What is the voltage in a circuit if the current is 6.2 A and the resistance is 18 ohms? A) 2.9 V B) 11.8 V C) 24.2 V D) 111.6 V

Physics

2 answers:

maks197457 [2]2 years ago

7 0

V = I · R = (6.2 A) · (18 Ω) = 111.6 volts (D)

docker41 [41]2 years ago

4 0

D)111.6V is the best answer

You might be interested in

Find the magnitude of the electric field due to a charged ring of radius "a" and total charge "Q", at a point on the ring axis a

34kurt

Answer:

E= $\frac{KQ}{2\sqrt 2a^2}$

Explanation:

We are given that

Charge on ring= Q

Radius of ring=a

We have to find the magnitude of electric filed on the axis at distance a from the ring's center.

We know that the electric field at distance x from the center of ring of radius R is given by

$E=\frac{kQx}{(R^2+x^2)^{\frac{3}{2}}}$

Substitute x=a and R=a

Then, we get

$E=\frac{KQa}{(a^2+a^2)^{\frac{3}{2}}}$

$E=\frac{KQa}{(2a^2)^{\frac{3}{2}}}$

$E=\frac{KQa}{2\sqrt 2a^3}$

$E=\frac{KQ}{2\sqrt 2a^2}$

Where K= $9\times 10^9 Nm^2/C^2$

Hence, the magnitude of the electric filed due to charged ring on the axis of ring at distance a from the ring's center= $\frac{KQ}{2\sqrt 2a^2}$

4 0

3 years ago

How would you determine the volume of an irregular shaped object.

Archy [21]

You can use the displacement method or the eureka can so basically in the displacement can what you have to do is to put some water into a measuring cylinder and measure its volume before adding the irregular shaped object and then measuring the level of water which had been displaced and then eureka can you can check online

7 0

3 years ago

What unit is used to measure the amount of energy used?

NNADVOKAT [17]

Answer: Joule

Explanation:

5 0

2 years ago

A solid metal object hangs from a force sensor by a thread in the open air, and the actual weight is measured to be 0.71 N. Then

Alexeev081 [22]

Answer:

The apparent weight of the object is 0.465 N.