Answer:
ΔU = 5.21 × 10^(10) J
Explanation:
We are given;
Mass of object; m = 1040 kg
To solve this, we will use the formula for potential energy which is;
U = -GMm/r
But we are told we want to move the object from the Earth's surface to an altitude four times the Earth's radius.
Thus;
ΔU = -GMm((1/r_f) - (1/r_i))
Where;
M is mass of earth = 5.98 × 10^(24) kg
r_f is final radius
r_i is initial radius
G is gravitational constant = 6.67 × 10^(-11) N.m²/kg²
Since, it's moving to altitude four times the Earth's radius, it means that;
r_i = R_e
r_f = R_e + 4R_e = 5R_e
Where R_e is radius of earth = 6371 × 10³ m
Thus;
ΔU = -6.67 × 10^(-11) × 5.98 × 10^(24)
× 1040((1/(5 × 6371 × 10³)) - (1/(6371 × 10³))
ΔU = 5.21 × 10^(10) J
Answer:
yo they deleted my answer. The answer is 0N
Explanation:
so when two forces pull on an object from opposite sides with the same force (in this case its 20N), then the object is in equilibrium at 0N.
So its clear that there is one person on the the opposite side.
SOOO generally<u>: (left or down) would be considered </u><u>negative</u><u> in an equation. And the other person (right or up) would be considered </u><u>positive</u><u>.</u> So if both forces are the same numbers on opposite sides then the answer is 0 (if you add both of them).
<em>0 is the number of equilibrium.</em>
OK, so the equation would be -20N + 20N and then badda bing badda boom viola, the answer: 0N
thanks for coming to my TED talk. I hope they don't delete this answer.
Answer:
D = 271.54 m
Explanation:
given,
1. car accelerates at 4.6 m/s² for 6.2 s
2. constant speed for 2.1 s
3. slows down at 3.3 m/s²
distance travel for case 1
using equation of motion
d₁ = 88.41 m
case 2
constant speed for 2.1 s now, we have to find velocity
v = u + at
v = 0 + 4.6 x 6.2
v = 28.52 m/s
distance travel in case 2
d₂ = v x t
d₂ = 28.52 x 2.1 = 59.89 m
for case 3
distance travel by the car
v² = u² + 2 a s
final velocity if the car is zero
0² = 28.52² + 2 x (-3.3) x d₃
6.6 d₃ = 813.39
d₃ = 123.24 m
total distance travel by the car
D = d₁ + d₂ + d₃
D = 88.41 + 59.89 + 123.24
D = 271.54 m
Rock fragments that are cemented together and compacted over time turn into sedimentary rock.
the whole process can be summed up as the combination of weathering of rocks to form sediments, transport of the sediments to form deposits, cementation of deposits to forms the sedimentary rocks.
Acceleration = (change in speed) / (time for the change)
-- during the first second, the object increases its speed to
(5 m/s²) · (1 s) = 5 m/s .
-- During the next 2 seconds, the object increases its speed by
(2 m/s²) · ( s) = 4 m/s
So at the end of the whole 3 seconds, its speed is (5 m/s) + (4 m/s) = 9 m/s
-- Over the whole time, its speed has changed from zero to 9 m/s.
Acceleration = (change in speed) / (time for the change)
Acceleration = (9 m/s) / (3 sec)
<em>Acceleration = 3 m/s²</em>
