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Assoli18 [71]
3 years ago
5

How is the use of word theory in science different from its more common use

Chemistry
1 answer:
weqwewe [10]3 years ago
4 0
It is like an idea that they come up with in an experimeant

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I’ll give BRAINLIEST please answer this question fast
geniusboy [140]

Answer:

i think its d im not sure

Explanation:

7 0
3 years ago
Based on the Lewis/electron dot representation
timama [110]

Answer:

B or C think so

4 0
2 years ago
How does things go sublime
Lemur [1.5K]
Things go sublime when changing automatically into vapor when it is heated, usually forming a solid figure.
5 0
3 years ago
WILL GIVE BRAINLIEST
OverLord2011 [107]

Answer:

  • <u><em>butylphenyl ether.</em></u>

Explanation:

The formula of the compound is:

  • CH₃ - CH₂ - CH₂ - CH₂ - O - C₆H₅

1. The functional group is of the kind R - O - R', i.e. two alkyl groups each attached to one end of the oxygen atom. That means that the compound is an ether.

2. One group attached to the oxygen group is CH₃ - CH₂ - CH₂ - CH₂ - which has 4 carbons and is named butyl group.

3. The other group attached to the oxygen atom is C₆H₅ - which is derived from ciclohexane as is known as phenyl group.

4. Using the rule of naming the subtituents in alphabetical order, you name butyl first and phenyl second, so it is <u><em>butylphenyl ether.</em></u>

4 0
3 years ago
How much carbon would be needed to make 8.8g of carbon dioxide?<br>​
PIT_PIT [208]
The calculation for such a question can be achieved via Avogadro hypothesis

We know molar mass of CO2 is 44g/mole which is the sum of atomic masses i.e; C and 2 oxygen atoms

Molar mass of CO2 =12(C)+2*16(O) = 44 g/mole will contain 6.023 ※10^23 CO2 molecules ..

44g/mole = 6.023 ※10^23 CO2 molecules

=> 1g = (6.023/44) ※10^23 CO2 molecules

==> 8.80g = 8.80(6.023÷44)10^23 = 1.2046 ※10^23 molecules of CO2….

Thus there r 1.2046 ※10^23 molecules of CO2 in 8.80g

if u need to calculate no. of carbon atoms then multiply result by 1 and if u need no of oxygen atoms in 8.80g of co2 then multiply the result by 2 ….
7 0
2 years ago
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