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kolezko [41]
2 years ago
14

For the circuit in the previous part, with the frequency set at 1 hz, what happens if the inductance of the inductor is increase

d?
Physics
1 answer:
lubasha [3.4K]2 years ago
7 0
The relationship between inductance and frequency can be clearly described using the following equation of inductive reactance:

Xl = 2*pi*f*L ; simplifying:

L = Xl / 2*pi*f

Therefore, as what we saw, inductance and frequency are inversely proportional. To add up, when inductance increases the frequency would decrease.
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Can you help me??????????????????????????)?
garik1379 [7]

Answer:

Velocity is a change in displacement over change in time and uses the units m/s.

Both are rates of change and can be positive or negative.

Acceleration is a change in velocity over change in time and uses the units m/s².

Explanation:

Velocity is the change in displacement over change in time, this makes it a rate of change. It can be positive or negative because it is a vector quantity. It uses the units m/s because that is a displacement unit over a time unit.

Acceleration is the change in velocity over change in time, this makes it a rate of change. It can be positive or negative because it is also a vector quantity. It uses the units m/s² (m/s/s) because that is a velocity unit over a time unit.

5 0
3 years ago
The diffusion coefficients for species A in metal B are given at two temperatures: T (°C) D (m2/s) 1020 8.01 × 10-17 1290 7.86×
Solnce55 [7]

Explanation:

Below is an attachment containing the solution.

5 0
3 years ago
Gold is classified as a:<br> O noble gas<br> O halogen<br> O transition metal<br> O nonmetal
dedylja [7]

Answer:

Transition metal.

Explanation:

Reason;in periodic table gold is third element in eleventh column. So its classified as TRANSITION METAL. Gold contain 79 protons, 79 electrons and 118 neutrons and gold is the most abundant isotope.

Hope i helped you..

6 0
2 years ago
There are two identical, positively charged conducting spheres fixed in space. The spheres are 40.4 cm apart (center to center)
Nadya [2.5K]

Answer:

q_1=5.64\times 10^{-7}\ \text{C} and q_2=2.32\times 10^{-6}\ \text{C}

Explanation:

F_1=0.072\ \text{N}

F_2=0.115\ \text{N}

r = Distance between shells = 40.4 cm

q_1 and q_2 are the charges

k = Coulomb constant = 8.99\times10^{9}\ \text{Nm}^2/\text{C}^2

Force is given by

F_1=\dfrac{kq_1q_2}{r^2}\\\Rightarrow q_1q_2=\dfrac{F_1r^2}{k}\\\Rightarrow q_1q_2=\dfrac{0.072\times 0.404^2}{8.99\times 10^{9}}\\\Rightarrow q_1q_2=1.307\times 10^{-12}\\\Rightarrow q_1=\dfrac{1.307\times 10^{-12}}{q_2}

F_2=\dfrac{kq^2}{r^2}\\\Rightarrow q=\sqrt{\dfrac{F_2r^2}{k}}\\\Rightarrow q=\sqrt{\dfrac{0.115\times 0.404^2}{8.99\times 10^{9}}}\\\Rightarrow q=1.44\times 10^{-6}\ \text{C}

q=\dfrac{q_1+q_2}{2}\\\Rightarrow q_1+q_2=2q\\\Rightarrow q_1+q_2=2\times1.44\times 10^{-6}\\\Rightarrow q_1+q_2=2.88\times 10^{-6}

Substituting the above value of q_1 we get

\dfrac{1.307\times 10^{-12}}{q_2}+q_2=2.88\times 10^{-6}\\\Rightarrow q_2^2-2.88\times 10^{-6}q_2+1.307\times 10^{-12}=0\\\Rightarrow \frac{-\left(-0.00000288\right)\pm \sqrt{\left(-0.00000288\right)^2-4\times \:1\times \:1.307\times 10^{-12}}}{2\times \:1}\\\Rightarrow q_2=2.32\times 10^{-6}, 5.64\times 10^{-7}

q_1=\dfrac{1.307\times 10^{-12}}{q_2}=\dfrac{1.307\times 10^{-12}}{2.32\times 10^{-6}}\\\Rightarrow q_1=5.63\times 10^{-7}

q_1=\dfrac{1.307\times 10^{-12}}{q_2}=\dfrac{1.307\times 10^{-12}}{5.64\times 10^{-7}}\\\Rightarrow q_1=2.32\times 10^{-6}

Since we know q_1

q_1=5.64\times 10^{-7}\ \text{C} and q_2=2.32\times 10^{-6}\ \text{C}.

5 0
2 years ago
A switch that connects a battery to a 30μf capacitor is closed. several seconds later you find that the capacitor plates are cha
Elanso [62]
You can find the emf of the battery by using:

Q = CV.

Q = Charge in capacitor plates = 30μC
C = Capacitance of the capacitor = 30μF

V = Q/C = 30/30 = 1V

Ans: The emf of the battery = 1V.
5 0
3 years ago
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