He's accelerating at 3 m/s² . That means his speed is increasing by 3 m/s every second.At the end of 8 seconds, his speed is (8 x 3 m/s) = 24 m/s .He's been moving south for the whole 8 seconds.So at the end of that time, his velocity is 24 m/s south .
On driving your motorcycle in a circle of radius 75 m on wet pavement, the fastest you can go before you lose traction, assuming the coefficient of static friction is 0.20 is 147m/s
Friction helps to maintain the slipping of the vehicle on the road hence lays a very important role.
Maximum velocity of a road with friction is given by the formula,
v = μRg
where, v is the maximum velocity
μ is the coefficient of static friction
R is the radius of the circle road
g is the acceleration due to gravity
Given,
μ = 0.20
R = 75m
g = 9.8m/s²
On substituting the given values in the above formula,
v = 0.20× 75 ×9.8
v = 147m/s
So, the Maximum velocity of the wet road is 147m/s.
Learn more about Velocity here, brainly.com/question/18084516
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Answer:
Δu=1300kJ/kg
Explanation:
Energy at the initial state
Is saturated vapor at initial pressure we have
Process 2-3 is a constant volume process
The overall in internal energy
Δu=u₁-u₃
We replace the values in equation
Δu=u₁-u₃
Δu=1300kJ/kg
ONE CAN perform this by doing an ideal experiment
by creating an isothermal system
its like you supply heat to a body and that body is present at very low temperature the amount of heat you supply is equal to the amount of heat lost by that body due to difference in the temperature of the body and the surrounding. heating curve will be constant as there is no change in the internal energy of the system ..
