Answer:
2.5 m/s²
Explanation:
Given,
Initial speed ( u ) = 10 m/s
Final speed ( v ) = 20 m/s
Time ( t ) = 4 seconds
To find : Acceleration ( a ) = ?
Formula : -
a = ( v - u ) / t
a = ( 20 - 10 ) / 4
= 10 / 4
= 5 / 2
a = 2.5 m/s²
Therefore,
The acceleration of the scooter is 2.5 m/s²
Answer:
![f_{beat} = 1.64\ Hz](https://tex.z-dn.net/?f=f_%7Bbeat%7D%20%3D%201.64%5C%20Hz)
Explanation:
given,
frequency of tuba.f = 64 Hz
Speed of train approaching, v = 8.50 m/s
beat frequency = ?
using Doppler's effect formula
![f' = f(\dfrac{v}{v-v_s})](https://tex.z-dn.net/?f=f%27%20%3D%20f%28%5Cdfrac%7Bv%7D%7Bv-v_s%7D%29)
v_s is the velocity of the source
v is the speed of sound, v = 340 m/s
now,
![f' = 64\times (\dfrac{340}{340 - 8.50})](https://tex.z-dn.net/?f=f%27%20%3D%2064%5Ctimes%20%28%5Cdfrac%7B340%7D%7B340%20-%208.50%7D%29)
f' = 65.64 Hz
now, beat frequency is equal to
![f_{beat} = f' - f](https://tex.z-dn.net/?f=f_%7Bbeat%7D%20%3D%20f%27%20-%20f)
![f_{beat} = 65.64 - 64](https://tex.z-dn.net/?f=f_%7Bbeat%7D%20%3D%2065.64%20-%2064)
![f_{beat} = 1.64\ Hz](https://tex.z-dn.net/?f=f_%7Bbeat%7D%20%3D%201.64%5C%20Hz)
hence, beat frequency is equal to 1.64 Hz
Answer:
Oxidation
Explanation:
The browning of the apple after you cut it undergoes a natural chemical change called oxidation, wherein the apple's enzymes react with the oxygen in the environment.
Answer:
16.4287
Explanation:
The force and displacement are related by Hooke's law:
F = kΔx
The period of oscillation of a spring/mass system is:
T = 2π√(m/k)
First, find the value of k:
F = kΔx
78 N = k (98 m)
k = 0.796 N/m
Next, find the mass of the unknown weight.
F = kΔx
m (9.8 m/s²) = (0.796 N/m) (67 m)
m = 5.44 kg
Finally, find the period.
T = 2π√(m/k)
T = 2π√(5.44 kg / 0.796 N/m)
T = 16.4287 s
Which way is it being pulled?