Answer:
1. K.E = 11.2239 kJ ≈ 11.224 kJ
2.
3.
Solution:
Now, the kinetic energy of an ideal gas per mole is given by:
K.E =
where
m = no. of moles = 3
R = Rydberg's constant = 8.314 J/mol.K
Temperature, T = 300 K
Therefore,
K.E =
K.E = 11223.9 J = 11.2239 kJ ≈ 11.224 kJ
Now,
The heat capacity at constant volume is:
Now,
Required heat transfer to raise the temperature by is:
Answer:
a) 1. 1365 × 10⁻⁹N
b) 9.1862 × 10⁻⁴⁶N
c) 8.61 × 10⁻¹¹C/Kg
Explanation:
Ke = 8.99× 109 N.m2 / C2 , G = 6.67 × 10-11 N. m2 / kg2
a) F = Ke . q₁.q₂/r²
= (8.99× 109 N.m2 / C2 ) ×(1.60×10⁻¹⁹C)²/(4.50×10⁻¹⁰C)²
= 1. 1365 × 10⁻⁹N
b)
F = Gm₁m₂/r²
= (6.67× 10⁻¹¹)×(1.67×10⁻²⁷)²/(4.50×10⁻¹⁰)²
= 9.1862 × 10⁻⁴⁶N
The electric force is larger by 8.0497 ×10³⁷ times
c)
if Keq₁q₂/r² Gm₁m₂/r²,
with q₁=q₂ = q, and m₁ =m₂ = m
Then q/m = =
= 8.61 × 10⁻¹¹C/Kg
