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mihalych1998 [28]
3 years ago
14

What causes the high luster of a metal?

Chemistry
1 answer:
Karo-lina-s [1.5K]3 years ago
7 0

Answer:

When light is shone on to the surface of a metal, its electrons absorb small amounts of energy and become excited into one of its many empty orbitals. The electrons immediately fall back down to lower energy levels and emit light. This process is responsible for the high luster of metals.

Explanation:

<em> </em><em>Your </em><em>well-wisher</em><em> </em><em>:-)</em>

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When a kettle is placed on the stove and water begins to boil, the hotter water at the bottom begins to rise and the
My name is Ann [436]

Answer:

The cooler water is denser

Explanation:

Convection drives the boiling of water placed on a stove in a kettle.

During convection, heat is circulated by density differences in portions of a fluid.

Convection is a form of heat transfer in fluids especially gas and liquid.

  • In boiling water, the heat is supplied to the base of the stove.
  • The water at the bottom on heat becomes lighter as the molecules gain more kinetic energy.
  • The colder part of the water on top sinks to replace the less dense on below.
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3 years ago
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A solution with a higher concentration of hydroxide ions (oh-) than hydrogen ions (h+)
Hoochie [10]
A solution with a higher concentration of hydroxide ions than hydrogen ions is basic solution.

This solution formed by Base dissolved in water and release hydroxide ions.

The PH of the solution is greater than 7
5 0
3 years ago
Roberto and his dad drove from town A to town B taking the long way, ate lunch and then came back using a
alina1380 [7]

Answer:c which is 70

Explanation:

i took the test and got it right

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3 years ago
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Hydrogen gas and fluorine gas will react to form hydrogen fluoride gas. What is the standard free energy change for this reactio
Marta_Voda [28]

Answer:

\Delta G=-541.4kJ/mol

Explanation:

Hello there!

In this case, according to the given information, it turns out firstly necessary to write out the described chemical reaction as shown below:

H_2+F_2\rightarrow 2HF

Now, we set up the expression for the calculation of the standard free energy change, considering the free energy of formation of each species, specially those of H2 and F2 which are both 0 because they are pure elements:

\Delta G=2\Delta G_f^{HF}-(\Delta G_f^{H_2}+\Delta G_f^{F_2})\\\\\Delta G=2*-270.70kJ/mol-(0kJ/mol+0kJ/mol)\\\\\Delta G=-541.4kJ/mol

Regards!

4 0
3 years ago
In the formula CO2, what does the subscript 2 after the O mean
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 it means two oxygen atoms
5 0
4 years ago
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