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2 years ago

Which law does this diagram illustrate?

Physics

1 answer:

kirill115 [55]2 years ago

6 0

Here, the diagram shows Kepler's first law of Planetary motion, which tells, "A line segment joining a planet and the Sun sweeps out equal areas during equal intervals of time".

In short, Your Answer would be Option D

Hope this helps!

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A spring has a spring constant of 100 N/m, and the mass hanging from is is 0.71 kg. What is the period of the spring's motion?

Anuta_ua [19.1K]

k = spring constant of the spring = 100 N/m

m = mass hanging from the spring = 0.71 kg

T = Time period of the spring's motion = ?

Time period of the oscillations of the mass hanging is given as

T = (2π) √(m/k)

inserting the values in the above equation

T = (2 x 3.14) √(0.71 kg/100 N/m)

T = (6.28) √(0.0071 sec²)

T = (6.28) (0.084) sec

T = 0.53 sec

hence the correct choice is D) 0.53

6 0

2 years ago

Which statement correctly describes earths magnetic field? 20 point question!!!!

Olegator [25]

Answer:

D). Field lines circle the Earth from east to west.

Explanation:

A microscopic force or gigantic magnetic field surrounds the Earth which functions as a force field that guards the planet against the radiations released from space. This magnetic field is characterized by the alignment of the North and South poles with the axis of rotation. Thus, the magnetic field lines of the Earth surround or circle of the Earth from East to West. Therefore, option D is the correct answer.

3 0

2 years ago

A force Fof 40000 lbf is applied to rod AC the negative Y-direction. The rod is 1000 inches tall. A Force P of 25 lbf is applied

erastova [34]

Answer:

The answer is "effective stress at point B is 7382 ksi "

Explanation:

Calculating the value of Compressive Axial Stress:

$\to \sigma y =\frac{F}{A} = \frac{4 F}{( p d ^2 )} = \frac{(4 x ( - 40000 \ lbf))}{[ p \times (1 \ in)^2 ]} = - 50.9 \ ksi \\$

Calculating Shear Transverse:

$\to \frac{4v}{ 3 A} = \frac{4 (75 \ lbf + 25 \ lbf)}{ \frac{3 ( lni)^2}{4}}$

$= \frac{4 (100 \ lbf)}{ \frac{3 ( lni)^2}{4}} \\\\ = \frac{400 \ lbf)}{ \frac{3 ( lni)^2}{4}} \\\\= 0.17 \ ksi$

$= R \times 200 \ in - P \times 100 \ in = 12500 \ lbf \times\ in$

$\to \sigma' =[ s y^2 +3( t \times y^2 + t yz^2 )] \times \frac{1}{2}\\\\$

$= [ (-50.9)^2 +3((63.7)^2 +(0.17)^2 )] \times \frac{1}{2}\\\\=[2590.81+ 3(4057.69)+0.0289]\times \frac{1}{2}\\\\=[2590.81+12,173.07+0.0289] \times \frac{1}{2}\\\\=14763.9089\times \frac{1}{2}\\\\ = 7381.95445 \ ksi\\\\ = 7382 \ ksi$

8 0

2 years ago

An elevator of massmis initially at rest onthe first floor of a building. It moves upward,and passes the second and third floors

Varvara68 [4.7K]

To solve this problem it is necessary to apply the concepts of Work. Work is understood as the force applied to travel a determined distance, in this case the height. The force in turn can be expressed by Newton's second law as the ratio between mass and gravity, as well

$W = mgh$

Where,

m = mass

h = height

g = Gravitational constant

When it ascends to the second floor it has traveled the energy necessary to climb a height, under this logic, until the 4 floor has traveled 3 times the height h of each of the floors therefore

$h = 3h$

Replacing in our equation we have to

$W = mgh\\W = mg(3h)\\W = 3mgh$

The correct answer is 4.

7 0

2 years ago

How do you calculate density?

Mashcka [7]

Mass per cubic metre so kg/m3. Temperature may give different results.

4 0

3 years ago