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atroni [7]
3 years ago
15

Which one of these substances will exist in solution only as molecules?

Chemistry
1 answer:
lukranit [14]3 years ago
6 0

The substances which will exist in molecular form in solution are-

A. CH₃NH₂

D. CH₃OH

The methyl amine (CH₃NH₂) and methanol (CH₃OH) is organic compounds which are hardly become ionic in nature and prefers to form as molecular state in the solution phase.

On the other hand B. LiOH and C. NH₄OH are inorganic compound and highly ionic in nature and remain as ionic state in solution.

Those are-

LiOH (s) → Li⁺(s) + OH⁻ (s)

NH₄OH→ NH₄⁺ (s) + OH⁻ (s)

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What element has a mass number of 16 and 8 neutrons
velikii [3]
The element would be Oxygen.
Work:
Mass = atomic # + neutrons
(The atomic number is the same as the number of protons in an element)

To find the number of protons substitute x 
16 = x + 8
x = 8 protons
Oxygen has 8 protons

I hope this helps!
8 0
4 years ago
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True or false? A chemical change involves an energy change.
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Whether a chemical reaction absorbs or releases energy, there is no overall change in the amount of energy during the reaction. I believe that your answer is to be true.

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True or False? In plant cells, the nucleus contains DNA? HELP
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Answer:

false

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3 years ago
Dipole-dipole interactions are (weaker than, stronger than, equal to) hydrogen bonds.
kozerog [31]

Answer and Explanation:

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7 0
3 years ago
An aqueous solution of sodium sulfide is allowed to react with an aqueous solution of magnesium chloride.
olya-2409 [2.1K]

Answer : The correct option is, (b) 2Na^+

Explanation :

Complete ionic equation : In complete ionic equation, all the substance that are strong electrolyte and present in an aqueous are represented in the form of ions.

Net ionic equation : In the net ionic equations, we are not include the spectator ions in the equations.

Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.

The balanced molecular equation will be,

Na_2S(aq)+MgCl_2(aq)\rightarrow 2NaCl(aq)+MgS(s)

The complete ionic equation in separated aqueous solution will be,

2Na^+(aq)+S^{2-}(aq)+Mg^{2+}(aq)+2Cl^{-}(aq)\rightarrow 2Na^+(aq)+2Cl^{-}(aq)+MgS(s)

In this equation the species Na^+\text{ and }Cl^{-} are the spectator ions.

Hence, the complete ionic equation contains specie is 2Na^+

4 0
3 years ago
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