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Ainat [17]
3 years ago
9

A car goes from 0 to 60 mi/h north in 5 seconds. what is the car's acceleration?

Physics
2 answers:
Tomtit [17]3 years ago
8 0

Answer:

<h2>17.6 feet / second ^2</h2>

Explanation:

Explanation: 0 to 60 miles per hour means 0 to 88 feet/sec in five seconds (60 multiplied by 5280 (feet in one mile) divided by 3600 (seconds in an hour). The acceleration is 17.6 feet / second ^2.

OLEGan [10]3 years ago
7 0

Answer:

43200mi/h^2

Explanation:

time will taken in hours so 5/60/60 --> 1/720 h

accelaration formula : (change in velocity or speed) /time

acceleration = (60 - 0)/(1/720) = 43200 mi/h^2

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On being introduced to the laws of thermodynamics, a student retorted, “When the brakes of a moving car are applied, the kinetic
inn [45]

Answer:

No, not at all. This kinetic energy of car is converted/lost in the form of sound and heat under the tyre when driver apply brakes.

Explanation:

This law states that energy can neither be created nor destroyed but it changes from one form to the other.

In this case reduction of kinetic energy of car does not contradict the law but it changes into heat and sound energy. When driver apply brakes we hear the sound of Tyre due to friction with the road. The tyre become hot too.

So it is not in contradiction to the law of conservation of energy (First Law of Thermodynamics).

Please mark branliest if you are satisfied with the answer. Thanking you in anticipation.

5 0
3 years ago
assume that the initial speed is 25 m/s and the angle of projection is 53 degree above the hroizontal. the cannon ball leaves th
finlep [7]

Answer:

A.  xmax = 131.49 m

B.  t = 8.74 s

C.  ymax = 220.33 m

Explanation:

A. In order to find the horizontal distance which cannon travels you first calculate the flight time. The flight time can be calculated by using the following formula:

y=y_o+v_osin\theta-\frac{1}{2}gt^2      (1)

yo: height from the projectile is fired = 200m

vo: initial velocity of the projectile = 25m/s

g: gravitational acceleration = 9.8 m/s^2

θ: angle between the direction of the initial motion of the ball and the horizontal = 53°

t: time

You need the value of t when the projectile hits the ground. Then, in th equation (1) you make y = 0m.

When you replace the values of all parameters in the equation (1), you obtain the following quadratic formula:

0=200+(25)sin53\°t-\frac{1}{2}(9.8)t^2\\\\0=200+19.96t-4.9t^2 (2)

You use the quadratic formula to obtain the value of t:

t_{1,2}=\frac{-19.96\pm\sqrt{(19.96)^2-4(-4.9)(200)}}{2(-4.9)}\\\\t_{1,2}=\frac{-19.96\pm65.71}{-9.8}\\\\t_1=8.74s\\\\t_2=-4.66s

You use the positive value because it has physical meaning.

Now, you can calculate the horizontal range of the projectile by using the following formula:

x_{max}=v_ocos\theta t      

x_{max}=(25m/s)(cos53\°)(8.74s)=131.49m

The cannon ball travels a horizontal distance of 131.49 m

B. The cannon ball reaches the canon for t = 8.74s

C. The maximum height is obtained by using the following formula:

y_{max}=y_o+\frac{v_o^2sin^2\theta}{2g}     (3)

By replacing in the equation (3) the values of all parameters you obtain:

y_{max}=200m+\frac{(25m/s)^2(sin53\°)^2}{2(9.8m/s^2)}\\\\y_{mac}=200m+20.33m=220.33m

The maximum height reached by the cannon ball is 220.33m

3 0
3 years ago
Pls answer quick with right answer !!!
svetoff [14.1K]

Answer: I will say ''Law of conservation of energy.''

Explanation: Please tell me the answer you get!:)

7 0
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Where are the answers
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How do igneous rocks differ from each other.
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Although hand specimen identification is some what of an art; igneous rocks are classified using two critiria:
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Most of the time the rock name, such as basalt or granite, reflects the chemical composition. The minerals and textures are used as adjectives that modify the rock name. You might see a name like an olivine basalt or a quartz porphyry rhyolite.
8 0
3 years ago
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