initial velocity

Xo=intial position

V=final velocity

X=displacement

a)

X=0+0*4+\frac{1}{2}*25*4^2

the intial position is zero because is lauched from the ground and the intial velocitiy is zero because it started from rest.

X=200m

V=0+25*4

V=100m/s

b)

The intial velocity is 100m/s we know that because question (a) the acceleration is -9.8\frac{m}{s^2} because it is going downward.

0=100^2+2*(-9.8)*X\\X=510.20\\totalheight=200+510.20=710.20m

c)

In order to find the velocity when it crashes, we can use the formula (3).

the initial velocity is 0 because in that moment is starting to fall.

V^2=0^2+2*(-9.8)*(710.20)\\V=-117.98 m/s

the minus sign means that the object is going down.

d)

We can find the total amount of time adding the first 4 second and the time it takes to going down.

to calculate the time we can use the formula (2) setting the reference at 200m:

-200=0+100*t+\frac{1}{2}*(-9.8)*t^2

solving this we have: time taken= 22.24 seconds

total time is:

total=22.24+4=26.24 seconds.

3 0
3 years ago
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