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atroni [7]
3 years ago
15

Which one of these substances will exist in solution only as molecules?

Chemistry
1 answer:
lukranit [14]3 years ago
6 0

The substances which will exist in molecular form in solution are-

A. CH₃NH₂

D. CH₃OH

The methyl amine (CH₃NH₂) and methanol (CH₃OH) is organic compounds which are hardly become ionic in nature and prefers to form as molecular state in the solution phase.

On the other hand B. LiOH and C. NH₄OH are inorganic compound and highly ionic in nature and remain as ionic state in solution.

Those are-

LiOH (s) → Li⁺(s) + OH⁻ (s)

NH₄OH→ NH₄⁺ (s) + OH⁻ (s)

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A closed, nonreactive system contains species Aand Bin vapor/liquid equilibrium. Species Ais a very light gas, essentially insol
musickatia [10]

Answer:

Remain unchanged.

Explanation:

The total number of moles of liquid remain unchanged as the some moles of species B are added to the system because specie B that is added in the liquid phase is again restored after addition. If the specie B did not restored after addition to the liquid phase so the total number of moles increases in the liquid phase so that's why we can say that the liquid phase remain unchanged.

5 0
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lighting a match results in light and heat since energy was not created by the match what transformation took place
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I think if was chemical energy hope I helped
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3 years ago
500 grams of an unknown substance gains 23000 J of heat as it is heated from a temperature of 250C to 1250C. Using mathematical
lutik1710 [3]

Answer:

The given substance is cast iron.

Explanation:

Given data:

Mass of substance = 50 g

Heat absorbed = 23000 J

Initial temperature = 250°C

Final temperature = 1250°C

Which metal is this = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 1250°C -  250°C

ΔT = 1000°C

23000 j = 50 g ×c ×1000 °C

23000 J = 50,000 g. °C×c

c = 23000 J /50,000 g. °C

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The given substance is cast iron.

4 0
3 years ago
The boron atom of BBr3 has
maks197457 [2]

Answer: The boron atom of BBr_3 has three hybrid orbitals

Explanation: Hybridization of the molecule can be calculated by:

Hyb=\frac{1}{2}(V+H-C+A)     .....(1)

where,

V =  number of valence electrons in the central metal atom

H = number of monovalent atoms

C = cationic charge

A = anionic charge

Here, electronic configuration of B = 1s^22s^22p^1

Number of valence electrons = 3

Number of monovalent atoms = 3

Cationic charge = 0

Anionic charge = 0

Putting these values in equation 1, we get

Hyb=\frac{1}{2}(3+3-0+0)=3

As the Hybridization is 3, which means that boron has 3 hybrid orbitals.

4 0
4 years ago
Read 2 more answers
NEED HELP ASAP!!
lawyer [7]

Answer: Fe + 3NaBr → FeBr3 + 3Na

Explanation: You take the Br from 2NaBr and it makes FeBr3, so it makes a single replacement.

8 0
1 year ago
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