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Sunny_sXe [5.5K]
3 years ago
8

Which of the following statements is true?

Physics
1 answer:
Alborosie3 years ago
8 0
My guess is A. I'm not 100% positive but i'm pretty sure.
You might be interested in
[ b) The time of reverberation of an empty hall without and with 500 audiences is 1.5 sec and 1.4 sec respectively. Find the rev
Lilit [14]

The reverberation time with 800 audiences is 0.875 seconds.

<h3>Reverberation time with 800 audience</h3>

R₁V₁ = R₂V₂

where;

  • R₁ is the reverberation time with 400 audience
  • R₂ is the reverberation time with 800 audience
  • V₁ is initial volume
  • V₂ is final volume

R₂ = R₁V₁/V₂

R₂ = (1.4 x 500) / 800

R₂ = 0.875 seconds

Thus, the reverberation time with 800 audiences is 0.875 seconds.

Learn more about reverberation time here: brainly.com/question/9278479

#SPJ1

4 0
2 years ago
A rocket ship carrying passengers blasts off to go from New York to Hong Kong, a distance of about 13,000 km. (a) How fast (in t
lapo4ka [179]

Answer:

0.14c

0.003 s

Explanation:

See attachment

8 0
3 years ago
Q|C (a) You need a 45-ω resistor, but the stockroom has only 20-ω and 50-ω resistors. How can the desired resistance be achieved
NNADVOKAT [17]
  1. In order to achieve the desired resistance under the given circumstances, we would connect two 50 Ohms resistors in parallel and then connect it in series with the 20 Ohms resistors.
  2. In order to get a 35 Ohms resistance under the given circumstances, we would connect two 50 Ohms resistors in parallel and then connect it in series with two 20 Ohms resistors that are connected in parallel.

<h3>How to achieve the desired resistance under these circumstances?</h3>

In order to achieve the desired resistance under the given circumstances, we would connect two 50 Ohms resistors in parallel and then connect it in series with the 20 Ohms resistors.

Mathematically, the total equivalence resistance of two resistors that are connected in parallel is given by:

1/Rt = 1/R₁ + 1/R₂

1/Rt = 1/50 + 1/50

1/Rt = 2/50

1/Rt = 1/25

Rt = 25 Ohms.

Next, we would connect this 25 Ohms resistor in series with the 20 Ohms resistor:

R₃ = 20 + Rt

R₃ = 20 + 25

R₃ = 45 Ohms.

<h3>Part B.</h3>

In order to get a 35 Ohms resistance under the given circumstances, we would connect two 50 Ohms resistors in parallel and then connect it in series with two 20 Ohms resistors that are connected in parallel.

1/Rt = 1/R₁ + 1/R₂

1/Rt = 1/50 + 1/50

1/Rt = 2/50

1/Rt = 1/25

Rt = 25 Ohms.

1/R't = 1/R₁ + 1/R₂

1/R't = 1/20 + 1/20

1/R't = 2/20

1/R't = 1/10

R't = 10 Ohms.

Next, we would connect the 25 Ohms resistor in series with the 10 Ohms resistor:

R₃ = 10 + Rt

R₃ = 10 + 25

R₃ = 35 Ohms.

Read more on resistors in parallel here: brainly.com/question/15121871

#SPJ4

Complete Question:

You need a 45-ω resistor, but the stockroom has only 20-ω and 50-ω resistors.

(a) How can the desired resistance be achieved under these circumstances?

(b) What can you do if you need a 35-ω resistor?

3 0
2 years ago
Car B is following Car A and has a greater speed than Car A. the two cars are moving in a straight line and in the same directio
ElenaW [278]

Answer:

Collision force will be same in both the cases.

Explanation:

A perfectly inelastic collision is said to take place  when a system loses the amount of its Kinetic Energy at its maximum. In a perfectly inelastic collision,  the colliding particles stick to each other. In such a collision, kinetic energy is lost by combining the two bodies with each other.

In situation 1:

Speed of Car A, v_{A} = 10 mph

Speed of Car B, v_{B} = 20 mph

Relative speed of car A and car B, v = v_{b} - v_{a} = 10 m/s

Now, in the situation 2:

Speed of car A, v_{A} = 30 mph

Speed of car B, v_{B} = 40 mph

Relative speed of car A and car B, v = v_{b} - v_{a} = 10 m/s

Therefore, Car A and Car B both have the same relative speed, v = 10 m/s

7 0
3 years ago
An electron with velocity v = 1.0 ´ 106 m/s is sent between the plates of a capacitor where the electric field is E = 500 V/m. I
oksano4ka [1.4K]

Answer:

The deviation in path is 4.39 \times 10^{-3}

Explanation:

Given:

Velocity v = 1 \times 10^{6} \frac{m}{s}

Electric field E = 500 \frac{V}{m}

Distance x = 1 \times 10^{-2} m

Mass of electron m = 9.1 \times 10^{-31} kg

Charge of electron q = 1.6 \times 10^{-19} C

Time taken to travel distance,

    t = \frac{x}{v}

    t = \frac{1 \times 10^{-2} }{1 \times 10^{6} }

    t = 10^{-8} sec

Acceleration is given by,

  F = qE

ma = qE

   a = \frac{qE}{m}

   a = \frac{1.6 \times 10^{-19} \times 500}{9.1 \times 10^{-31} }

   a = 8.77 \times 10^{13} \frac{m}{s^{2} }

For finding the distance, we use kinematics equations.

   y = vt + \frac{1}{2}  at^{2}

Where v = 0 because here initial velocity zero

   y = \frac{1}{2} at^{2}

   y = \frac{1}{2} \times  8.77 \times 10^{13 } \times (10^{-2} )^{2}

   y = 4.39 \times 10^{-3} m

Therefore, the deviation in path is 4.39 \times 10^{-3}

6 0
3 years ago
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