Answer:
d = 40 m
Explanation:
Given that,
Force, F = 4000 N
Mass of a car, m = 800 kg
Initial velocity, u = 0 (at rest)
Final velocity, v = 20 m/s
We need to find the distance traveled. Force acting on a car is given by :
F = ma
Where
a is the acceleration of the car.

Let it has traveled d distance. Using third equation of motion.

So, the required distance is equal to 40 m.
I pretty sure number 3 is false
Answer:
dJ = 1.7 m
Explanation:
The Equation of the Balancing the moments in the center of the seesaw is like this:
∑Mo = 0
Mo = F*d
Where:
∑Mo : Algebraic sum of moments in the center(o) of the balance
Mo : moment in the o point ( N*m)
F : Force ( N)
d : distancia of the force to the the o point ( N*m)
Data
mA = 60 kg : mass of the Anna
mJ = 70 kg : mass of theJon
dA = 2 m : Distance from Anna to the center of the seesaw
g: acceleration due to gravity
Calculation of the distance from Jon to the center of the seesaw (dJ)
∑Mo = 0 WA : Ana's weight , WJ : Jon's weight
W = m*g
(WA)(dA) - (WJ) (dJ) = 0
(mA*g)(dA) - (mJ*g)(dJ) = 0
We divide by g the equation:
(mA)(dA) - (mJ)(dJ)= 0
(mA)(dA) = (mJ)(dJ)


dJ = 1.7 m
Velocity is the rate of change in distance over change in
time, this can be written as:
v = Δd / Δt
While acceleration is the rate of change in velocity over
change in time, this is written as:
a = Δv / Δt
<span>Both quantities are vector quantities because negative
values means that the acceleration or velocity is acting on the opposite
direction.</span>