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ipn [44]
2 years ago
10

552000 in scientific notation

Physics
1 answer:
LUCKY_DIMON [66]2 years ago
4 0
5.52 × 10 to the 5th power (100000)  . In scientific notation you need to have a decimal numver times 10 to the power of something so you can divide 552000 by 10  5  times. So in order to get 552000 you need to have 10 to the 4th power and 5.52
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2 years ago
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Which statement describes what most likely occurs when a compass is placed next to a simple circuit made from a battery, a light
aleksley [76]
D. A magnetic field created by the electric current causes the compass needle to move.
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2 years ago
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11. Scientists put a sample of water into a sealed tank. Water can be a solid, liquid, or gas. At first, the water was a liquid.
leva [86]

Answer:

c . slower and started moving in place.

Explanation:

Matter can exist generally in three phases, as a solid, liquid or gas. But it can be transformed from one phase to another by the removal or application of heat energy.

The water was initially in a liquid form in the sealed tank until energy was transferred out of the substance. Thus, this causes a change of state in which the water turns to a solid. Whereby during the process, the molecules of the water moved slowly until they are fixed at a point, and vibrates individually at their individual point.

Therefore the molecules of water moved slower and stated moving in place (i.e vibrating at a point). The water turns to an ice.

3 0
3 years ago
In the Millikan oil drop experiment the measured charge of any single droplet was always a whole number multiple of -1.60 x 10-1
BaLLatris [955]

Answer:

Number of electrons, n = 6

Explanation:

Total charge in a single droplet, q=-9.6\times 10^{-19}\ C

The measured charge of any single droplet, e=-1.6\times 10^{-19}\ C

Let n is the number of excess electrons are contained within the drop. According to the quantization of charge :

q=ne

n=\dfrac{q}{e}

n=\dfrac{-9.6\times 10^{-19}}{-1.6\times 10^{-19}}

n = 6

So, there are 6 electrons contained within the drop. Hence, this is the required solution.

7 0
3 years ago
Find the moments of inertia Ix, Iy, I0 for a lamina that occupies the part of the disk x2 y2 ≤ 36 in the first quadrant if the d
Tasya [4]

Answer:

I(x)  = 1444×k ×{\pi}

I(y)  = 1444×k ×{\pi}

I(o) = 3888×k ×{\pi}  

Explanation:

Given data

function =  x^2 + y^2 ≤ 36

function =  x^2 + y^2 ≤ 6^2

to find out

the moments of inertia Ix, Iy, Io

solution

first we consider the polar coordinate (a,θ)

and polar is directly proportional to a²

so p = k × a²

so that

x = a cosθ

y = a sinθ

dA = adθda

so

I(x) = ∫y²pdA

take limit 0 to 6 for a and o to \pi /2 for θ

I(x) = \int_{0}^{6}\int_{0}^{\pi/2} y²p dA

I(x) = \int_{0}^{6}\int_{0}^{\pi/2} (a sinθ)²(k × a²) adθda

I(x) = k  \int_{0}^{6}a^(5)  da ×  \int_{0}^{\pi/2}  (sin²θ)dθ

I(x) = k  \int_{0}^{6}a^(5)  da ×  \int_{0}^{\pi/2}  (1-cos2θ)/2 dθ

I(x)  = k ({r}^{6}/6)^(5)_0 ×  {θ/2 - sin2θ/4}^{\pi /2}_0

I(x)  = k × ({6}^{6}/6) × (  {\pi /4} - sin\pi /4)

I(x)  = k ×  ({6}^{5}) ×   {\pi /4}

I(x)  = 1444×k ×{\pi}    .....................1

and we can say I(x) = I(y)   by the symmetry rule

and here I(o) will be  I(x) + I(y) i.e

I(o) = 2 × 1444×k ×{\pi}

I(o) = 3888×k ×{\pi}   ......................2

3 0
3 years ago
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