Answer:
yield = 8501.96 g H3PO4
Explanation:
2344.44 g H20 × (1 mol H2O/18.01528 g H20)
= 130.14 mol H20
130.14 mol H2O × (4 mol H3PO4/6 mol H2O)
= 86.76 mol H3PO4
86.76 mol H3PO4 × (97.994 g H3PO4/1 mol H3PO4)
= 8501.96 g H3PO4
<em> $ 434.40</em>
<em>41 miles ............ 1 gallon</em>
<em>4700 miles .......x gallon</em>
<em>x = 4700×1/41 = 114.63 gallons</em>
<em />
<em>114.63 gallons×$3.79 ≈ $ 434.40</em>
There can be two electrons in one orbital maximum. The s sublevel has just one orbital, so can contain 2 electrons max. The p sublevel has 3 orbitals, so can contain 6 electrons max. The d sublevel has 5 orbitals, so can contain 10 electrons max.
The balanced neutralization reaction here is:
Ca(OH)2 + 2HBr --> 2H2O + CaBr2
Notice that two moles of Her are required to neutralize every one mole of Ca(OH)2. This means that for however many moles of Her reacted, HALF as many moles of Ca(OH)2 reacted as well.
Moles of HBr reacted = 0.75 M x 0.345 L = 0.259 mol
Moles of Ca(OH)2 reacted = 0.259 mol / 2 = 0.130 mol
Concentration of Ca(OH)2 = 0.130 mol / 0.250 L = 0.52 M