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podryga [215]
3 years ago
10

All of the following are examples of mechanical energy except:

Physics
1 answer:
Paladinen [302]3 years ago
8 0
The answer is B. The nuclei of elements.
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A small ball of mass m is aligned above a larger ball of mass M = 0.63kg (with a slight separation) and the two are dropped simu
natta225 [31]
 <span>a) M is the big one 
m is the little one 

v is the speed of each of them when they impact 

V = speed of mii after collision 

Conservation of momentum 

Mv – mv = mV 

Conservation of energy 

1/2Mv^2 + 1/2mv^2 = 1/2 mV^2 

This pair simplify to give 

M = 3m 

V = 2v 

So m = 0.21kg 

and h = 4 . 2.7 = 10.8 m</span>Source(s):<span>Old teacher</span>
8 0
3 years ago
A 500-kg golf cart is moving on level ground in a circular path of radius 10 m with a speed of 12 m/s. What is the centripetal f
Alborosie

Answer:

7200N

Explanation:

Centripetal force is directly proportional to the product of the mass and the square of the velocity and inversely proportional to the radius given.

8 0
2 years ago
Which statement is true about nuclear fusion? it is caused by the same process that causes nuclear fission.
Sergeeva-Olga [200]

The correct statement about nuclear fusion is the last one: "it produces nearly all the elements that are heavier than helium". Nuclear fusion is the process of combination of two smaller atoms into a larger one. It requires a high activation energy, which is reached in the stars. Elements from He to Iron were formed in the Sun, but larger elements require a higher energy and are formed inside supernovas.

6 0
3 years ago
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Only one of three balls A, B, and C carries a net charge q. The balls are made from conducting material and are identical. One o
Zarrin [17]

Answer:

This is greater than the initial charge, which violates the principle that the charge cannot be created or destroyed, consequently this distribution is impossible to achieve

Explanation:

The metals distribute the charge on all surface when they touch the surface increases so that charge density decreases and when the charge is separated into smaller in each metal.

Let's apply this principle to our case.

One of the spheres is loaded with a charge q, when touching a ball its charge is reduced to 1 / 2q for each ball.

         qA = ½ q

         qB = ½ q

         qC = 0

The total charge is q

we make a second contact

If we touch the ball A again with the other sphere not charged C, the chare is distributed and when separated it is reduced by half

         qA = 1/2 (q / 2) = ¼ q

         qC = ¼ q

         qB = ½ q

At this point all spheres have a charge,

      qA = ¼ q

      qb = ½ q

      qC = ¼ q

The total charge is q

Now let's contact spheres B and one of the other two

       Q = ½ q + ¼ q = ¾ q

When splitting the charge

        qB = ½ ¾ q = 3/8 q

        qC = ½ ¾ q = 3/8 q

        qA = ¼ q

The total charge is q

Note that the total load is always equal to q

Now let's analyze the given configuration

Let's look for the total load

       Q = qA + QB + QC

       Q = ½ q + 3/8 q + ¼ q

        Q = 9/8 q

This is greater than the initial charge, which violates the principle that the charge cannot be created or destroyed, consequently this distribution is impossible to achieve

8 0
3 years ago
PLEASE HELP WILL GIVE 25 POINTS!!!!!
zimovet [89]

The answer is B. 1,4, and 6

8 0
3 years ago
Read 2 more answers
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