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Fed [463]
3 years ago
11

What is the voltage in a circuit if the current is 6.2 A and the resistance is 18 ohms? A) 2.9 V B) 11.8 V C) 24.2 V D) 111.6 V

Physics
2 answers:
maks197457 [2]3 years ago
7 0

V = I · R  =  (6.2 A) · (18 Ω) =  111.6 volts  (D)
docker41 [41]3 years ago
4 0
D)111.6V is the best answer
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Which conditions I think you have place an incorrect image?
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3 years ago
A bird is about 6.26.2 in.​ long, with a​ thin, dark bill and a​ wide, white wing stripe. If the bird can fly 9292 mi with the w
Trava [24]

Answer:

209 mph

Explanation:

V = Speed of bird in still air

v = Speed of wind = 44 mph

Consider the motion of the bird with the wind

D_{1} = distance traveled with the wind = 9292 mi

t_{1} = time taken to travel the distance with wind

Time taken to travel the distance with wind is given as

t_{1} = \frac{D_{1}}{V + v}

t_{1} = \frac{9292}{V + 44}                              eq-1

Consider the motion of the bird with the wind

D_{2} = distance traveled against the wind = 6060 mi

t_{2} = time taken to travel the distance against wind

Time taken to travel the distance against wind is given as

t_{2} = \frac{D_{2}}{V + v}

t_{2} = \frac{6060}{V - 44}                              eq-2

As per the question,

Time taken with the wind = Time taken against the wind

t_{1} = t_{2}

\frac{9292}{V + 44} = \frac{6060}{V - 44}

(9292) (V - 44) = (6060) (V + 44)

9292V - 408848 = 6060V + 266640

3232V = 675488

V = 209 mph

5 0
2 years ago
Unpolarized light passes through a combination of two ideal polarizers. The transmission axes of the first polarizer and the sec
Yuliya22 [10]

Answer:

62.5 %

Explanation:

Let the initial intensity of unpolarized light is Io.

After first polariser the intensity of light becomes I'.

So, I' = \frac{I_{0}}{2}

Now it passes through another polariser. The angle between the first polariser and the second polariser is given by Ф. The intensity is I''.

According to the law of Malus

I'' = I' Cos^{2}\phi

Here, Ф = 30 degree

I'' = \frac{I_{0}}{2} Cos^{2}30=0.375I_{0}

The percentage change in the intensity is given by

\frac{I_{0}-I''}{I_{0}}\times 100=\frac{I_{0}-0.375I_{0}}{I_{0}}\times100

= 62.5 %

7 0
3 years ago
A 1.31 kg object is attached to a horizontal spring of force constant 2.70 N/cm and is started oscillating by pulling it 6.20 cm
goldfiish [28.3K]

Answer:

The answer is below

Explanation:

a) The change in energy is the difference between the final energy and the initial energy.

ΔE (energy change) = Ef (final energy) - Ei (initial energy)

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The negative sign shows that energy is lost to the environment. Hence 0.334 J is lost to the environment.

b) According to the law of conservation of energy, energy cannot be created or destroyed but transformed from one form to another.

The oscillating object loses energy due to wind resistance, friction between the spring and the object. Given that the air is frictionless, hence the energy loss is due to friction which is converted to heat.

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zloy xaker [14]

uhhhh, I think it depends your height or weigh...?

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2 years ago
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