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Anettt [7]
4 years ago
5

In a Hall-effect experiment, a current of 3A sent lengthwise through a conductor of 1 cm wide, 4 cm long,

Physics
1 answer:
Marina CMI [18]4 years ago
4 0

Answer:drift velocity is 1.7*10^-4m/s and number of charge is 2.7*10^-24

Explanation:

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A battery is used to power a flashlight. When the flashlight is in use, what type of energy is lost during energy transformation
diamong [38]

Answer:

The answer is chemical energy

4 0
3 years ago
Read 2 more answers
The average period of pendulum clock is found to be 1.2s at sea level. The period of the same pendulum on a mountain top is foun
Kipish [7]

Answer:

g' = 10.12m/s^2

Explanation:

In order to calculate the acceleration due to gravity at the top of the mountain, you first calculate the length of the pendulum, by using the information about the period at the sea level.

You use the following formula:

T=2\pi \sqrt{\frac{l}{g}}         (1)

l: length of the pendulum = ?

g: acceleration due to gravity at sea level = 9.79m/s^2

T: period of the pendulum at sea level = 1.2s

You solve for l in the equation (1):

l=\frac{gT^2}{4\pi^2}\\\\l=\frac{(9.79m/s^2)(1.2s)^2}{4\pi^2}=0.35m

Next, you use the information about the length of the pendulum and the period at the top of the mountain, to calculate the acceleration due to gravity in such a place:

T'=2\pi \sqrt{\frac{l}{g'}}\\\\g'=\frac{4\pi^2l}{T'^2}

g': acceleration due to gravity at the top of the mountain

T': new period of the pendulum

g'=\frac{4\pi^2(0.35m)}{(1.18s)^2}=10.12\frac{m}{s^2}

The acceleration due to gravity at the top of the mountain is 10.12m/s^2

5 0
3 years ago
Pushing a rock from a hill top is called
wariber [46]
It's called "utter disregard for the safety and welfare
of the people standing at the bottom of the hill".
6 0
3 years ago
What happens when the moon faces one side of the earth?
algol [13]
When the moon faces earth a solar eclipse happens :-)
5 0
3 years ago
Consider a situation of simple harmonic motion in which the distance between the endpoints is 2.39 m and exactly 8 cycles are co
aivan3 [116]

Answer:

1.195 m

2.8375 s

2.21433 rad/s

Explanation:

d = Distance = 2.39 m

N = Number of cycles = 8

t = Time to complete 8 cycles = 22.7 s

Radius would be equal to the distance divided by 2

r=\frac{d}{2}\\\Rightarrow r=\frac{2.39}{2}\\\Rightarrow r=1.195\ m

The radius is 1.195 m

Time period would be given by

T=\frac{t}{N}\\\Rightarrow T=\frac{22.7}{8}\\\Rightarrow T=2.8375\ s

Time period of the motion is 2.8375 s

Angular speed is given by

\omega=\frac{2\pi}{T}\\\Rightarrow \omega=\frac{2\pi}{2.8375}\\\Rightarrow \omega=2.21433\ rad/s

The angular speed of the motion is 2.21433 rad/s

4 0
3 years ago
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