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3 years ago

You have 2344.44 grams of water that react according to this balanced chemical reaction. What is the theoretical yield of H3PO4?

Chemistry

1 answer:

alexgriva [62]3 years ago

5 0

Answer:

yield = 8501.96 g H3PO4

Explanation:

2344.44 g H20 × (1 mol H2O/18.01528 g H20)

= 130.14 mol H20

130.14 mol H2O × (4 mol H3PO4/6 mol H2O)

= 86.76 mol H3PO4

86.76 mol H3PO4 × (97.994 g H3PO4/1 mol H3PO4)

= 8501.96 g H3PO4

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How many grams of silver oxide are needed to react with 7.9 g of hydrochloric acid produce silver chloide and water?

Anastaziya [24]

Answer:

25.11 g.

Explanation:

It is clear from the balanced equation:

Ag₂O + 2HCl → 2AgCl + H₂O.

that 1.0 mole of Ag₂O reacts with 2.0 moles of HCl to produce 2.0 mole of AgCl and 1.0 moles of H₂O.

7.8 g of HCl reacts with excess Ag₂O. To calculate the no. of grams of Ag₂O that reacted, we should calculate the no. of moles of HCl:

no. of moles of HCl = mass/atomic mass = (7.9 g)/(36.46 g/mol) = 0.2167 mol.

From the balanced equation; every 1.0 mol of Ag₂O reacts with 2 moles of HCl.

∴ 0.2167 mol of HCl will react with (0.2617 mol / 2 = 0.1083 mol) of Ag₂O.

∴ The mass of reacted Ag₂O = no. of moles x molar mass = (0.1083 mol)(231.735 g/mol) = 25.11 g.

7 0

3 years ago

Inferring Relationships Most earthquakes take

Whitepunk [10]

Answer:

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Explanation:

8 0

2 years ago

Barium fluoride (BaF2) has a Ksp = 2. 5 × 10–5 (mol/L)3.

vagabundo [1.1K]

This problem is asking for the dissolution reaction of barium fluoride, both the equilibrium and Ksp expressions in terms of concentrations and x and its molar solubility in water. Thus, answers shown below:

$BaF_2(s)\rightleftharpoons Ba^{2+}(aq)+2F^-(aq)$
$Ksp=[Ba^{2+}][F^-]^2$
$Ksp=(x)(2x)^2$
0.0184 M.

<h3>Solubility product</h3>

In chemistry, when a solid is dissolved in water, one must take into account the fact that not necessarily its 100 % will be able to break into ions and thus undergo dissolution.

In such a way, and specially for sparingly soluble solids, one ought to write the dissolution reaction at equilibrium as shown below for the given barium fluoride:

$BaF_2(s)\rightleftharpoons Ba^{2+}(aq)+2F^-(aq)$

Next, we can write its equilibrium expression according to the law of mass action, which also demands us to omit any solid and refer it to the solubility product constant (Ksp):

$Ksp=[Ba^{2+}][F^-]^2$

Afterwards, one can insert the reaction extent, x, as it stands for the molar solubility of this solid in water, taking into account the coefficients balancing the reaction:

$Ksp=(x)(2x)^2$

Finally, we solve for the x as the molar solubility of barium fluoride as shown below:

$2.5x10^{-5}=(x)(2x)^2\\\\2.5x10^{-5}=4x^3\\\\x=\sqrt[3]{\frac{2.5x10^{-5}}{4} } \\\\x=0.0184M$

Learn more about chemical equilibrium: brainly.com/question/26453983

6 0

2 years ago

Classify each as acidic or basic - pH 9 - pH 2.3 - pH 11 - pH 5 - solution where the concentration of hydronium ions [H ] is 0.0

balu736 [363]

Answer:

pH = 9: Basic; pH = 2.3: acidic; pH = 11: basic; pH = 5: Acidic; [H⁺] = 0.0056M: Acidic; [H⁺] = 3.45E-9M: Basic

Explanation:

A solution is defined as acidic when pH < 7 and as basic when pH > 7.

Also, pH = -log[H⁺].

Thus:

pH = 9: >7 → Basic

pH = 2.3: <7 → Acidic

pH = 11: >7 → Basic

pH = 5: <7 → Acidic

[H⁺] = 0.0056M, pH = -log0.0056M = 2.25: <7: Acidic

[H⁺] = 3.45E-9M, pH = 8.46: > 7: Basic

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2 years ago

Which material is likely to slow the flow of electric charges the most? Explain.

kap26 [50]

Answer:

copper hiiiiiiiiiiiii

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3 years ago